Is it possible to find (search) in Dynamics AX 2009 for an exact match?
For example, when I am searching in the AOT for "AddressRelationship", I don't want to see DirPartyAddressRelationship in the results.
Okay, it took me a while, but I have figured this out, it Is possible.
Adding a breakpoint to the find form shows that it uses a class called SysUtilScanSource to find your string within the AX source code.
In SysUtilScanSource.do() the method match is used to find a match against the specific source code. You can read more about match here;
http://msdn.microsoft.com/en-us/library/aa886279(v=ax.10).aspx
The match method allows you to use expressions.
The expression you require is as follows;
:SPACE
Where SPACE is the character ' '. Sets the match to blanks, tabulations, and control characters such as Enter (new line).
For example:
match("ab: cd","ab cd"); //returns 1
match("ab: cd","ab\ncd"); //returns 1
match("ab: cd","ab\tcd"); //returns 1
match("ab: cd","ab cd"); //returns 0 - only the first space is matched
Therefore, in your example you need enter the following string in the "containing text" field;
: AddressRelationship:
Note that in the above string there are spaces in the following locations;
:SPACEAddressRelationship:SPACE
Try it. I did, it works a treat.
When you do the find, look at "properties" tab at the end of the find form window. This allows you to scale down the search based on properties. I do not believe there is a way to use an exact match but you can narrow your search down using the properties.
Related
I'm using the REGEXREPLACE function in google sheets to extract some text contained in skus. If it doesn't find a text, it seems to return the entire original string. Is it possible to make it return an empty string instead? Having problems with this because it doesn't actually error out, so using iserror doesn't seem to work.
Example: my sku SHOULD contain 5 separate groups delimited by the underscore character '_'. in this example it is missing the last group, so it returns the entire original string.
LDSS0107_SS-WH_5
=REGEXREPLACE($A3,"[^_]+_[^_]+_[^_]+_[^_]+_(.*)","$1")
Fails to find the fifth capture group, that is correct... but I need it to give me an empty string when it fails... presently gives me the whole original string. Any ideas??
Perhaps the solution would be to add the missing groups:
=REGEXREPLACE($A1&REPT("_ ",4-(LEN($A1)-LEN(SUBSTITUTE($A1,"_","")))),"[^_]+_[^_]+_[^_]+_[^_]+_(.*)","$1")
This returns space as result for missing group. If you don't want to, use TRIM function.
In the visual studio 2015 find and replace window you can specify file types to look in for:
Looking in *.cs-Files
There, you can enter sth like *.cs which searches in i.e. Program.cs and Class1.cs.
*.as?x searches in Program.asPx and Program.asCx.
I've found no other way to enter a pattern except the wildcard characters *(any item 0 to infinit times) and ?(any item one time).
Is it possible to use any other pattern here to search in cs and resx-files, i.e. *.(resx|cs)[this doesnt work]? Is it possible to use some kind of regex like in the Find what-field?
In Find what you may use the regex defined here.
You can enter a semicolon-separated list of patterns, like this: *.resx;*.cs
I'm using oracle text to do a readahead (according to the spec writer) in the search bar.
Basically, a user can start typing text and we fill the suggestions bar with likely matches.
I tried using oracle text for this, and ran into some issues, and the latest one being:
Table contains this entry for answertext: ... we offer many pricing options ...
SELECT
questiontext as qtext,
answertext as text,
questionid FROM question
WHERE contains(answertext, '{pric}', 1) > 0
;
This query returns nothing. But using {pricing} will return the correct result.
And suggestion why this is happening would be great!
Edit: just wanted to add that using stemming does not work for me because the user wants to differentiate between "report" and "reporting" and they want the matching substring to be highlighted which can be done if I can find the substring among the returned results.
Edit 2: I have my guess, that oracle tokenizes each word using word boundary of some sort in the index, and thus without any wildcards it looks for a token that equals = 'pric' and therefore does not find it (because there is a token 'pricing'). So, if that guess is correct I would love if someone can chime in for how I can make the query above work with the example entry while still maintaining whitespace so if type 'pricing options' it should return but if i type 'many options' it should not...
CONTAINS operator supports wildcards and fuzzy text search. Try:
SELECT * FROM question WHERE contains(answertext, '{pric%}', 1) > 0;
or
SELECT * FROM question WHERE contains(answertext, 'fuzzy({pric})', 1) > 0;
But with fuzzy "prize" will also match your search criteria.
To highlight found substrings you can use CTX_DOC.MARKUP.
I want to transform the following text
This is a , here is another 
into
This is a , here is another 
In other words I want to find all the image paths that are enclosed between brackets (the text is in Markdown syntax) and replace them with other paths. The string containing the new path is returned by a separate real_path function.
I would like to do this using String#gsub in its block version. Currently my code looks like this:
re = /!\[.*?\]\((.*?)\)/
rel_content = content.gsub(re) do |path|
real_path(path)
end
The problem with this regex is that it will match  instead of just foto.jpeg. I also tried other regexen like (?>\!\[.*?\]\()(.*?)(?>\)) but to no avail.
My current workaround is to split the path and reassemble it later.
Is there a Ruby regex that matches only the path inside the brackets and not all the contextual required characters?
