I want to create a simple form in Drupal7 with only one field. When hitting the submit button I need to call an ajax function with the field value and update a DIV on the page without reload.
I'm not familiar with Drupal form API, and I tried to implement the examples form the form api documentation but I always get errors like this:
Notice: Undefined index: #title_display form_pre_render_conditional_form_element() függvényben (/var/www/nmtest/includes/form.inc 2986 sor).
Notice: Undefined index: #value theme_textarea() függvényben /var/www/nmtest/includes/form.inc 3727 sor).
I can do it by creating a custom page and simply use native PHP but this is not an "elegant" way.
I want something similar like the one here, but without form valitation, page reload or so: Create a VERY simple form in Drupal
I only want one button that calls an ajax function. Shoud I do this with forms API or just use plain old native PHP and jQuery?
Edit: Looks like I don't even need a real ajax call, because I only need to change an SRC of an IMG tag.
Here's what I did in native PHP. I want to achive this trough forms api:
<script>
function getstar() {
starpoints = jQuery('#starpoints').val();
rand = Math.floor(Math.random() * 9999) + 1;
src = "test.php?star=" + starpoints + '&rand=' + rand;
jQuery('#starimg').attr("src",src);
return false;
}
</script>
<form>
<input type="text" name="starpoints" id="starpoints" />
<input type="submit" onclick="return getstar();" />
</form>
<img src="/test.php?star=5" id="starimg" />
Edit: Ok, I managed to render a form with the Drupal API. Now the only thing is that I want to insert the placeholder for the IMG via my module, but I don't know how to do it. The form renders fine, but I want to add a HTML block after it. Currently I do it by javascript:
jQuery(document).ready(function() {
jQuery('<div><br /><img id="starimg" src="" /></div>').insertAfter('#drawstar-form');
});
What hook should I catch to render this HTML block after the form? I tried drupal_get_form but that returns an array and I cannot attach the HTML block.
The Form API provides everything that you need to do this without writing a single line of JavaScript code. See http://drupal.org/node/752056 and http://api.drupal.org/api/examples/ajax_example!ajax_example.module/function/ajax_example_simplest/7 and .
Related
I am learning ASP.NET MVC. I have to submit a to controller side after validation in client-side(in jquery). How this can be done? Should i use <form action="#" method="post"> instead of <form action="Controller/Method" method="post"> and add an event handler in click event of submit button of , to send via ajax etc? What should i do? pls help
You are on the right track, and what you suggested will work.
A better method would be to leave the original action intact, providing backwards compatibility to older browsers. You would then create the event handler as normal, and include code to prevent the default submit behavior, and use ajax instead.
$('#submitbutton').live('click', function(e){ e.preventDefault(); });
The easiest way to do this is to use the jQuery forms plugin.
This is my go-to plugin for this type of thing. Basically it will take your existing form, action url etc and convert the submission to an ajax call automatically. From the website:
The jQuery Form Plugin allows you to easily and unobtrusively upgrade
HTML forms to use AJAX. The main methods, ajaxForm and ajaxSubmit,
gather information from the form element to determine how to manage
the submit process. Both of these methods support numerous options
which allows you to have full control over how the data is submitted.
It is extremely useful for sites hosted in low cost web hosting
providers with limited features and functionality. Submitting a form
with AJAX doesn't get any easier than this!
It will also degrade gracefully if, for some reason, javascript is disabled. Take a look at the website, there are a bunch of clear examples and demos.
This is how I do:
In jQuery:
$('document').ready(function() {
$('input[name=submit]').click(function(e) {
url = 'the link';
var dataToBeSent = $("form#myForm").serialize();
$.ajax({
url : url,
data : dataToBeSent,
success : function(response) {
alert('Success');
},
error : function(request, textStatus, errorThrown) {
alert('Something bad happened');
}
});
e.preventDefault();
});
In the other page I get the variables and process them. My form is
<form name = "myForm" method = "post">//AJAX does the calling part so action is not needed.
<input type = "text" name = "fname"/>
<input type= "submit" name = "submit"/>
<FORM>
In the action page have something like this
name = Request.QueryString("fname")
UPDATE: As one of your comment in David's post, you are not sure how to send values of the form. Try the below function you will get a clear idea how this code works. serialize() method does the trick.
$('input[name=submit]').click(function(e){
var dataToBeSent = $("form#myForm").serialize();
alert(dataToBeSent);
e.preventDefault();
})
Is it possible to render json data into a javascript variable while making an ajax call in grails?
I am using the submitToRemote inorder to make an ajax call from my grails view to an action in my grails controller. The action returns a json variable/value. I need to to assign this value to a javascript variable for further usage on my web page. Is this possible to achieve? Any leads will be helpful.
submitToRemote have the onSuccess option that you can use to retrieve the json data. From the docs:
onSuccess (optional) - The JavaScript function to call if successful
An example of how doing it can be seen in this blog post.
