I have an AppleScript:
on run
set pathName to "/Users/Alexander/Documents/GeekTool/DiskCapacityMeter"
set usedSpace to (do shell script "df -hl | grep 'disk0s2' | awk '{sub(/%/, \"\");print $5}'") as integer
set theNumber to (round (usedSpace / 5)) * 5
do shell script ("cp " & pathName & "/img/" & theNumber & ".png " & pathName & "/temp.png")
end run
(downloaded from: Here)
I wanna change this script to show my CPU usage instead of my disc capacity, and since i really don't know any AppleScript, i have no clue how to change it.
I just know i need to change this part:
(do shell script "df -hl | grep 'disk0s2' | awk '{sub(/%/, \"\");print $5}'")
to give me my CPU usage instead of my disc capacity.. if it's even possible to get my CPU usage this way?
edit*
There are 11 picures associated with this script (0-10.png) and a twelfth picture (temp.png) that changes to one of the first 11 depending on the number generated by the script.
I don't know how accurate this is, but the CPU usage at single points of time has a lot of variance:
ps axo %cpu | awk '{s+=$1}END{print s}'
This would be even less accurate, because top itself uses a lot of CPU:
top -l1 -n0 | sed -En 's/^CPU usage: ([^%]*)% user, ([^%]*)%.*/\1+\2/p' | bc
Related
I am trying to get the CPU usage of a mac over time.
I am using this top cmd in terminal getting the result i want but would like it to output to a file and update every 5 seconds.
top -l 1 | grep -E "^CPU|^Phys"
CPU usage: 3.27% user, 14.75% sys, 81.96% idle
PhysMem: 5807M used (1458M wired), 10G unused.
This command prints all 3 CPU usage percentages tab-separated to a file (appending line by line for each call):
top -l1 | grep -E "CPU usage:" | awk -v FS="CPU usage: | user, | sys, | idle" '{print $2, $3, $4}' >> cpu_user_sys_idle.tsv
Works with pipe separated command chain:
Top as you suggested
Grep to filter only line with CPU usage
Awk with variable field-separator (-v FS) using either of the 4 strings to get all percentages as isolated fields. Then print second, third and fourth (omit first since it is empty).
>> redirects output appending to file (e.g. cpu_user_sys_idle.tsv)
You additionally can put it into automated or scheduled (apple)script to collect measures in regular intervals.
Ive seen the same question asked on linux and windows but not mac (terminal). Can anyone tell me how to get the current processor utilization in %, so an example output would be 40%. Thanks
This works on a Mac (includes the %):
ps -A -o %cpu | awk '{s+=$1} END {print s "%"}'
To break this down a bit:
ps is the process status tool. Most *nix like operating systems support it. There are a few flags we want to pass to it:
-A means all processes, not just the ones running as you.
-o lets us specify the output we want. In this case, it all we want to the cpu% column of ps's output.
This will get us a list of all of the processes cpu usage, like
0.0
1.3
27.0
0.0
We now need to add up this list to get a final number, so we pipe ps's output to awk. awk is a pretty powerful tool for parsing and operating on text. We just simply add up the numbers, then print out the result, and add a "%" on the end.
Adding up all those CPU % can give a number > 100% (probably multiple cores).
Here's a simpler method, although it comes with some problems:
top -l 2 | grep -E "^CPU"
This gives 2 samples, the first of which is nonsense (because it calculates CPU load between samples).
Also, you need to use RegEx like (\d+\.\d*)% or some string functions to extract values, and add "user" and "sys" values to get the total.
(From How to get CPU utilisation, RAM utilisation in MAC from commandline)
Building on previous answers from #Jon R. and #Rounak D, the following line prints the sum of user and system values, with the added percent. I've have tested this value and I like that it roughly tracks well with the percentages shown in the macOS Activity Monitor.
top -l 2 | grep -E "^CPU" | tail -1 | awk '{ print $3 + $5"%" }'
You can then capture that value in a variable in script like this:
cpu_percent=$(top -l 2 | grep -E "^CPU" | tail -1 | awk '{ print $3 + $5"%" }')
PS: You might also be interested in the output of uptime, which shows system load.
Building upon #Jon R's answer, we can pick up the user CPU utilization through some simple pattern matching
top -l 1 | grep -E "^CPU" | grep -Eo '[^[:space:]]+%' | head -1
And if you want to get rid of the last % symbol as well,
top -l 1 | grep -E "^CPU" | grep -Eo '[^[:space:]]+%' | head -1 | sed s/\%/\/
top -F -R -o cpu
-F Do not calculate statistics on shared libraries, also known as frameworks.
-R Do not traverse and report the memory object map for each process.
-o cpu Order by CPU usage
Answer Source
You can do this.
printf "$(ps axo %cpu | awk '{ sum+=$1 } END { printf "%.1f\n", sum }' | tail -n 1),"
Ive seen the same question asked on linux and windows but not mac (terminal). Can anyone tell me how to get the current processor utilization in %, so an example output would be 40%. Thanks
This works on a Mac (includes the %):
ps -A -o %cpu | awk '{s+=$1} END {print s "%"}'
To break this down a bit:
ps is the process status tool. Most *nix like operating systems support it. There are a few flags we want to pass to it:
-A means all processes, not just the ones running as you.
-o lets us specify the output we want. In this case, it all we want to the cpu% column of ps's output.
