Bash - get variables from an external file - bash

I'm trying to make a configuration file to help running a bash script.
The idea is having a file (script.conf) like this
directory=c:/path/to/a/specific/directory/
logo=y
title=y
hotspots=n
combobox=n
Then, running the script, it will read script.conf and get those variables to use in the script.
How can I do that?

The source command (also known as ., but not to be confused with the directory of the same name) will allow you to run another file in the current shell. Simply make that file contain variable assignments.
foo.sh
#!/bin/bash
. bar.sh
echo "$baz"
bar.sh
baz=42

Related

shell program to build a stack in Linux ubuntu [duplicate]

How to set a global environment variable in a bash script?
If I do stuff like
#!/bin/bash
FOO=bar
...or
#!/bin/bash
export FOO=bar
...the vars seem to stay in the local context, whereas I'd like to keep using them after the script has finished executing.
Run your script with .
. myscript.sh
This will run the script in the current shell environment.
export governs which variables will be available to new processes, so if you say
FOO=1
export BAR=2
./runScript.sh
then $BAR will be available in the environment of runScript.sh, but $FOO will not.
When you run a shell script, it's done in a sub-shell so it cannot affect the parent shell's environment. You want to source the script by doing:
. ./setfoo.sh
This executes it in the context of the current shell, not as a sub shell.
From the bash man page:
. filename [arguments]
source filename [arguments]
Read and execute commands from filename in the current shell
environment and return the exit status of the last command executed
from filename.
If filename does not contain a slash, file names in PATH are used to
find the directory containing filename.
The file searched for in PATH need not be executable. When bash is not
in POSIX mode, the current directory is searched if no file is found
in PATH.
If the sourcepath option to the shopt builtin command is turned off,
the PATH is not searched.
If any arguments are supplied, they become the positional parameters
when filename is executed.
Otherwise the positional parameters are unchanged. The return status
is the status of the last command exited within the script (0 if no
commands are executed), and false if filename is not found or cannot
be read.
source myscript.sh is also feasible.
Description for linux command source:
source is a Unix command that evaluates the file following the command,
as a list of commands, executed in the current context
#!/bin/bash
export FOO=bar
or
#!/bin/bash
FOO=bar
export FOO
man export:
The shell shall give the export attribute to the variables corresponding to the specified names, which shall cause them to be in the environment of subsequently executed commands. If the name of a variable is followed by = word, then the value of that variable shall be set to word.
A common design is to have your script output a result, and require the cooperation of the caller. Then you can say, for example,
eval "$(yourscript)"
or perhaps less dangerously
cd "$(yourscript)"
This extends to tools in other languages besides shell script.
In your shell script, write the variables to another file like below and source these files in your ~/.bashrc or ~/.zshrc
echo "export FOO=bar" >> environment.sh
In your ~/.bashrc or ~/.zshrc, source it like below:
source Path-to-file/environment.sh
You can then access it globally.
FOO=bar
export FOO

How to reference a file for variables using ksh?

How do I reference a variable from another file using ksh?
I know in bash you just use "source script" and then "echo $variable"
but in ksh, when I try that, it does not work.
example I am trying to do:
config.sh:
variable=apple
access_var.sh:
#!/bin/bash
source config.sh
echo $variable
in ksh I just get " config.sh: cannot open [No such file or directory]"
Provide a path for to the file. If the file is in the current directory use source ./config.sh. Otherwise an absolute or relative path is OK, the latter must not start with ./.
If you don't provide a path ksh searches the file in the directories in $PATH.
(And remember to change the shebang in the other script to whereever your ksh is (or make sure your scripts are POSIX shell compatible and just use #!/bin/sh to have scripts with a high chance to run everywhere).)

Is there a good way to preload or include a script prior to executing another script?

I am looking to execute a script but have it include another script before it executes. The problem is, the included script would be generated and the executed script would be unmodifiable. One solution I came up with, was to actually reverse the include, by having the include script as a wrapper, calling set to set the arguments for the executed script and then dotting/sourcing it. E.g.
#!/bin/bash
# Generated wrapper or include script.
: Performing some setup...
target_script=$1 ; shift
set -- "$#"
. "$target_script"
Where target_script is the script I actually want to run, importing settings from the wrapper.
However, the potential problem I face is that callers of the target script or even the target script itself may be expecting $0 to be set to the path of it's location on the file system. But because this wrapper approach overrides $0, the value of $0 may be unexpected and could produce undefined behaviour.
Is there another way to perform what is in effect, an LD_PRELOAD but in the scripted form, through bash without interfering with its runtime parameters?
I have looked at --init-file or --rcfile, but these only seem to be included for interactive shells.
Forcing interactive mode does seem to allow me to specify --rcfile:
$ bash --rcfile /tmp/x-include.sh -i /tmp/xx.sh
include_script: $0=bash, $BASH_SOURCE=/tmp/x-include.sh
target_script: $0=/tmp/xx.sh, $BASH_SOURCE=/tmp/xx.sh
Content of the x-include.sh script:
#!/bin/bash
echo "include_script: \$0=$0, \$BASH_SOURCE=$BASH_SOURCE"
Content of the xx.sh script:
#!/bin/bash
echo "target_script: \$0=$0, \$BASH_SOURCE=$BASH_SOURCE"
From the bash documentation:
When bash is started non-interactively, to run a shell script, for example, it looks for the variable BASH_ENV in
the environment, expands its value if it appears there, and uses the expanded value as the name of a file to read
and execute. Bash behaves as if the following command were executed:
if [ -n "$BASH_ENV" ]; then . "$BASH_ENV"; fi
but the value of the PATH variable is not used to search for the file name.
So that settles it then:
BASH_ENV=/tmp/x-include.sh /bin/bash /tmp/xx.sh

How to run 'cd' in shell script and stay there after script finishes?

