expect in bash script × 16172 - bash

Question

I try to set a expect script in bash.
#!/bin/bash
/usr/bin/expect <<- EOD
set router 192.168.0.251
set user admin
set pass test
set timeout 1000
set filesave [exec date +%m-%d-%Y]
spawn telnet $router
send "\n"
expect "Username:"
send "$user\n"
expect "Password:"
send "$pass\n"
expect ">"
send "en\n"
expect "Password:"
send "$pass\n"
send "term len 0\n"
log_file $router--$filesave.cfg
send "show running-config\n"
expect "end\r"
send "\n"
log_file
send "exit\n"
EOD
cat /Users/test/Desktop/python/$router--$filesave.cfg | grep end
exit 0
I just got this output
./script2
spawn telnet
telnet> telnet>

Answer 1

Try changing your shebang from:
#!/bin/bash
to
#!/bin/expect
and remove:
/usr/bin/expect <<- EOD
And see if that works.
Update: if you need to have expect run as part of your bash script, either encapsulate the expect code in a separate script with a expect shebang and source it from your bash script, or encode it as in the following example:
expect_sh=$(expect -c "
spawn ssh $login#$IP
expect \"password:\"
send \"$password\r\"
expect \"#\"
send \"cd $dest_dir\r\"
expect \"#\"
send \"chmod +x $server_side_script $other_script\r\"
expect \"#\"
send \"./$device_side_script\r\"
expect \"#\"
send \"cat $deploy_count\r\"
expect \"#\"
send \"exit\r\"
")
echo "$expect_sh"

Answer 2

The problem is that bash is interpreting all the $variables before expect sees the script. Thus you're simply spawning telnet with no hostname given. Change:
/usr/bin/expect <<- EOD
to:
/usr/bin/expect <<- 'EOD'
This has the effect of single-quoting the entire here-document.
http://www.gnu.org/software/bash/manual/bashref.html#Here-Documents
Note also that the next bash command (cat /Users/...) relies on variables defined in Expect -- they are not defined in bash. Try this
#!/bin/bash
export router=192.168.0.251
export filesave=$(date +%m-%d-%Y)
/usr/bin/expect <<- 'EOD'
set router $env(router)
set filesave $env(filesave)
# the rest stays the same