I am trying to read in the following in line:
110134458.602 7 20957861.900
My format line is currently as follows:
READ(7,110,END=999) L1,C1,D1
write(*,*) L1,C1,D1
110 FORMAT(F14.3,1x,F1.0,2x,F14.3)
However the output I am receiving is:
110134458.60200000 7.0000000000000000 20957861.899999999
Why do I have so many decimal places and why is the final value not match?
Thank you!
It looks that you are reading the values correctly. With list-directed IO for the output the compiler will typically use the maximum number of digits for the numeric type. Not all decimal values will have exact finite precision binary equivalents -- that is probably what you are seeing for the 3rd number. If you use a format statement for the output, specifying fewer digits, the value will get rounded and appear correct.
Related
I want to apply data validation to my column so as to only accept whole numbers.
However I want these to be displayed with a dot so as to make it easier to read later on.
e.g. input = 14354 which is valid and then displayed 14.354
the data validation regular expression I am ussing is:
=regexmatch(to_text(A2);"^\d+\.*\d+$")
and the custom formatting is:
#,##
for most this working fine, large numbers are displayed with the '.' and things it shouldnt accept it is rejecting.
However, in the case of numbers which are entered with a decimal point as these are hidden, it is accepting it as valid.
It is also changing the format to auto atic and reading as date such entries like: 15.4
I should point out that I am using sheets in spanish and therefore the , is the marker for decimal places.
What am i missing here??
Select the cell range then go to Data > Data validation...
Add a custom formula rule:
=mod(A1;1)=0
Try this one:
=and(regexmatch(to_text(A2);"^\d+(\.\d{3})*$");mod(A2;1)=0)
Improved your formula to only accept a dot when it is followed by 3 numbers (this way, we invalidate the date e.g A2)
Combining the improved formula of yours and Aresvik's modulo answer, we need to check if the value does not have decimal. (this way, we invalidate the decimal e.g A6)
When both returns true, this shall confirm that the number inputted is a whole number with no decimal and not a date.
Output:
Invalid inputted values:
A2 - 15.4
A6 - 16412,212
I want to show amount like this format 100,000,000.00. In my code i defined variable like this
DEFINE VARIABLE mAMOUNT AS INTEGER FORMAT "999,999,999,999,99.99".
and mAMOUNT = 100,000,000.00and how ever i got amount like this 100000000 Plz help me
define variable amount as decimal ">>>,>>>,>>>,>>9.99" no-undo.
amount = 123456789.01.
display amount.
"9" in a FORMAT phrase forces a digit to be shown -- you might have an "all 9s" format if you wanted leading zeros but that is unusual.
If you intend to have decimal places you need to use the DECIMAL datatype, not INTEGER.
I want to convert a hexadecimal value to decimal value, perform some arithmetic operation and convert it back to hexadecimal.
In an attempt to do so, I am facing the following error,
"myshell.sh: line 77: 16##0x00a002: invalid number (error token is
"16##0x00a002")
The related line of code is:
SUBVER3_1=$((16##$SUBVER3_1))
Can someone let me know:
What this error is and how can i fix it?
How to perform arithmetic operations on hexadecimal numbers in shell?
The 0x prefix is not valid for base 16 notation. Strip it before converting. Also, if you are using Bash, the syntax for base conversion uses a single # after the base.
SUBVER3_1=$((16#${SUBVER3_1#0x}))
This uses the traditional POSIX ${variable#prefix} notation to strip off a prefix. The # in that is unrelated to the base#string notation.
The shell supports basic integer arithmetic. The arithmetic operations are independent of the base you are using; simple addition etc like $((255+255)) can use base-16 notation just as well $((16#FF+16#FF)) but keep in mind that division with only integers is of rather limited usefulness. If you want results in hex, printf can do that:
printf "%04x\n" $((16#ff + 16#ff))
The issue is now resolved,
I used print statement to fix this issue instead of the above statement
SUBVER3_1=$(printf "%x" $SUBVER3_1) # Converting from decimal to hexadecimal
This served the purpose
How can I use parameters in format descriptor in Fortran90?
I want to make a matrix, say square(n*n), but I want to make it general. So, I declared a parameter like this: integer,parameter::n=3 (say n is 3 here)
Then after inputting the elements of the matrix in a do/implied do loop, I want to write it with the format function as follows:
format(ni5)
But it gives the error: Unexpected element 'N' in format string
Any simple way to solve this??
Little-known fact: format specifiers can be constructed at runtime as a character string. This means that you can programmatically define the format specifier and pass it to the write statement.
CHARACTER(len=30) fm
INTEGER :: i
i = 3
WRITE(fm,'(a,i1,a)')"(",i,"i5)"
WRITE(*,fm)1,2,3
In the above, we are generating the actual format specifier with the number of integers that you need to print for the given situation (i), then using that string as the format of the second write statement.
I very rarely see people use this trick, and its possible that it is not defined in the actual standard, but it does work in gfortran.
I know ths is a common question here. I have read the solutions and modified the code then also i am not getting the solution so I have posted my code here.
when I read a value from the text box and parse the value into int from String in servlet, why does it show NumberFormatException?
String ph=request.getParameter("phone");
int phone=Integer.parseInt(ph.trim());// exception is generated here
You can't have any characters or symbols in an int AND the maximum size of an int is 2,147,483,647 which means the phone number 555 555 5555 would be to large to store in an int.
Change the parse to a long and it should fix your problem
A good rule to follow is do not store any number like SSN or Phone numbers's in numerical primitives. You want to leave the numerical primitives for values you plan on doing something math related. Keep them as strings if at all possible.
Because the value you are feeding it is not a valid integer. Make sure it doesn't have strange characters in it.
9835008199 is higher then MAXINT, so that's probaly it.
The docs tell me:
Throws NumberFormatException - if the string does not contain a parsable integer.
On another note: do not store phone numbers as integers. You will get in trouble (you are in fact already). Rule of thumb: if you do not want to do math with a number, it's not an int, but a string.
Use isNumber function to check whether it is a valid number.