You could use the onSuccess callback of submitToRemote to read the result of your request and pass them into a javascript variable.
<script type="text/javascript">
function passResult(result) {
yourVariable = result.responseText
}
</script>
<g:form action="show">
Login: <input name="login" type="text" />
<g:submitToRemote update="updateMe" onSuccess="passResult(result)"/>
</g:form>
<div id="updateMe">this div will be updated with the form submit response</div>
The code above is untested but should work.
In my MVC app, I am returning some Javascript. Howveer, I am using the anti-forgery token on the view, so the rendered result would be
<input name="__RequestVerificationToken" type="hidden" value="E8as+4Ff1u/c/+kuFcNXXCREB5pz5GAfH2krN5RvzURJaHZSApuRc4czZqmoITaKdy0XhN5sFfRzl4ne+wB3PkWOscBWzoIxUk3hGaFwDxRXSbMs8K9IwojEAtV5u57MR7hiSujr6MOTpjjbf5FPaYgO4gmH6lSR9mbSyO2IedI=" />
<script type="text/javascript">
// Here, we ensure that jQuery is loaded then load up the rest of our JS in in order.
ord = Math.random() * 10000000000000000;
...
So there is some HTML to be added to the page then the JS.
The issue is that I get the following notification in Chrome:
Resource interpreted as Script but transferred with MIME type
I need the browser to interpret this as HTML in order to make use of the anti-forgery token.
I have tried putting this on the view:
<%#Page Title="" Language="C#" ContentType="text/xml" %>
Which renders:
<%System.Web.WebPages.DynamicPageDataDictionary`1[System.Object] Title="" Language="C#" ContentType="text/xml" %>
<input name="__RequestVerificationToken" type="hidden"
...
...but the same message persists.
In my controller I have also tried:
System.Text.ASCIIEncoding encoding = new System.Text.ASCIIEncoding();
Byte[] bytes = encoding.GetBytes(page.clientScript);
return new ContentResult
{
ContentType = "text/xml", // also tried text/html
Content = Encoding.UTF8.GetString(bytes),
ContentEncoding = System.Text.Encoding.UTF8
};
Same issue.
-- UPDATE --
This is how I'm invoking the MVC app to return the text:
// used to load scripts on to the client script using a non-blocking asynch request
(function() {
function async_load(){
var s = document.createElement('script');
s.type = 'text/javascript';
s.async = true;
s.src = 'http://myserver/MyAppPath/someids';
var x = document.getElementsByTagName('script')[0];
x.parentNode.insertBefore(s, x);
}
if (window.attachEvent)
window.attachEvent('onload', async_load);
else
window.addEventListener('load', async_load, false);
})();
If I've understood correctly, you need an MVC action which returns both html and a script tag that can be injected in a page via a <script... include. You also want to render this via an MVC view.
The biggest issue you've missed is that in order to get this content into the calling page, you need to execute document.write from the script - you can't just send back HTML and script in response to the script include - the browser won't understand it, it's expecting javascript only.
There are a few ways to do this - I have written a full suite of ViewContent MVC controller methods, with the same overloads as View which returns the result of a view to a controller action as a string. I can then pass that back as a string literal (useful for html email generation) but also to a javascript encoder.
In this case, you don't need to be so generalist. We can leverage Darin Dimitrov's answer to this SO: Embed MVC Partial View into a document.write JS call and split your view into a View and a partial. The view writes the document.write() skeleton, and the partial view renders the dynamic html you want to be injected into the page. It's unclear if you're using the Anti Forgery Token in the main view which will call the script (in which case it should be rendered as part of the view that it returns) or if you're actually hard-coding it in the script. The second should definitely not be used but I'm writing this answer as if it is, because that appears to be what you want.
First, your partial view (let's call it Fragment.cshtml, put it in ~/Views/Shared)
<input name="__RequestVerificationToken"
type="hidden"value="[ommitted]" />
<script type="text/javascript">
// Here, we ensure that jQuery is loaded then load up the rest of our JS in in order.
ord = Math.random() * 10000000000000000;
...
Second, the host view, called SomeIds.cshtml
#{ Response.ContentType = "text/javascript"; }
document.write('#Html.Raw(HttpUtility.JavaScriptStringEncode(Html.Partial("~/Views/Shared/Fragment").ToHtmlString()))')
Now this view returns a document.write call that injects the HTML returned by the Fragment.cshtml into the page that includes the script.
Are you returning a PartialView that has all of the markup rendered?