Post-answers update: The main problem here is that Ruby's regexen have no way to specify zero-width lookbehinds. The most generic solution is to group what the part of regexp before and the one after the real matching part, i.e. /(pre)(matching-part)(post)/, and reconstruct the full string afterwards.
In this case the solution would be
re = /(!\[.*?\]\()(.*?)(\))/
rel_content = content.gsub(re) do
$1 + real_path($2) + $3
end
A quick solution (adjust as necessary):
s = 'This is a '
s.sub!(/!(\[.*?\])\((.*?)\)/, '\1(/folder1/\2)' )
p s # This is a [foto](/folder1/foto.jpeg)
You can always do it in two steps - first extract the whole image expression out and then second replace the link:
str = "This is a , here is another "
str.gsub(/\!\[[^\]]*\]\(([^)]*)\)/) do |image|
image.gsub(/(?<=\()(.*)(?=\))/) do |link|
"/a/new/path/" + link
end
end
#=> "This is a , here is another "
I changed the first regex a bit, but you can use the same one you had before in its place. image is the image expression like , and link is just the path like foto.jpeg.
[EDIT] Clarification: Ruby does have lookbehinds (and they are used in my answer):
You can create lookbehinds with (?<=regex) for positive and (?<!regex) for negative, where regex is an arbitrary regex expression subject to the following condition. Regexp expressions in lookbehinds they have to be fixed width due to limitations on the regex implementation, which means that they can't include expressions with an unknown number of repetitions or alternations with different-width choices. If you try to do that, you'll get an error. (The restriction doesn't apply to lookaheads though).
In your case, the [foto] part has a variable width (foto can be any string) so it can't go into a lookbehind due to the above. However, lookbehind is exactly what we need since it's a zero-width match, and we take advantage of that in the second regex which only needs to worry about (fixed-length) compulsory open parentheses.
Obviously you can put real_path in from here, but I just wanted a test-able example.
I think that this approach is more flexible and more readable than reconstructing the string through the match group variables
In your block, use $1 to access the first capture group ($2 for the second and so on).
From the documentation:
In the block form, the current match string is passed in as a parameter, and variables such as $1, $2, $`, $&, and $' will be set appropriately. The value returned by the block will be substituted for the match on each call.
As a side note, some people think '\1' inappropriate for situations where an unconfirmed number of characters are matched. For example, if you want to match and modify the middle content, how can you protect the characters on both sides?
It's easy. Put a bracket around something else.
For example, I hope replace a-ruby-porgramming-book-531070.png to a-ruby-porgramming-book.png. Remove context between last "-" and last ".".
I can use /.*(-.*?)\./ match -531070. Now how should I replace it? Notice
everything else does not have a definite format.
The answer is to put brackets around something else, then protect them:
"a-ruby-porgramming-book-531070.png".sub(/(.*)(-.*?)\./, '\1.')
# => "a-ruby-porgramming-book.png"
If you want add something before matched content, you can use:
"a-ruby-porgramming-book-531070.png".sub(/(.*)(-.*?)\./, '\1-2019\2.')
# => "a-ruby-porgramming-book-2019-531070.png"
I'm trying to parse a webpage to get posts from a forum.
The start of each message starts with the following format
<div id="post_message_somenumber">
and I only want to get the first one
I tried xpath='//div[starts-with(#id, '"post_message_')]' in yql without success
I'm still learning this, anyone have suggestions
I think I have a solution that does not require dealing with namespaces.
Here is one that selects all matching div's:
//div[#id[starts-with(.,"post_message")]]
But you said you wanted just the "first one" (I assume you mean the first "hit" in the whole page?). Here is a slight modification that selects just the first matching result:
(//div[#id[starts-with(.,"post_message")]])[1]
These use the dot to represent the id's value within the starts-with() function. You may have to escape special characters in your language.
It works great for me in PowerShell:
# Load a sample xml document
$xml = [xml]'<root><div id="post_message_somenumber"/><div id="not_post_message"/><div id="post_message_somenumber2"/></root>'
# Run the xpath selection of all matching div's
$xml.selectnodes('//div[#id[starts-with(.,"post_message")]]')
Result:
id
--
post_message_somenumber
post_message_somenumber2
Or, for just the first match:
# Run the xpath selection of the first matching div
$xml.selectnodes('(//div[#id[starts-with(.,"post_message")]])[1]')
Result:
id
--
post_message_somenumber
I tried xpath='//div[starts-with(#id,
'"post_message_')]' in yql without
success I'm still learning this,
anyone have suggestions
If the problem isn't due to the many nested apostrophes and the unclosed double-quote, then the most likely cause (we can only guess without being shown the XML document) is that a default namespace is used.
Specifying names of elements that are in a default namespace is the most FAQ in XPath. If you search for "XPath default namespace" in SO or on the internet, you'll find many sources with the correct solution.
Generally, a special method must be called that binds a prefix (say "x:") to the default namespace. Then, in the XPath expression every element name "someName" must be replaced by "x:someName.
Here is a good answer how to do this in C#.
Read the documentation of your language/xpath-engine how something similar should be done in your specific environment.
#FindBy(xpath = "//div[starts-with(#id,'expiredUserDetails') and contains(text(), 'Details')]")
private WebElementFacade ListOfExpiredUsersDetails;
This one gives a list of all elements on the page that share an ID of expiredUserDetails and also contains the text or the element Details