//Using Validation Plugin, how can i submit form when either one of the checkbox is checked or specific text field is not empty? I have checkboxes which generates dynamically and category_name text field. I want to submit form when either one of the checkbox is checked or category_name text field is not empty...
<?php
while($cat_row = "fetch_result"){
$tr.='<b><input type="checkbox" class="required" name="category[]" value="'.$cat_row['category_name'].'" id="category[]" checked/>'.$cat_row['category_name'].'</b>';
}
?>
//HTML File
<body>
<form id="abc" name="abc" action="PATH_TO_PHPFILE" method="post" enctype="multipart/form-data" >
<div id="cd">
<?=$tr?>
<div id="err"></div>
</div>
<input type="text" name="category_name" id="category_name" class="text_box" value="" />
</form>
<script>
$(function() {
$("form").validate({
rules:{
category:{
required:true,
minlength:2
}
},
errorPlacement: function(error, element) {
error.appendTo('#err');
},
submitHandler: function(form){
var options = {
success:function (data){
$.unblockUI();
//do something
},
beforeSubmit:function (){
//do something
}
};
$(form).ajaxSubmit(options);
}
});
});
</script>
</body>
Related
i am creating a form for searching a client, using either id or email both are set to be unique. Application made on Codeignitor.
I have created a form with two radio buttons, one for search with ID and another for search with mail+dob.
Depending on the radio button selected, corresponding input fields shown.
In controller, it choose the model function based on the radio button value.
This is I coded, i need to pass the value of radio button to Controller.php file
Form(only included the radio button)
$(document).ready(function() {
$("#usingdob").hide();
$("#usingmail").hide();
$("input:radio").click(function() {
if ($(this).val() == "id") {
$("#usingId").show();
$("#usingdob").hide();
$("#usingmail").hide();
} else {
$("#usingId").hide();
$("#usingdob").show();
$("#usingmail").show();
}
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="col-md-4">
<label class="radio-inline">
<input type="radio" name="optradio" value="id" checked>Using ID </label></div>
<div class="col-md-4">
<label class="radio-inline">
<input type="radio" name="optradio" value="mail">Using DOB</label>
</div>
I expected to get the radio button value correctlyenter image description here
JS:
$('input[name="optradio"]').click(function(){
var optradio = $(this).val();
//or
var optradio = $("input[name='optradio']:checked").val();
if(optradio == 'id'){
//do your hide/show stuff
}else{
//do your hide/show stuff
}
});
//on search button press call this function
function passToController(){
var optradio = $("input[name='optradio']:checked").val();
$.ajax({
beforeSend: function () {
},
complete: function () {
},
type: "POST",
url: "<?php echo site_url('controller/cmethod'); ?>",
data: ({optradio : optradio}),
success: function (data) {
}
});
}
Try this
<script type="text/javascript">
$( document ).ready(function() {
$("#usingdob, #usingmail").hide();
$('input[name="radio"]').click(function() {
if($(this).val() == "id") {
$("#usingId").show();
$("#usingdob, #usingmail").hide();
} else {
$("#usingId").hide();
$("#usingdob, #usingmail").show();
}
});
});
</script>
One thing I noticed is that you have 'mail' as a value in the DOB option. Another is that there seems to be 3 options and yet you only have 2 radios?
I adjusted the mail value to dob and created dummy divs to test the code. It seems to work.
$(document).ready(function() {
$("#usingdob").hide();
$("#usingmail").hide();
$("input:radio").click(function() {
console.log($(this).val());
if ($(this).val() == "id") {
$("#usingId").show();
$("#usingdob").hide();
$("#usingmail").hide();
} else {
$("#usingId").hide();
$("#usingdob").show();
$("#usingmail").show();
}
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="col-md-4">
<label class="radio-inline">
<input type="radio" name="optradio" value="id" checked>Using ID </label></div>
<div class="col-md-4">
<label class="radio-inline">
<input type="radio" name="optradio" value="dob">Using DOB</label>
</div>
<div id="usingId">
Using Id div
</div>
<div id="usingdob">
Using dob div
</div>
<div id="usingmail">
Using mail div
</div>
As far as passing the value to the controller goes, ideally the inputs should be in a form. When you submit the form, the selected value can be passed to the php.
