I'm trying to get the first key and value key from a hash table in ruby. I don't know the key values of the hash because it is passed to the method. I cant find anywhere online how to find the first key/value as a separate hash table.
I think hash[0] will just try to find an element with a name 0 it just returns nil when I run the code.
I know I can find the key name and the value and then create a new hash from them but i wonder if there is an easier way to do this so I get a hash right away.
here is my code:
def rps_game_winner(game)
rock_in_hash = game.invert['R']
paper_in_hash = game.invert['P']
scissors_in_hash = game.invert['S']
if(rock_in_hash)
if(paper_in_hash)
return paper_in_hash;
elsif(scissors_in_hash)
return rock_in_hash
end
elsif(paper_in_hash)
if(rock_in_hash)
return paper_in_hash
elsif(scissors_in_hash)
return scissors_in_hash
end
end
key = game.keys[-1]
value = game.values[-1]
winner = {key => value}
return winner
end
game_one = { "Bob" => 'P', "Jim" => 'P' }
puts rps_game_winner(game_one)
This gets me the correct result the problem is I don't understand why it's -1 instead of zero...
And i was hoping there was a better way to get the first key/value pair of a hash table instead of creating new hash table with the key and value you retrieved from the previous table.
You can just do
key, value = hash.first
or if you prefer:
key = hash.keys[0]
value = hash.values[0]
Then maybe:
new_hash = {key => value}
There is a shorter answer that does not require you to use extra variables:
h = { "a" => 100, "b" => 200 , "c" => 300, "d" => 400, "e" => 500}
Hash[*h.first] #=> {"a" => 100}
Or if you want to retrieve a key/value at a any single position
Hash[*h.to_a.at(1)] #=> {"b" => 200}
Or retrieve a key/values from a range of positions:
Hash[h.to_a[1,3]] #=> {"b"=>200, "c"=>300, "d"=>400}
[hash.first].to_h
Another way to do it.
my_hash = { "a" => "first", "b" => "second" }
{ my_hash.keys.first => my_hash.values.first }
This works too
Related
I am trying to run through the following hash
my_family_pets_ages = {"Evi" => 6, "Hoobie" => 3, "George" => 12, "Bogart" => 4, "Poly" => 4, "Annabelle" => 0, "Ditto" => 3}
and return an array of the keys whose values match a specified integer for age. So, for example, if I wanted to find all of the pets that are 3 years old, it would return an array of just their names.
["Hoobie", "Ditto"]
I have the following method, but I can't seem to get the method to return an array of just the keys, but I keep just getting the key => value in an array like this:
["Hoobie"=>3, "Ditto"=>3]
Here is the method I have so far
def my_hash_finding_method(source, thing_to_find)
source.select {|name, age| name if age == thing_to_find}
end
Any pointers? I'm stuck on how to return only the keys
Just use #select, then #keys to get an array of the matching keys:
def my_hash_finding_method(source, thing_to_find)
source.select { |name, age| age == thing_to_find }.keys
end
See Hash#keys for more information.
This is my code
lunch_order = {
"Ryan" => "wonton soup",
"Eric" => "hamburger",
"Jimmy" => "sandwich",
"Sasha" => "salad",
"Cole" => "taco"
}
lunch_order.each { |element| puts element }
I want the value to be printed out, but here, both the value and the key are printed.
You can use
lunch_order.each { |key, value| puts value}
Codepad Example
You can loop over the values only with each_value
h = { "a" => 100, "b" => 200 }
h.each_value {|value| puts value }
You can read more about api of hash here.
So many ways to do it in Ruby:
lunch_order.values.each { |element| puts element }
In Ruby a hash contains Keys and Values. So in your case the keys are:
Keys
Ryan
Eric
Jimmy
Sasha
Cole
And the Values for those keys are:
Values
Wonton Soup
Hamburger
Sandwich
Salad
Taco
And all you'd need to do to call the values is use the each loops like you've done but instead of using element as the local variable within the block, you use something like this:
lunch_order.each do { |key, value| puts value }
lunch_order.each_pair { |key,value| puts value }
Docs: http://apidock.com/ruby/Hash/each_pair
Given your original code
lunch_order = {
"Ryan" => "wonton soup",
"Eric" => "hamburger",
"Jimmy" => "sandwich",
"Sasha" => "salad",
"Cole" => "taco"
}
You created a hash, which consists of both keys and values. Keys are on the left, values on the right. To get only the values use
lunch_order.values.each{|value| puts value}
Hope this helps.
I have a user inputed string called x_value whose value contains something like ticker|high. Whenever there is a |, that indicates that the latter is a child of the former. The purpose of the method is to return a specific value within a hash.
sections = []
object.x_value.split('|').each do |part|
sections << part.to_sym
end
I then want to drill down the data hash and retrieve the value of the last key.
data = {"ticker":{"high":529.5,"low":465,"avg":497.25,"vol":7520812.018}}
In this example
data[sections[0]][sections[1]] returns the expected 529.5 value. However, the user may have different hashes and different levels deep of nested key/values. How can I write this?
I have tried data[sections], but that didn't work.
