bashscript for changing wput uploaddirectory on every 5000 passage - bash

Question

how i can change the uploaddirectory of wput on every 5000 passage?
whats wrong in my code?
only for the record; i need infnite loop i want run this script 24h 365 days!
every 5000 passage one number higher in directory like incoming1-infinite
best regards
haug
#!/bin/bash
for (( ; ; ))
do
no=1
while [ $no -le 5000 ]
do
perl job.pl false false 1
cd comp
for fname in *.jpg;
do
mv -i "$fname" ${RANDOM}${RANDOM}.jpg
done
for fname in *.jpg;
do
mv "$fname" $(echo "$fname" | sha1sum | cut -f1 -d' ').jpg
done
if [ $no = '5000' ]
then
echo $no
echo $n
n=$(( n+1 )) # <-- this one not do what i need :-(
else
wput *.jpg ftp://user:pass#ip:port/incoming$n/ # <-- here is the important part 2, i need it to change one directory higher every 5000 passage for example; incoming1 until infinite
rm -rf *.jpg
cd ..
fi
no=`expr $no + 1`
done
done

Answer 1

cd comp
for ((no=1; ; no++))
do
n=`expr $no / 5000`
perl job.pl false false 1
for fname in *.jpg;
# ... rest of the script
done

Answer 2

Just calculate the remainder of division by 5000 and if it is equal 0 (or 1 or anything < 5000) do what you need.
if [ $((no%5000)) = 0 ]
then
...
fi

Answer 3

Just put a for-loop that executes 5,000 times inside your infinite loop (which can keep track of the directory sequence number for you):
#!/bin/bash
for (( n=0; ; n++ )); do
for (( no=1; no < 5000; no++ )); do
perl job.pl false false 1
( # Subshell so we don't have to worry about returning
# to the previous directory.
cd comp
# No need to rename each file twice.
for fname in *.jpg; do
mv "$fname" $(echo "${RANDOM}${RANDOM}.jpg" | sha1sum | cut -f1 -d' ').jpg
done
wput *.jpg ftp://user:pass#ip:port/incoming$n
)
done
done