I am working on codeigniter and I am writing the following query:
$this->db->select('*');
$this->db->from('tbl_profile');
$this->db->join('tbl_msg', 'tbl_msg.msg_sender_id = tbl_profile.profile_id');
$this->db->order_by("msg_id", "desc");
$query = $this->db->get('', $config['per_page'], $this->uri->segment(3));
$data['records'] = $query->result_array();
Correspondingly I am getting the following result:
SELECT (*) FROM tbl_profile
JOIN tbl_msg ON tbl_msg.msg_sender_id = tbl_profile.profile_id
Which is returninng a wrong result as I want the result corresponding to the following query:
select * from tbl_profile as A
join (select * from tbl_msg) as B on A.profile_id = B.msg_sender_id
Please help
First of all, you missing the order by clause, but I assum, you mean other differences.
If you want that, you can use this query, what will gave you back the exact code:
$this->db->select('*', FALSE);
$this->db->from('tbl_profile as A');
$this->db->join('( select * from tbl_msg ) as B', 'A.msg_sender_id = B.profile_id');
$this->db->order_by("msg_id", "desc");
$query = $this->db->get('', $config['per_page'], $this->uri->segment(3));
$data['records'] = $query->result_array();
From codeigniter user manual:
$this->db->select()
accepts an optional second parameter. If you set it to FALSE, CodeIgniter will not try to protect your field or table names with backticks. This is useful if you need a compound select statement.
Related
I have 4 tables like this:
Now, I want to select all columns from all tables where model.featured=1. i.e.
model.id
model.name
model_attributes.id
model_attributes.attributes_value
model_images.id
model_images.model_images
attributes.id
attributes.name
attributes.value
I can only do basic level queries and I'm not sure if I'm anywhere near to the solution but this is what I have tried (returns nothing):
$this->db->select('*');
$this->db->from('model');
$this->db->join('model_images','model.id = model_images.model_id','RIGHT');
$this->db->join('model_attributes','model.id = model_attributes.model_id','RIGHT');
$this->db->join('attributes','model_attributes.attributes_id = attributes.id','RIGHT');
$this->db->where('model.featured', 1);
$query = $this->db->get();
return $query->result();
How do I achieve what I want ? Or, is there any other better methods to do it ?
// try this query
$this->db->select('*');
$this->db->from('model');
$this->db->join('model_images','model_images.model_id = model.id');
$this->db->join('model_attributes','model_attributes.model_id = model.id');
$this->db->join('attributes','attributes.id = model_attributes.attributes_id');
$this->db->where('model.featured','1');
$query = $this->db->get()->result();
return $query;
Please go through below mentioned solution.
$this->db->select('model.*,model_images.*,model_attributtes.*, attributes.*'):
Let me know if it not works for you.
Please go through below solution. If multiple table has same column name then you have to give alias for each column name which have same name in both the table. because by default CI merge all column name and generate result.
$this->db->select('*,c.name as c_name,s.name as s_name');
$this->db->from('country c');
$this->db->join('state s', 'c.id = s.country_id');
$query = $this->db->get();
I have 2 tables - for orders and for documents for these orders. I want to show all orders from first table and if there are documents for these orders, to show date of documents(I take date from table documents).
I'm trying to make 2 join conditions because in table documents if I only join on idOrder, there are more than 1 row and I have to join on documents.name to be same as $this->uri->segment(3).
But I'm using the following code and it gives me error. Could I use 2 join conditions in this way:
My model is:
<?php
public function get_all_orders($user_id){
$this->db->select('ordersheader.*, customer.name as customerName,documents.date_make');
$this->db->from('ordersheader');
$this->db->join('customer', 'ordersheader.idCustomer = customer.idCustomer');
$this->db->join('documents', 'ordersheader.idOrder = documents.idOrder','left');
$this->db->join('documents as D', 'D.name="declaration"','left');
$this->db->where('ordersheader.user_id', $user_id);
$query = $this->db->get();
return $query->result_array();
}
Edited: I found solution. But it's written in pure sql, how to write it with Codeingiter syntax? My new working code is:
<?php
$query=("SELECT ordersheader.*, customer.name as customerName,documents.date_make,documents.deactivated_at
FROM ordersheader JOIN customer ON ordersheader.idCustomer = customer.idCustomer
LEFT JOIN documents
ON ordersheader.idOrder = documents.idOrder AND documents.name = '".$document."'
WHERE ordersheader.user_id = '".$user_id."' ");
$result = $this->db->query($query);
return $result->result_array();
This is wrong in your query
$this->db->join('documents as D', 'D.name="declaration"','left');
you can compare column using where clause
public function get_all_orders($user_id){
$this->db->select('ordersheader.*, customer.name as customerName,documents.date_make');
$this->db->from('ordersheader');
$this->db->join('customer', 'ordersheader.idCustomer = customer.idCustomer');
$this->db->join('documents', 'ordersheader.idOrder = documents.idOrder','left');
// $this->db->join('documents as D', 'D.name="declaration"','left'); / comment this line
$this->db->where('documents.name', 'declaration');
$this->db->where('ordersheader.user_id', $user_id);
$query = $this->db->get();
return $query->result_array();
}
I am trying to get URL parameter in SQL, but nothing happens.
