I want to get the data of the higher band and lower band of the Bollinger Band because I want the difference of the two data, how could I do that? thanks. (Teechart2011Eval & VB6)
Having a Chart with a Candle series, you have to add a FastLine series and set it to be a Bollinger function as shown here:
TChart1.Aspect.View3D = False
TChart1.AddSeries scCandle
TChart1.Series(0).FillSampleValues
TChart1.AddSeries scFastLine
TChart1.Series(1).SetFunction tfBollinger
TChart1.Series(1).DataSource = TChart1.Series(0)
Doing it, the FastLine you created is the High Bollinger Band, and a third series (another FastLine series) is created internally to represent the Low Bollinger Band. Then, to access the High Bollinger Band values you can just do it like this:
TChart1.Series(1).YValues.Value(i)
And to access the Lower Bollinger Band, you have two ways:
Through the Bollinger function in the FastLine you created:
TChart1.Series(1).FunctionType.asBollinger.LowBand.YValues.Value(i)
Directly using the series index of the series created internally:
TChart1.Series(2).YValues.Value(i)
Related
I am using working on Tableau stacked bar chart.
The bar chart represents the total %. Therefore, the length of bar chart is equal.
Now I would like to sort the dimension (referee) based on the values of legends ( highest to lowest).
can anyone suggest me how to do it.
I also attached the packaged workfile here
Here is the picture of sort screen;
Level of data source below:
Below is the screen shot based on the final answer provided:
Thanks,
Zep
So to get this you first need to get a calc field that gets the win %:
SUM(IF [FTR] = 'AWins' OR [FTR] = 'Hwins' THEN 1 END)/COUNTD([Game ID])
This can then be used to rank the referees:
Now the reason that it may not be working for you with your technique is that you're sorting on COUNTD(Wins) which is the total number of wins, not the percentage wins for the ref. So someone that has just played more games may come up higher in the rank
Now you have the calc field, you can go back to your report and sort on the new field:
I rearranged the legend so you can see that the ref with the best % wins are shown first (red and blue bars)
If you don't want it sorted by win %, then change the calc field to:
SUM(IF [FTR] = 'AWins' OR [FTR] = 'Hwins' THEN 1 END)
For the COUNTD of games, if you only have the date and the game available and want to create an ID from that that is unique, create a calc field like this:
game-date-id = STR([game]) + STR(' ') + STR(date)
This will then be used in your COUNTD if statement:
SUM(IF [FTR] = 'AWins' OR [FTR] = 'Hwins' THEN 1 END)/COUNTD([game-date-id])
I have attached the picture of the dashboard.
I want to sort the referee based of Hwin
Yeah. It did not work out as expected
not sure how to do this. I have the following data:
Date, Country, QuantityA, QuantityB.
I want to make a timeline Chart with the ratio between Quantity A and B. I also want to create a barChart with Country, which will show the ratio in every country.
The problem is that the ratios are not additive, so if I do this:
var timeDim = ndx.dimension(function(d) {return d.Date;});
ratioAB = timeDim.group().reduceSum(function(d) {return QuantityA/QuantityB}
This will return the ratios for every country separately and will add them up. What I want is to add up QuantityA and QuantityB and then do the ratio.
Thus, the timeline chart will only show the right ratio if I filter in one of the countries.
Is there a way to add both the country and the date as a dimension?
You can create a custom grouping to calculate the sum of QuantityA, the sum of QuantityB, and the ratio between the 2. Or you could just create 2 sum groups, one summing QuantityA, the other QuantityB, and then calculate the ratio when you build the visualization.
I am using the pack layout for packing different no of equal sized circles. I have a group of clusters to be visualized. So I am calling pack function for each cluster of circles. In all the d3 examples the diameter is either calculated with the given size or fixed diameter. I would like to calculate it according to the no of circles to be packed. So how do I calculate the packing circle diameter?
is there any formula so that I can pack the circles without wasting the space.
If you truly don't care about relative sizing of the circles, then you could make your JSON file represent only the data you care about(say, names) and feed your packing function a dummy value that the 'value' accessor function is expecting.
For instance:
var circleChildren = [{
"value": 1
}, {
"value": 1
}, {
"value": 1
}, {
"value": 1
}];
would give you a JSON object that you can use as children for your packing function:
var circleInput = Object();
circleInput.children = circleChildren;
You can verify that in your console by running:
bubble.nodes(circleInput)
.filter(function (d) {
return !d.children; //we're flattening the 'parent-child' node structure
})
where bubble is your D3 packing bubble variable.
Here's a fiddle that demonstrates that. It may have some extra things but it implements what you're looking for. In addition, you can play around with the number of circles by adding more dummies in the JSON file, as well as changing the SVG container size in the diameter variable. Hope that helps!