<?php
if (isset($_POST['submit'])) {
if(isset($_POST['optradio']))
{
Radio selection is :".$_POST['optradio']; // Radio selection
}
?>
If you want to get currently checked radio button value Try below line which will return current radio button value
var radioValue = $("input[name='gender']:checked").val();
if(radioValue)
{
alert("Your are a - " + radioValue);
}
I'm using Codeigniter with Ckeditor. My problem is that when I submit the content, the data from the textarea is not stored in the database. But when I tried it again it finally did. So the situation is like I have to double click submit button to save it.
I stored the downloaded Ckeditor on a folder named ./Assests/Ckeditor(Sorry for the wrong spelling.I'll fix this later.)
Here's my form in my view folder:
ask_view.php:
<form id="form" enctype="multipart/data" method="post" onsubmit="createTextSnippet();">
<div class="form-group">
<label for="exampleInputEmail1">Title</label>
<input type="text" name ="title" class="form-control" id="title" placeholder="Title" required >
</div>
<input type="hidden" name="hidden_snippet" id="hidden_snippet" value="" />
<div class="form-group">
<label for="exampleInputEmail1">Editor</label>
<textarea name ="text" class="form-control" id="text" rows="3" placeholder="Textarea" required></textarea>
</div>
<input type="submit" class="btn " name="submit" value ="Submit" style="width: 100%;background: #f4a950;color:#161b21;">
</form>
<script src="<?php echo base_url('assests/js/editor.js')?>"></script>
<script type="text/javascript">
CKEDITOR.replace('text' ,{
filebrowserBrowseUrl : '<?php echo base_url('assests/filemanager/dialog.php?type=2&editor=ckeditor&fldr=')?>',
filebrowserUploadUrl : '<?php echo base_url('assests/filemanager/dialog.php?type=2&editor=ckeditor&fldr=')?>',
filebrowserImageBrowseUrl : '<?php echo base_url('assests/filemanager/dialog.php?type=1&editor=ckeditor&fldr=')?>'
}
);
</script>
<script type="text/javascript">
//code used to save content in textarea as plain text
function createTextSnippet() {
var html=CKEDITOR.instances.text.getSnapshot();
var dom=document.createElement("DIV");
dom.innerHTML=html;
var plain_text=(dom.textContent || dom.innerText);
var snippet=plain_text.substr(0,500);
document.getElementById("hidden_snippet").value=snippet;
//return true, ok to submit the form
return true;
}
</script>
<script type="text/javascript">
$('#form').on('submit', function (e) {
e.preventDefault();
$.ajax({
type: 'POST',
url: '/knowmore2/index.php/ask_controller/book_add',
data: $('form').serialize(),
success: function (data) {
console.log(JSON.parse(data));
}
});
});
</script>
Ask_model.php:
public function book_add($data)
{
$query=$this->db->insert('article', $data);
return $query;
}
Ask_controller.php:
public function book_add(){
$data = $_POST;
$details = array();
$details['title'] = $data['title'];
$details['content'] = $data['text'];
$details['snippet'] = $data['hidden_snippet'];
$details['createdDate']=date('Y-m-d H:i:s');
$result=$this->ask_model->book_add($details);
echo json_encode($details);
}
The content with html tags should be save in a column named content in the database, but it didn't save in the first click. It only saves on the second one,but the other data are saved in the first like the title, etc. So I get 2 rows of data, one without the content and the other with one.
Database:
First, I'm not having luck with ajax submitting at all in cakephp 1.3 environment. Once I successfully submit, I'm hoping user stays on page and submit button hidden or replaced with a checkmark. I've tried a few things... controller without $action and then .click function instead of on submit. I'm also not versed in debugging js to see where it might be wrong so any suggestions are welcome.
