Spring,Quartz and JobStoreTX - spring

Question

By using CronTriggerBean i have created two triggers(say trigger A & B) for invoking two different action. We have placed our project as .war in 2 servers.I am using JobStoreTX for clustering. The problem i am facing is that i want to cluster only one trigger i.e A and trigger B should not be clustered. Is there a way to specify through code which trigger has to be clustered. My code goes on as below.
<bean id="shedulerJobStoreTX" class="org.quartz.impl.jdbcjobstore.JobStoreTX>
<property name="driverDelegateClass" value="org.quartz.impl. jdbcjobstore.oracle.OracleDelegate">
<property name="dataSource" value ="jndiDS"/>
<property name="tablePrefix" value="someschemaName"/>
<property name="isClustered" value="true"/>
<property name="clusterCheckinInterval" value="${someValue}"/>
</bean>
<bean class="org.springframework.scheduling.quartz.SchedulerFactoryBean">
<property name="triggers">
<list>
<ref bean="cronTrigger" />
<ref bean="clusterCronTrigger"/>
</list>
</property>
</bean>
<bean id="cronTrigger" class="org.springframework.scheduling.quartz.CronTriggerBean">
<property name="jobDetail" ref="runAppJob" />
<property name="cronExpression" value="${someTimeValue1}"/>
</bean>
<bean id="clusterCronTrigger" class="org.springframework.scheduling.quartz.CronTriggerBean">
<property name="jobDetail" ref="runClusterJob" />
<property name="cronExpression" value="${someTimeValue2}"/>
</bean>
Hi, I have refined the code and the above said issue is not happening.PFB the code for the same.
<bean class="org.springframework.scheduling.quartz.SchedulerFactoryBean">
<property name="triggers">
<list>
<ref bean="cronTrigger" />
<ref bean="clusterCronTrigger"/>
</list>
</property>
<property name="quartzProperties">
<props>
<prop key="org.quartz.jobStore.isClustered">false</prop>
<prop key="org.quartz.scheduler.instanceId">AUTO</prop>
<prop key ="org.quartz.jobStore.class">org.quartz.impl.jdbcjobstore.
JobStoreTX </prop>
<prop key="org.quartz.jobStore.tablePrefix">schemaName</prop>
<prop key="org.quartz.jobStore.driverDelegateClass"> org.quartz.impl.jdbcjobstore.oracle.OracleDelegate</prop>
<prop key="org.quartz.jobStore.selectWithLockSQL"> SELECT * FROM {0}LOCKS UPDLOCK WHERE LOCK_NAME= ?</prop>
</props>
</property>
<property name="dataSource" ref="fsmJndiDataSource"/>
But the problem on executing the above code is that i am getting the below exception when the quartz is trying to get the lock ..."Invocation of init method failed; nested exception is org.quartz.SchedulerConfigException: Failure occured during job recovery. [See nested exception: org.quartz.impl.jdbcjobstore.LockException: Failure obtaining db row lock: ORA-00942: table or view does not exist"

Answer 1

you need to create required quartz tables in database before you run scheduler.
default quartz tables sql script is available at \docs\dbTables..
example if you are using quartz 2.2.1 distribution (quartz-2.2.1-distribution.tar\quartz-2.2.1\docs\dbTables\tables_oracle)
execute the sql script on database and make sure you see the tables created in it refer below image

Answer 2

Due to the message "ORA-00942: table or view does not exist", I think the table "schemaNameLOCKS" is missing. Indeed, from the doc:
org.quartz.jobStore.selectWithLockSQL
Must be a SQL string that selects a row in the "LOCKS" table and
places a lock on the row. If not set, the default is "SELECT * FROM
{0}LOCKS WHERE SCHED_NAME = {1} AND LOCK_NAME = ? FOR UPDATE", which
works for most databases. The "{0}" is replaced during run-time with
the TABLE_PREFIX that you configured above. The "{1}" is replaced with
the scheduler's name.