This will get us a list of all of the processes cpu usage, like
0.0
1.3
27.0
0.0
We now need to add up this list to get a final number, so we pipe ps's output to awk. awk is a pretty powerful tool for parsing and operating on text. We just simply add up the numbers, then print out the result, and add a "%" on the end.
Adding up all those CPU % can give a number > 100% (probably multiple cores).
Here's a simpler method, although it comes with some problems:
top -l 2 | grep -E "^CPU"
This gives 2 samples, the first of which is nonsense (because it calculates CPU load between samples).
Also, you need to use RegEx like (\d+\.\d*)% or some string functions to extract values, and add "user" and "sys" values to get the total.
(From How to get CPU utilisation, RAM utilisation in MAC from commandline)
Building on previous answers from #Jon R. and #Rounak D, the following line prints the sum of user and system values, with the added percent. I've have tested this value and I like that it roughly tracks well with the percentages shown in the macOS Activity Monitor.
top -l 2 | grep -E "^CPU" | tail -1 | awk '{ print $3 + $5"%" }'
You can then capture that value in a variable in script like this:
cpu_percent=$(top -l 2 | grep -E "^CPU" | tail -1 | awk '{ print $3 + $5"%" }')
PS: You might also be interested in the output of uptime, which shows system load.
Building upon #Jon R's answer, we can pick up the user CPU utilization through some simple pattern matching
top -l 1 | grep -E "^CPU" | grep -Eo '[^[:space:]]+%' | head -1
And if you want to get rid of the last % symbol as well,
top -l 1 | grep -E "^CPU" | grep -Eo '[^[:space:]]+%' | head -1 | sed s/\%/\/
top -F -R -o cpu
-F Do not calculate statistics on shared libraries, also known as frameworks.
-R Do not traverse and report the memory object map for each process.
-o cpu Order by CPU usage
Answer Source
You can do this.
printf "$(ps axo %cpu | awk '{ sum+=$1 } END { printf "%.1f\n", sum }' | tail -n 1),"
Can somebody please help me to write a KSH Script to get the CPU usage of the AIX server ?
Here I want my script to get the Current usage of CPU that time it is executed
There are a number of tools on AIX (and elsewhere) to get the current CPU usage.
nmon
On AIX (and Linux) you have nmon. This gives very detailed infos on memory, cpu usage, disk usage, etc. It is normally used as an interactive tool.
sar
call sar -u 1 1 to get the current cpu usage. See the manual page of sar for a whole lot of options. Depending on your installation you need to be root or add your user to the group "adm".
Just call w -u. It outputs a little bit more than you ask for. If you don't need that you can use awk/sed/cut to cut it away.
I use the following script in bash, but I just tried it in ksh and it works all the same:
top -bn2 | grep 'Cpu(s)' | sed -n '2s/.*, *\([0-9.]*\)%* id.*/\1/p' | awk '{print "CPU: " 100 - $1" %"}
You can also use
top -bn1 | grep 'Cpu(s)' | sed -n 's/.*, *\([0-9.]*\)%* id.*/\1/p' | awk '{print "CPU: " 100 - $1" %"}'
for faster response, but the result will be less accurate.
Is there a way to see how many context switches each thread generates? (both in and out if possible) Either in X/s, or to let it run and give aggregated data after some time.
(either on linux or on windows)
I have found only tools that give aggregated context-switching number for whole os or per process.
My program makes many context switches (50k/s), probably a lot not necessary, but I am not sure where to start optimizing, where do most of those happen.
On recent GNU/Linux systems you can use SystemTap to collect the data you want on every call to sched_switch(). The schedtimes.stp example is probably a good start: http://sourceware.org/systemtap/examples/keyword-index.html#SCHEDULER
Linux
I wrote a small script to see the details of a specific thread of the process. By executing this script you can see context switch as well.
if [ "$#" -ne 2 ]; then
echo "INVALID ARGUMENT ERROR: Please use ./see_thread.sh processName threadNumber"
exit
fi
ls /proc/`pgrep $1`/task | head -n$2 | tail -n+$2>temp
cat /proc/`pgrep $1`/task/`cat temp`/sched
Hope this will help.
I've a bash script that calculates voluntary and non-voluntary context switches made by a thread during a specific time frame. I'm not sure whether this will serve your purpose but I'll post it anyway.
This script is looping over all threads of a process and recording "voluntary_ctxt_switches" & "nonvoluntary_ctxt_switches" from /proc/< process-id>/task/< thread-id>/status. What I do generally is record these counters at the start of a performance run and record again at the end of the run and then calculate difference as total vol & non-vol ctx switches during the performance run.
pid=`ps -ef | grep <process name> | grep $USER | grep -v grep | awk '{print $2}'`
echo "ThreadId;Vol_Ctx_Switch;Invol_Ctx_Switch"
for tid in `ps -L --pid ${pid} | awk '{print $2}'`
do
if [ -f /proc/$pid/task/$tid/status ]
then
vol=`cat /proc/$pid/task/$tid/status | grep voluntary_ctxt_switches | grep -v nonvoluntary_ctxt_switches | awk '{print $NF}'`
non_vol=`cat /proc/$pid/task/$tid/status | grep nonvoluntary_ctxt_switches | awk '{print $NF}'`
fi
echo "$tid;$vol;$non_vol"
done
Script is bit heavy, in my case process has around 2500 threads. Total time to collect ctx switches is around 10 seconds.