#Transactional in Spring+Hibernate - spring

Question

I an using Spring 3.1 + Hibernate 4.x in my web application.
In my DAO, i am saving User type object as following
sessionFactory.getCurrentSession().save(user);
But getting following exception:
org.hibernate.HibernateException: save is not valid without active transaction
I googled and found similar question on SO, with following solution:
Session session=getSessionFactory().getCurrentSession();
Transaction trans=session.beginTransaction();
session.save(entity);
trans.commit();
That solves the problem. But in that solution, there is lot of mess of beginning and committing the transactions manually.
Can't i use sessionFactory.getCurrentSession().save(user); directly without begin/commit of transactions manually?
I try to use #Transactional on my service/dao methods too, but the problem persists.
EDIT : Here is my Spring Config File:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-3.1.xsd
http://www.springframework.org/schema/aop
http://www.springframework.org/schema/aop/spring-aop-3.1.xsd">
<!-- enable the configuration of transactional behavior based on annotations -->
<tx:annotation-driven transaction-manager="txManager"/>
<bean id="dataSource"
class="org.springframework.jdbc.datasource.DriverManagerDataSource"
p:driverClassName="${db.driverClassName}" p:url="${db.url}"
p:username="${db.username}" p:password="${db.password}" />
<bean id="sessionFactory"
class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="packagesToScan" value="com.myapp.entities" />
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
</bean>
<bean id="txManager"
class="org.springframework.orm.hibernate4.HibernateTransactionManager">
<property name="sessionFactory">
<ref bean="sessionFactory" />
</property>
</bean>
</beans>
I am using following Hibernate 4 dependencies:
<!-- Hibernate Dependency -->
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-core</artifactId>
<version>4.1.7.Final</version>
</dependency>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-entitymanager</artifactId>
<version>4.1.1.Final</version>
</dependency>
<dependency>
<groupId>cglib</groupId>
<artifactId>cglib</artifactId>
<version>${cglib.version}</version>
<scope>runtime</scope>
</dependency>
Please help.

Answer 1

Basically what needs to be done is to remove from the applicationContext.xml file the following line for Hibernate properties:
<prop key="hibernate.current_session_context_class">thread</prop>
Once that is remove, Hibernate makes use of Spring for transaction management
Good luck to you all.

Answer 2

i think you are using Hibernate 4.x then why you are using hibernate 3 transaction manager in application context file?
<bean id="txManager"
class="org.springframework.orm.hibernate3.HibernateTransactionManager">
<property name="sessionFactory">
<ref bean="sessionFactory" />
</property>
</bean>
i think it should be
<bean id="txManager"
class="org.springframework.orm.hibernate4.HibernateTransactionManager">
<property name="sessionFactory">
<ref bean="sessionFactory" />
</property>
</bean>
just try to use hibernate 4 transaction manager along with #Transactional attribute it should work.

Answer 3

Using your working version of the Spring XML, and the #Transactional annotated DAO class, are you defining the DAO in your Spring XML ? (Perhaps as a prototype) Because if you're not, then so far as I can see, your DAO is not going to be AOP'ed for transactional aspects. I think that's the easiest way. This example is from the Spring 3 Doc, section 10.5.6 Using #Transactional.
<!-- this is the service object that we want to make transactional -->
<bean id="fooService" class="x.y.service.DefaultFooService"/>
<!-- enable the configuration of transactional behavior based on annotations -->
<tx:annotation-driven transaction-manager="txManager"/>
...where you might substitute DefaultFooService for your DAO.