how to show data from 3 tables in one view, because using JTable i can show data only bind to that JTable, please help me with this one.
my code so far(not working) in models:
public function getEntireProject(){
$item_id = $this->getItem()->id;
$db =& JFactory::getDBO();
$query = $db->getQuery(true);
$query->select('*');
$query->from('#__project_part_1 AS a');
$query->leftJoin('#__project_part_2 AS u ON a.uuid = u.uuid');
$query->leftJoin('#__project_part_3 AS y ON a.uuid = y.uuid');
$query->where('a.id = '. (int) $item_id);
$db->setQuery($query);
return $db->loadResult();
}
protected function loadFormData()
{
// Check the session for previously entered form data.
$data = JFactory::getApplication()->getUserState('com_web_projects.edit.webproject.data', array());
if (empty($data)) {
$data = $this->getEntireProject();
}
return $data;
}
try to overwrite getItem function.This will also be helpful if you are calling get('Item') in view. -
public function getItem($pk = null){
if ($item = parent::getItem($pk)) {
$db =& JFactory::getDBO();
$query = $db->getQuery(true);
$query->select('*');
$query->from('#__project_part_1 AS a');
$query->leftJoin('#__project_part_2 AS u ON a.uuid = u.uuid');
$query->leftJoin('#__project_part_3 AS y ON a.uuid = y.uuid');
$query->where('a.id = '. (int) $item->id);
$db->setQuery($query);
$item = $db->loadAssoc();
}
return $item;
}
protected function loadFormData()
{
// Check the session for previously entered form data.
$data = JFactory::getApplication()->getUserState('com_web_projects.edit.webproject.data', array());
if (empty($data)) {
$data = $this->getItem();
}
return $data;
}
For Multi-Row Results use loadRowList(), loadAssocList(), loadAssocList($key), loadObjectList(), loadObjectList('key'). $db->loadResult() only load one result. Read more.
If I understand your question right this should fix your problem. If you not please ask.
Related
I have this doubt.
// This is my controller
public function profile()
{
$session_data = $this->session->userdata('logged_in');
$uid= $session_data['id'];
$pic = $this->user_model->getImage($uid);
$data['profile_pic']= $pic ;
$data['row'] = $this->user_model->get_user_data($uid);
$test = $this->load->view('profile_view',$data,TRUE);
echo $test;exit;
}
Based on name it seems to be:
public function profile()
{
$session_data = $this->session->userdata('logged_in');//checking user login or not
$uid= $session_data['id'];//getting id from session
$pic = $this->user_model->getImage($uid);//geting user image
$data['profile_pic']= $pic ;//storing image to data array
$data['row'] = $this->user_model->get_user_data($uid);//passing $uid to model and store in data array what row model returns
$test = $this->load->view('profile_view',$data,TRUE);//passing data array to view
echo $test;exit;
}
//model
i am passing user id only
public function get_user_data($uid){
//echo $uid;exit;
$data = array();
$this->db->select('*');
$this->db->from('user');
$this->db->where('id',$uid);
$query = $this->db->get();//checking that $uid data in database
if($query->num_rows() > 0){
$get_user_data=$query->result();
//print_r($get_user_data);exit;
//print_r($items);exit;
return $get_user_data; // if find, return data to controller
}
else{
return FALSE;
}
//return $query->row();
}
Ok I want to pass two variables from a controller to a model but I get some kind of error. Am I passing variables on right way? My syntax is:
Controller:
public function add_tag(){
if(isset($_POST['id_slike']) && isset($_POST['id_taga'])){
$slika = $_POST['id_slike'];
$tag = $_POST['id_taga'];
$this->load->model("Member_model");
$res = $this->Member_model->add_tags($slike, $tag);
foreach ($res->result() as $r){
echo $r->name;
}
}
else{
echo "";
}
}
Model:
public function add_tags(){
$data = array(
'tags_id' => $tag ,
'photos_id' => $slika
);
$check = $this->db->query("SELECT tags_id,photos_id FROM bridge WHERE bridge.tags_id='{$tag}' AND bridge.photos_id={$slika} ");
if($check->num_rows()==0){
$this->db->insert('bridge',$data);
$res = $this->db->query("SELECT name FROM tags where `tags`.`id`='{$tag}' ");
return $res;
}
}
you are passing variables correctly, but do not get them correctly in the model, which should look like this:
public function add_tags($slike, $tag){
//your other code
}
The following code write on the controller file:-
$data = array();
$this->load->model('dbmodel');
$data['item'] = $this->dbmodel->getData('*','catagory',array('cat_id'=>21));
$this->load->view('listing_view', $data);
The following code write on the dbmodel file:-
public function getData($cols, $table, $where=array()){
$this->db->select($cols);
$this->db->from($table);
$this->db->where($where);
$query = $this->db->get();
$result = $query->result();
return $result;}
How i can get some parameters from a disabled/not yet actived plugin in joomla 1.6/2.5?
$module = JPluginHelper::getPlugin('system','myplugin');
$moduleParams = new JParameter($module->params);
$val = $moduleParams->get("key");
This method didn't work becouse i need to use within an element JFormField generator.
