Ruby multithreading questions - ruby

Question

I've started looking into multi-threading in Ruby.
So basically, I want to create a few threads, and have them all execute, but not display any of the output until the thread has successfully completed.
Example:
#!/usr/bin/env ruby
t1 = Thread.new {
puts "Hello_1"
sleep(5)
puts "Hello_1 after 5 seconds of sleep"
}
t2 = Thread.new {
puts "Hello_2"
sleep(5)
puts "Hello_2 after 5 seconds of sleep"
}
t1.join
t2.join
puts "Hello_3"
sleep(5)
puts "Hello_3 after 5 seconds of sleep"
The first Hello_1 / Hello_2 execute immediately. I wouldn't want any of the output to show until the thread has successfully completed.

Answer 1

Because puts prints to a single output stream (sysout) you can't use it if you want to capture the output each thread.
You will have to use separate buffered stream for each thread, write to that in each thread, and then dump them to sysout when the thread terminates to see the output.
Here is an example of a thread:
t = Thread.new() do
io = StringIO.new
io << "mary"
io.puts "fred"
io.puts "fred"
puts io.string
end
You will have to pass io to every method in the thread.
or have a look at this for creating a module that redirects stdout for a thread.
But in each thread that your start wrap your code with:
Thread.start do
# capture the STDOUT by storing a StringIO in the thread space
Thread.current[:stdout] = StringIO.new
# Do your stuff.. print using puts
puts 'redirected to StringIO'
# print everything before we exit
STDIO.puts Thread.current[:stdout].string
end.join

Answer 2

You can share a buffer but you should 'synchronize' access to it:
buffer = ""
lock = Mutex.new
t1 = Thread.new {
lock.synchronize{buffer << "Hello_1\n"}
sleep(5)
lock.synchronize{buffer << "Hello_1 after 5 seconds of sleep\n"}
}
t2 = Thread.new {
lock.synchronize{buffer << "Hello_2\n"}
sleep(5)
lock.synchronize{buffer << "Hello_2 after 5 seconds of sleep\n"}
}
t1.join
t2.join
puts buffer