Create a PartialView with your (form and script includes) and in your Controller:
public ActionResult Index(Models.MyModel model)
{
// validate the model if needed
return PartialView("[My PartialView Name]", model);
}
You could put your scripts in separate files, and add the [script src] tags in the PartialView.
I'm trying to set up a basic web page, and it has a small music player on it (niftyPlayer). The people I'm doing this for want the player in the footer, and to continue playing through a song when the user navigates to a different part of the site.
Is there anyway I can do this without using frames? There are some tutorials around on changing part of a page using ajax and innerHTML, but I'm having trouble wrapping my head aroung getting everything BUT the music player to reload.
Thank you in advance,
--Adam
Wrap the content in a div, and wrap the player in a separate div. Load the content into the content div.
You'd have something like this:
<div id='content'>
</div>
<div id='player'>
</div>
If you're using a framework, this is easy: $('#content').html(newContent).
EDIT:
This syntax works with jQuery and ender.js. I prefer ender, but to each his own. I think MooTools is similar, but it's been a while since I used it.
Code for the ajax:
$.ajax({
'method': 'get',
'url': '/newContentUrl',
'success': function (data) {
// do something with the data here
}
});
You might need to declare what type of data you're expecting. I usually send json and then create the DOM elements in the browser.
EDIT:
You didn't mention your webserver/server-side scripting language, so I can't give any code examples for the server-side stuff. It's pretty simple most of time. You just need to decide on a format (again, I highly recommend JSON, as it's native to JS).
I suppose what you could do is have to div's.. one for your footer with the player in it and one with everything else; lets call it the 'container', both of course within your body. Then upon navigating in the site, just have the click reload the page's content within the container with a ajax call:
$('a').click(function(){
var page = $(this).attr('page');
// Using the href attribute will make the page reload, so just make a custom one named 'page'
$('#container').load(page);
});
HTML
<a page="page.php">Test</a>
The problem you then face though, is that you wouldnt really be reloading a page, so the URL also doesnt get update; but you can also fix this with some javascript, and use hashtags to load specific content in the container.
Use jQuery like this:
<script>
$("#generate").click(function(){
$("#content").load("script.php");
});
</script>
<div id="content">Content</div>
<input type="submit" id="generate" value="Generate!">
<div id="player">...player code...</div>
What you're looking for is called the 'single page interface' pattern. It's pretty common among sites like Facebook, where things like chat are required to be persistent across various pages. To be honest, it's kind of hard to program something like this yourself - so I would recommend standing on top of an existing framework that does some of the leg work for you. I've had success using backbone.js with this pattern:
http://andyet.net/blog/2010/oct/29/building-a-single-page-app-with-backbonejs-undersc/
You can reload desired DIVs via jQuery.ajax() and JSON:
For example:
index.php
<script type="text/javascript" src="jquery-1.4.2.js"></script>
<script type="text/javascript" src="ajax.js"></script>
<a href='one.php' class='ajax'>Page 1</a>
<a href='two.php' class='ajax'>Page 2</a>
<div id='player'>Player Code</div>
<div id='workspace'>workspace</div>
one.php
<?php
$arr = array ( "workspace" => "This is Page 1" );
echo json_encode($arr);
?>
two.php
<?php
$arr = array( 'workspace' => "This is Page 2" );
echo json_encode($arr);
?>
ajax.js
jQuery(document).ready(function(){
jQuery('.ajax').click(function(event) {
event.preventDefault();
// load the href attribute of the link that was clicked
jQuery.getJSON(this.href, function(snippets) {
for(var id in snippets) {
// updated to deal with any type of HTML
jQuery('#' + id).html(snippets[id]);
}
});
});
});
jQuery.validate stops my form from being submitted. I would like it to just show the user what is wrong but allow them to submit anyway.
I am using the jquery.validate.unobtrusive library that comes with ASP MVC.
I use jquery.tmpl to dynamically create the form and then I use jquery.datalink to link the input fields to a json object on the page. So my document ready call looks something like this.
jQuery(function ($) {
// this allows be to rebind validation after the dynamic form has been created
$("form").removeData("validator");
$("form").removeData("unobtrusiveValidation");
$.validator.unobtrusive.parse($("form"));
// submit the answers
$("form").submit(function(e) {
$("input[name=jsonResponse]").val(JSON.stringify(answerArray));
return true;
});
}
I note that there is an option
$("form").validate({ onsubmit: false });
but that seems to kill all validation.
So just to recap when my form is rendered I want to show all errors immediately but I don't want to prevent the submit from working.
So after some research (reading the source code) I found I needed to do 2 things
add the class cancel to my submit button
<input id="submitButton" type="submit" class="cancel" value="OK" />
This stops the validation running on submit.
To validate the form on load I just had to add this to my document ready function
$("form").valid();
Hope this helps someone else