Thanks for help!
With JPluginHelper::getPlugin it's possible to access only enabled plugins, so here's the code for direct access to database.
// Build query
$db = JFactory::getDbo();
$query = $db->getQuery(true);
$query
->select( 'params' )
->from( '#__extensions' )
->where( 'type = ' . $db->q('plugin') )
->where( 'folder = ' . $db->q('authentication') ) // Plugin type
->where( 'element = ' . $db->q('gmail') ) // Plugin element
;
// Execute query
$db->setQuery($query);
try
{
$result = $db->loadResult();
}
catch (RuntimeException $e)
{
return false;
}
// Parse parameters
if (!empty($result))
{
$params = new JRegistry($result);
$val = $params->get('key', 'defaultValue');
}
You may store query results in in the JFormField Object so save database queries in case field is availabile multiple times.
protected $results = null;
Perhaps you may want to try this:
// Get plugin parameters
$db = JFactory::getDBO();
$query = $db->getQuery(true);
$query->select('`params`')
->from ('`#__extensions`')
->where ("`type` = 'plugin'")
->where ("`folder` = 'system'")
->where ("`element` = 'myplugin'");
$db->setQuery($query);
$res = json_decode($db->loadResult(), true);
$val = $res['key'];
Just find the answer by myself.
$data = null;
foreach ((array) $this->form as $k => $v) {
if($val instanceof JRegistry){
$data = &$v;
break;
}
}
$data = $data->toArray();
$val = $data['params']['key'];
Thanks! Bye!
codeIgniter form_dropdown() function can receive only associative array but I have multi dimension array by using result_array() function. How can I fetch my data on form_dropdown() function?
Let's say you want a dropdown of items, using result_array():
$query = $this->db->query("SELECT id, item_name FROM items");
$options = array();
foreach ($query->result_array() as $row){
$options[$row['id']] = $row['item_name'];
}
echo form_dropdown('my_items_dropdown', $options, '1');
I have extended the class DB_result.php in system/database with this new function
public function dropdown_array($id_field = FALSE, $list_field = FALSE)
{
$result = array();
if ($id_field === FALSE || $list_field === FALSE) return $result;
$array = $this->result_array();
foreach ($array as $value) {
$result[$value[$id_field]] = $value[$list_field];
}
return $result;
}
Now you can simply call from every Model class your new function to generate a dropdown-compliant array like this:
$customers = $this->db->get('customers');
$result = $customers->dropdown_array('id', 'name');
return $result;
I want to add pagination to my component, i've created a simple model with query. I must be missing something. What else do I need here ?
MODEL
jimport('joomla.application.component.modellist');
class PaieskaModelPradinis extends JModelList
{
public function getListQuery()
{
$db = JFactory::getDBO();
$query = "SELECT * FROM #__content";
$db->setQuery( $query );
$db->query( $query );
$result = $db->LoadObjectList();
return $result;
}
}
VIEW
jimport( 'joomla.application.component.view');
class PaieskaViewPradinis extends JView
{
protected $items;
protected $pagination;
function display ($tpl = null)
{
$this->items = $this->get('ListQuery');
$this->pagination = $this->get('Pagination');
parent::display($tpl);
}
}
TPL
foreach ($this->items as $item) {
echo $item->title;
}
EDITED:
I edited a bit code, so now it works fine, almost. Button display(number of rows to display) is not working. And I wonder if this part can be done in a different way ?
$limit = JRequest::getVar('limit' , 25);
$start = JRequest::getVar('start' , 0);
$query = "SELECT * FROM #__content LIMIT $start, $limit";
-
class PaieskaModelPradinis extends JModelList
{
public function getItems()
{
$db = JFactory::getDBO();
$limit = JRequest::getVar('limit' , 25);
$start = JRequest::getVar('start' , 0);
$query = "SELECT * FROM #__content LIMIT $start, $limit";
$db->setQuery( $query );
$db->query( $query );
$lists = $db->LoadObjectList();
return $lists;
}
function getPagination()
{
$main = JFactory::getApplication();
$db = JFactory::getDBO();
$limit = JRequest::getVar('limit' , 25);
$limitstart = JRequest::getVar('limitstart', 0);
$query = "SELECT count(title) FROM #__content";
$db->setQuery( $query );
$total = $db->loadResult();
// include a pagination library
jimport('joomla.html.pagination');
$pagination = new JPagination($total, $limitstart, $limit);
return $pagination;
}
}
VIEW
jimport( 'joomla.application.component.view');
class PaieskaViewPradinis extends JView
{
function display($tpl = null)
{
$this->items = $this->get('items');
$this->pagination = $this->get('pagination');
parent::display($tpl);
}
}
Going off your original code, not the edited version.
The getListQuery method only builds your database query, so you don't execute your query here. Use com_weblinks as an example for building out your model: https://github.com/joomla/joomla-cms/blob/2.5.x/components/com_weblinks/models/category.php
follow this link http://docs.joomla.org/J1.5:Using_JPagination_in_your_component properly.
I have used Joomla pagination. You'll be able to use Joomla pagination easily, if you follow documentation properly. BTW its very simple.