I used 'change directory' in my shell script (bash)
#!/bin/bash
alias mycd='cd some_place'
mycd
pwd
pwd prints some_place correctly, but after the script finished my current working directory doesn't change.
Is it possible to change my path by script?
You need to source the file as:
. myfile.sh
or
source myfile.sh
Without sourcing the changes will happen in the sub-shell and not in the parent shell which is invoking the script. But when you source a file the lines in the file are executed as if they were typed at the command line.
While sourcing the script you want to run is one solution, you should be aware that this script then can directly modify the environment of your current shell. Also it is not possible to pass arguments anymore.
Another way to do, is to implement your script as a function in bash.
function cdbm() {
cd whereever_you_want_to_go
echo arguments to the functions were $1, $2, ...
}
This technique is used by autojump:
http://github.com/joelthelion/autojump/wiki
to provide you with learning shell directory bookmarks.
The script is run in a separate subshell. That subshell changes directory, not the shell you run it in. A possible solution is to source the script instead of running it:
# Bash
source yourscript.sh
# or POSIX sh
. yourscript.sh
It can be achieved by sourcing. Sourcing is basically execute the script in the same shell whereas normal execution(sh test.sh or ./test.sh) will create sub shell and execute script there.
test.sh
cd development/
ls
# Do whatever you want.
Execute test.sh by
source test.sh
. is shortest notation for source. So you can also do by
. test.sh
This will execute the script and change the directory of current shell to development/.
whenever you run a script on your login shell, a new subprocess is spawned and the script execution is done in a subshell.Once the script completes, the subshell exits and you are returned to the login shell.Hence whenever you do a cd through a script,the directory is changed to the path specified by cd, but by the time script finishes you come back to your login shell to the working directory from where you started the script.
The way to overcome this is use,
source yourscript.sh
what source does is it executes the script as TCL script, i.e it has the same effect as when you typed each line on the command line of your login shell and it executed from there. So this way when the script finishes after cd , it stays in that directory.
Another practical solution is to end your script by opening another shell session.
For instance:
#!/bin/bash
cd some_place
bash
This is useful, in my case, for scripts located in my ~/bin for instance, called from any other place. It is just a bit painful to type source ~/bin/mygoodoldscript instead of mygoo<TAB><ENTER>.
The downside is that the additional shell takes up a few more resources (not much).
Though there are answers. I think the intention of question is to use script to navigate to specific path.
Here is a simple practical solution works here without cancel out existing terminal environment flag.
provide a bash/tch/sh script to work for path generation
/* .goto.sh */
#!/usr/bin/env bash
echo '~/workspace'
add alias to the script output
alias goto 'cd `.goto.sh`'

Global environment variables in a shell script

How to set a global environment variable in a bash script?
If I do stuff like
#!/bin/bash
FOO=bar
...or
#!/bin/bash
export FOO=bar
...the vars seem to stay in the local context, whereas I'd like to keep using them after the script has finished executing.
Run your script with .
. myscript.sh
This will run the script in the current shell environment.
export governs which variables will be available to new processes, so if you say
FOO=1
export BAR=2
./runScript.sh
then $BAR will be available in the environment of runScript.sh, but $FOO will not.
When you run a shell script, it's done in a sub-shell so it cannot affect the parent shell's environment. You want to source the script by doing:
. ./setfoo.sh
This executes it in the context of the current shell, not as a sub shell.
From the bash man page:
. filename [arguments]
source filename [arguments]
Read and execute commands from filename in the current shell
environment and return the exit status of the last command executed
from filename.
If filename does not contain a slash, file names in PATH are used to
find the directory containing filename.
The file searched for in PATH need not be executable. When bash is not
in POSIX mode, the current directory is searched if no file is found
in PATH.
If the sourcepath option to the shopt builtin command is turned off,
the PATH is not searched.
If any arguments are supplied, they become the positional parameters
when filename is executed.
Otherwise the positional parameters are unchanged. The return status
is the status of the last command exited within the script (0 if no
commands are executed), and false if filename is not found or cannot
be read.
source myscript.sh is also feasible.
Description for linux command source:
source is a Unix command that evaluates the file following the command,
as a list of commands, executed in the current context
#!/bin/bash
export FOO=bar
or
#!/bin/bash
FOO=bar
export FOO
man export:
The shell shall give the export attribute to the variables corresponding to the specified names, which shall cause them to be in the environment of subsequently executed commands. If the name of a variable is followed by = word, then the value of that variable shall be set to word.
A common design is to have your script output a result, and require the cooperation of the caller. Then you can say, for example,
eval "$(yourscript)"
or perhaps less dangerously
cd "$(yourscript)"
This extends to tools in other languages besides shell script.
In your shell script, write the variables to another file like below and source these files in your ~/.bashrc or ~/.zshrc
echo "export FOO=bar" >> environment.sh
In your ~/.bashrc or ~/.zshrc, source it like below:
source Path-to-file/environment.sh
You can then access it globally.
FOO=bar
export FOO

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