EDIT: The size of your layout(in this case, a misnomer of the 'diameter' variable) directly determines the size and diameter of your circles within. At some point you have to assign the pack.size() or pack.radius() value in order for your circles to display within a layout(documentation ):
If size is specified, sets the available layout size to the specified two-element array of numbers representing x and y. If size is not specified, returns the current size, which defaults to 1×1.
Here you have several options:
If you want your circles to be 'dynamically' sized to your available element's width (that is, if you want them to cover up all the element width available) then I'd recommend you get your element's width beforehand, and then apply in your pack() function. The problem is then you have to think about resizing, etc.
If you want to keep the maximum sizing available, then you have to make your viz responsive. There's a really good question already in SO that deals with that.
I know this isn't the full solution but hopefully that points you in the right direction for what you're trying to do.
FURTHER EDIT:
All of a sudden, another idea came to mind. Kind of an implementation of my previous suggestion, but this would ensure you're using the maximum space available at the time for your circle drawing:
zone = d3.select("#myDiv");
myWidth = zone.style("width").substring(0, zone.style("width").length - 2);
I have a histology image like this:
From the image, we can observe there are two kinds of different cells.
and
Is there any way that I can separate these two types of cells into two groups?
How about using your raw image and previous code to achieve this?
% % % your old code
I=imread(file);
t1=graythresh(I);
k1=im2bw(I,t1);
k1=~k1;
se = strel('disk',1);
k0=imfill(~k1,'holes');
cc = conncomp(k0);
k0(cc.PixelIdxList{1})=0;
k1=imfill(k1,'holes');
mask=k0 | k1;
%%%%%%%%%%%%%%%%%%
This will give you:
I=rgb2hsv(I);
I=double(I);
I1=I(:,:,1); % again, the channel that can maximizing the margin between donut and full circle
Imask=(I1-0.2).*(I1-0.9)<0;
k2=mask-Imask;
k2=bwareaopen(k2,100);
This will give you:
k2=mask-Imask;
I2=zeros(size(I1,1),size(I1,2),3);
I2(:,:,1)=(k2==1)*255;
I2(:,:,3)=((I1-0.2).*(I1-0.9)<0)*255;
imshow(I2)
will finally give you (the two types are stored in two channels in the rgb image):
I would use regionprops
props=regionprops(YourBinaryImage, 'Solidity');
The objects with a high solidity will be the disks, those with a lower solidity will be the circles.
(Edit) More formally:
I=imread('yourimage.jpg');
Bw=~im2bw(I, 0.5);
BWnobord = imclearborder(Bw, 4); % clears the partial objects
Props=regionprops(BWnobord, 'All');
solidity=cell2mat({Props.Solidity});
Images={Props.Image};
Access the elements of Images where the value in solidity is higher than 0.9 and you get your disks. The circles are the other ones.
Hope it helps
I made a simulation of 10000 times and want to view part of simulation between 5000-5200. I am able to view it with the code below, but the x-axis says 0-250. I want the x-axis to display the exact figure of 5000-5200. Also there seems to be a small gap at the end of the figure as the axis runs up to 250 for some reason. I just want to view the figure in for this set time with the x-axis showing the exact labels and without the gap at the end.
Thanks
N=10000;%Number of simulation
P=0.02;
Q = zeros(N,1); %current value of queue
X=zeros(N,1);%simulation data
Ci=0;
L=0.9;
Bu=zeros(N,1);
Bs=30;
Bd1=50;
Bd2=270;
Ti=0;
for Ti=2:N
U=rand(1);
a=log10(U);
b=log10(1-P);
c=(a/b);
d=1+c;
X(Ti)=round(d);
Ci=Ci+1;
if X(Ti)< (L)*(Bs)
Bu(Ti)=Bs;
else if X(Ti) < (L)*(Bs+Bd1)
Bu(Ti)=Bs+Bd1;
else
Bu(Ti)=Bs+Bd1+Bd2;
end
end
Ti=Ti+1;
end
plot(X(5000:5200,1),'r');
set (gca,'ylim',[0 400]);
hold on;
plot(Bu(5000:5200,1),'b');
set (gca,'ylim',[0 400]);
hold off
Plot expects two inputs, the first depicting the horizontal axis and the second depicting the vertical axis. When you do not supply two inputs, then it computes the length of the single input (in this case that length is 5200-5000 = 200), and it just uses 1 through that length (1:200 in this case) as if it is the values for the horizontal axis variable.
I think you want to issue the command:
plot(5000:5200, X(5000:5200,1), 'r')
Often Matlab will adjust plot axes for better default views, so it's probably showing the axis out to the index 250 just by virtue of some default plotting convention. You can similarly use set(gca, 'xlim', [5000 5200]) if you wish.