Here is my URL:
http://localhost/webshop/imagegallery.php?categori=necklace
Here is my SQL query:
$sql = 'SELECT count(productid) FROM products where productcategori=".$_GET["categori"]"';
What am I doing wrong?
Have a look at this query, too:
$sql = 'select * from products join ids on products.productid=ids.productid join photos on photos.photosid=ids.photoid where products.productcategori='".$_GET["kategori"]."' && ids.photonumber=1 ORDER BY products.productid DESC $limit';
First of all, your quotation marks seem to be the problem. Try changing your query line to this:
$sql = "SELECT count(productid) FROM products where productcategori='".$_GET["categori"]."'";
Further, you should never insert variables into a SQL query like this. Never.
The reason is that like this, your system is vulnerable for SQL injections.
Instead consider using PDO. This SO question has a nice answer on how to do it correctly.
Using that answer, this is some example code regarding the last part of your question. Note that I replaced all variables in your query string by PDO placeholders.
<?php
$pdo = new PDO('mysql:dbname=mydatabase;host=127.0.0.1;charset=utf8', 'username', 'password');
$pdo->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$sql = "SELECT * FROM products JOIN ids ON products.productid=ids.productid JOIN photos ON photos.photosid=ids.photoid WHERE products.productcategori=:categori && ids.photonumber=1 ORDER BY products.productid DESC LIMIT :limit_min , :limit_max";
$stmt = $pdo->prepare($sql);
$stmt->bindParam(':categori', $_GET['categori']);
$stmt->bindParam(':limit_min', ($pagenum - 1) * $page_rows, PDO::PARAM_INT);
$stmt->bindParam(':limit_max', $page_rows, PDO::PARAM_INT);
$stmt->execute();
foreach($stmt as $row) {
// do something with $row
}
?>
Basicly i have two tables photos and users. I wanna join tables and Update colums image_max and image_min. I get error unknown colum username. In which way i can join two tabels and get data from both. My sintax is:
$this->db->select('*');
$this->db->from('photos');
$this->db->join('users', 'photos.id = users.id');
$this->db->where('username',$username);
$this->db->update('photos',$data);
And I get error
Unknown column username in where clause
UPDATE `photos` SET `image_max` = '', `image_min` = '' WHERE `username` = 'wwww'
apparently you need a letter on the table should say "users.username", check that.
Greetings.
$this->db->select('*');
$this->db->from('photos');
$this->db->join('users', 'photos.id = users.id');
$this->db->where('users.username',$username);
$this->db->update('photos',$data);
You don't need to use "select and from" before upload fields, just update in this way
$data = array('image_max'=> 4, 'image_min' => 1);
$this->db->join('users', 'photos.id = users.id');
$this->db->where('username',$username);
$this->db->update('photos',$data);
How can I select rows from two or more tables?
I'm setting default fields for a form, and I need values from two tables...
My current code reads:
$this->CI->db->select('*');
$this->CI->db->from('user_profiles');
$this->CI->db->where('user_id' , $id);
$user = $this->CI->db->get();
$user = $user->row_array();
$this->CI->validation->set_default_value($user);
The example in the User Guide should explain this:
$this->db->select('*'); // <-- There is never any reason to write this line!
$this->db->from('blogs');
$this->db->join('comments', 'comments.id = blogs.id');
$query = $this->db->get();
// Produces:
// SELECT * FROM blogs
// JOIN comments ON comments.id = blogs.id
See the whole thing under Active Record page in the User Guide.
Just add the other table to the "->from()" method. Something like:
$this->db->select('t1.field, t2.field2')
->from('table1 AS t1, table2 AS t2')
->where('t1.id = t2.table1_id')
->where('t1.user_id', $user_id);
I think the question was not so much about joins as how to display values from two different tables - the User Guide doesn't seem to explain this.
Here's my take:
$this->db->select('u.*, c.company, r.description');
$this->db->from('users u, company c, roles r');
$this->db->where('c.id = u.id_company');
$this->db->where('r.permissions = u.permissions');
$query = $this->db->get();
I think the syntax is incorrect.
You need to select one record. I have two tables, and I have an id from one table transfer by parameter, and the relation of both tables.
Try this
$this->db->select('*')
->from('student')
->where('student.roll_no',$id)
->join('student_details','student_details.roll_no = student.roll_no')
->join('course_details','course_details.roll_no = student.roll_no');
$query = $this->db->get();
return $query->row_array();
$SqlInfo="select a.name, b.data fromtable1 a, table2 b where a.id=b.a_id";
$query = $this->db->query($SqlInfo);
try this way, you can add a third table named as c and add an 'and' command to the sql command.
// Select From Table 1 All Fields, and From Table 2 one Field or more ....
$this->db->select('table1.*, table2.name');
$this->db->from('table1, table2');
$this->db->where('table2.category_id = table1.id');
$this->db->where('table2.lang_id',$id); // your where with variable
$query = $this->db->get();
return $query->result();