Get only one value from the table using LINQ - linq

Question

I have a Customer Table and a Address Table (customer_id, address_forename, address_surname, address_street, address_city, address_zip,
address_storedtime) where customer_id as a foreign key.
One customer can have several address.
Now I am trying to get only the last entered address using LINQ as bellow which should allow me put the address in a string and return that:
CODE:
var customerAddress = (from c in myDB.address
where (c.customer_id == customerId)
select new
{
c.customer_id,
c.address_forename,
c.address_surname,
c.address_street,
c.address_city,
c.address_zip,
c.address_storedtime
}).GroupBy(g => new
{
Customer = .customer_id,
Address = g.address_forename + " " + g.address_surname + " " + g.address_street + " " + g.address_city + " " + g.address_zip
}).Select(g => new
{
g.Key.Customer,
g.Key.Address,
StoredTime = g.Max(x => x.address_storedtime)
}).Disinct();/*First();*/
string result = "";
foreach (var ad in customerAddress)
{
if (ad.Address != null)
{
result = ad.Address;
}
break;
}
return result;
I am getting same address string for different addresses in DB for the Customer whereas I am trying to get only one.

Answer 1

Since you're already filtering by customer id, the grouping clause isn't necessary. You should be able to just order the results for the customer descending and project the address much more simply.
var customerAddress = (from c in myDB.address
where (c.customer_id == customerId)
orderby c.address_storedtime descending
select c.address_forename + " " + c.address_surname + " " + c.address_street + " " + c.address_city + " " + c.address_zip)
.FirstOrDefault();

Answer 2

Replace your foreach by
var result =
customerAdress.Any(ad => ad.Address != null)
? customerAdress.Last(ad => ad.Address != null).Address
: default(string);