Maybe "update_a" is the $action within my dashboard controller
"function applications($action) {" instead?
dashboard controller
function update_a($action) {
...
switch ($action) {
case 'save':
if (!empty($this->data)) {
// update fields in database table matching model
$this->data['Model']['submitted'] = $_POST['submitted'];
$this->data['Model']['locked'] = $_POST['locked'];
if ($this->Model->save($this->data)) {
// save form fields to other models
$this->OtherModel->saveField('form_status_id',$_POST['form_status_id']);
$this->OtherModel->saveField('form_status',$_POST['form_status']);
}
}
}
break;
default:
//$this->redirect("admin/index");
$this->render("dashboard/applications");
break;
} //case
} // end function
html
<body>
<form id='update_a' action='save'>
<div class='form-group'>
<input type='hidden' class='hidden' name='locked' id='locked' value='1'>
<input type='hidden' class='hidden' name='form_status' id='form_status' value='Locked'>
<input type='hidden' class='hidden' name='form_status_id' id='form_status_id' value='3'>
<input type='hidden' class='hidden' name='submitted' id='submitted' value='<?php echo date("Y-m-d G:i:s") ?>'>
</div>
<div class='text-center'>
<input name='submit' type='button' class='btn btn-default' value='Submit Form A'>
</div>
</form>
</body>
<script>
$(document).ready(function () {
$('#update_a').on('submit', function (e) {
//$('#update_a').click(function (e) {
e.preventDefault();
$.ajax({
type: 'POST',
url: '/dashboard/update_a',
data: $('#update_a').serialize(),
success: function () {
alert('Form A has been submitted and locked for editing');
$('#update_a').hide();
},
error : function() {
alert("Error");
}
});
return false;
});
});
</script>
I have an component with text input. After fill input and submit form i sand axios query and after response i need stay on the same page with error popup or include new component with response data.
my component
<template>
<div class="col-md-12">
<div class="form-container">
<form v-on:submit="prepareCollage()" class="main-form">
<div class="form-group">
<input type="hidden" name="_token" value="">
<input placeholder="your text" v-model="text" name="query" type="text" class="form-control">
</div>
<button class="go btn btn-primary">Go!</button>
</form>
</div>
</div>
</template>
<script>
export default {
data () {
return {
text : '',
}
},
methods: {
prepareCollage(){
event.preventDefault();
axios.get('/api/prepare?query='+encodeURIComponent(this.text))
.then(function(result){
const result_data = result.data;
// if controller gave an error
if(result_data.error === true){
let error_text = result_data.error_text;
if(typeof(result_data.with_link) != 'undefined' && result_data.with_link.length > 0){
error_text += "<a href='"+result_data.with_link+"'>"+result_data.link_text+"</a>";
}
Vue.swal({
title: 'Error!',
html: error_text,
type: 'error',
})
}else{
// here i need include new component
}
});
}
}
}
</script>
in "else" block i have to include new vue component with data from this component. I have never used vuejs and have difficulty with understand this.
when a submit button is clicked i want to generate a pop up showing the list of items. The code i tried to create pop up is as follows:`
Index View:
<script type="text/javascript">
$('#popUp').Hide();
$('#button').click(function () {
$('#popUp').click();
});
</script>
<div class="left-panel-bar">
#using (Html.BeginForm(FormMethod.Post))
{
<p>Search For: </p>
#Html.TextBox("companyName",Model);
<input id="button" type="submit" value="Submit" />
}
</div>
<div id="popUp">
#Html.ActionLink("Get Company List", "CreateDialog", "Company", null, new
{
#class = "openDialog",
data_dialog_id = "emailDialog",
data_dialog_title = "Get Company List"
});
</div>
but i got trouble using this code.. when i click the submit button it opens another page instead of popup. The controller code is as follows:
[HttpPost]
public ActionResult Index(Companies c)
{
Queries q1 = new Queries(c.companyName);
if (Request.IsAjaxRequest())
return PartialView("_CreateDialog", q1);
else
return View("CreateDialog", q1);
}
You could use AJAX:
<script type="text/javascript">
$(function() {
$('form').submit(function() {
$.ajax({
url: this.action,
type: this.method,
data: $(this).serialize(),
success: function(result) {
$('#popUp').html(result);
}
});
return false;
});
});
</script>
<div class="left-panel-bar">
#using (Html.BeginForm())
{
<p>Search For: </p>
#Html.TextBox("companyName", Model);
<input id="button" type="submit" value="Submit" />
}
</div>
<div id="popUp">
</div>
Now ehn the form is submitted, an AJAX request will be sent to the Index POST action and since inside you test if the request was an AJAX request it will return the _CreateDialog.cshtml partial view and insert it into the #popUp div. Also it is important to return false from the form submit handler in order to cancel the default even which is to redirect the browser away from the current page.