Use Enumerable#reduce
data = {"ticker" => {"high" => 529.5, "low" => 465,"avg" => 497.25,"vol" => 7520812.018}}
"ticker|high".split('|').reduce(data) { |dat,val| dat[val] } #=> 592.5
more example:
data = {"more_ticker" => {"ticker" => {"high" => 529.5, "low" => 465,"avg" => 497.25,"vol" => 7520812.018}}}
"more_ticker|ticker|avg".split('|').reduce(data) { |dat,val| dat[val] }
#=> 497.25
You could also use recursion:
def getit(hash, x_value)
recurse(hash, x_value.split('|'))
end
def recurse(hash, keys)
k = keys.shift
keys.empty? ? hash[k] : recurse(hash[k], keys)
end
data = {"ticker" => {"high" => 529.5, "low" => 465}}
getit(data, "ticker|high") #=> 529.5
getit(data, "ticker") #=> {"high"=>529.5, "low"=>465}
data = {"more_ticker" => {"ticker" => {"high" => 529.5, "low" => 465}}}
getit(data, "more_ticker|ticker|low") #=> 465
getit(data, "more_ticker|ticker|avg") #=> nil
Given two hashes, I'm trying to replace a value in the first hash for a key that the second hash also has. To be specific, I have these two hashes:
data = {
"study" => "Lucid Study",
"name" => "Lucid Plan",
"studyWillBe" => "Combination"
}
conditions = { "study" => "((current))" }
I want data to have its "study" key updated since conditions has that key. I want data to end up like this:
data = {
"study" => "((current))",
"name" => "Lucid Plan",
"studyWillBe" => "Combination"
}
I got this far:
data = Hash[data.map {|k, v| [conditions[k] || k, v] }]
but that's not quite doing the trick. Can anyone point me in the right direction?
You can do this
data.each {|k, v| data[k] = conditions[k] if conditions[k]}
It's called merge.
data = {"study"=>"Lucid Study", "name"=>"Lucid Plan", "studyWillBe"=>"Combination"}
conditions = {"study"=>"((current))"}
data.merge(conditions)
#{"study"=>"((current))", "name"=>"Lucid Plan", "studyWillBe"=>"Combination"}
The method merge can take a block where you can make some specific operation not only assign new value
data.merge(conditions) do |key, oldvalue, newvalue|
newvalue
end
=> {"study"=>"((current))", "name"=>"Lucid Plan", "studyWillBe"=>"Combination"}
Given I have the below clients hash, is there a quick ruby way (without having to write a multi-line script) to obtain the key given I want to match the client_id? E.g. How to get the key for client_id == "2180"?
clients = {
"yellow"=>{"client_id"=>"2178"},
"orange"=>{"client_id"=>"2180"},
"red"=>{"client_id"=>"2179"},
"blue"=>{"client_id"=>"2181"}
}
Ruby 1.9 and greater:
hash.key(value) => key
Ruby 1.8:
You could use hash.index
hsh.index(value) => key
Returns the key for a given value. If
not found, returns nil.
h = { "a" => 100, "b" => 200 }
h.index(200) #=> "b"
h.index(999) #=> nil
So to get "orange", you could just use:
clients.key({"client_id" => "2180"})
You could use Enumerable#select:
clients.select{|key, hash| hash["client_id"] == "2180" }
#=> [["orange", {"client_id"=>"2180"}]]
Note that the result will be an array of all the matching values, where each is an array of the key and value.
You can invert the hash. clients.invert["client_id"=>"2180"] returns "orange"
You could use hashname.key(valuename)
Or, an inversion may be in order. new_hash = hashname.invert will give you a new_hash that lets you do things more traditionally.
try this:
clients.find{|key,value| value["client_id"] == "2178"}.first
According to ruby doc http://www.ruby-doc.org/core-1.9.3/Hash.html#method-i-key key(value) is the method to find the key on the base of value.
ROLE = {"customer" => 1, "designer" => 2, "admin" => 100}
ROLE.key(2)
it will return the "designer".
From the docs:
(Object?) detect(ifnone = nil) {|obj| ... }
(Object?) find(ifnone = nil) {|obj| ... }
(Object) detect(ifnone = nil)
(Object) find(ifnone = nil)
Passes each entry in enum to block. Returns the first for which block is not false. If no object matches, calls ifnone and returns its result when it is specified, or returns nil otherwise.
If no block is given, an enumerator is returned instead.
(1..10).detect {|i| i % 5 == 0 and i % 7 == 0 } #=> nil
(1..100).detect {|i| i % 5 == 0 and i % 7 == 0 } #=> 35
This worked for me:
clients.detect{|client| client.last['client_id'] == '2180' } #=> ["orange", {"client_id"=>"2180"}]
clients.detect{|client| client.last['client_id'] == '999999' } #=> nil
See:
http://rubydoc.info/stdlib/core/1.9.2/Enumerable#find-instance_method
The best way to find the key for a particular value is to use key method that is available for a hash....
gender = {"MALE" => 1, "FEMALE" => 2}
gender.key(1) #=> MALE
I hope it solves your problem...
Another approach I would try is by using #map
clients.map{ |key, _| key if clients[key] == {"client_id"=>"2180"} }.compact
#=> ["orange"]
This will return all occurences of given value. The underscore means that we don't need key's value to be carried around so that way it's not being assigned to a variable. The array will contain nils if the values doesn't match - that's why I put #compact at the end.
Heres an easy way to do find the keys of a given value:
clients = {
"yellow"=>{"client_id"=>"2178"},
"orange"=>{"client_id"=>"2180"},
"red"=>{"client_id"=>"2179"},
"blue"=>{"client_id"=>"2181"}
}
p clients.rassoc("client_id"=>"2180")
...and to find the value of a given key:
p clients.assoc("orange")
it will give you the key-value pair.