command line menu options - bash

I have been trying to get my menu to work, however it seems that it only accepts one argument/option at a time, how can I get it to accept multiple options?
#!/bin/bash
##### Main
function usage
{
echo "
usage: infinidb [[-f file ] [-i] | [-h]] name ...
}
while [ "$1" != "" ]; do
case $1 in
-f | --file ) shift
filename=$1
;;
-i | ) filename2=$2
;;
-h | --help ) usage
exit
;;
* ) usage
exit 1
esac
shift
done
echo $filename
echo $filename2
when running the script
the following output show show
./script.sh -f apple -i tree
apple tree

This works for me
#!/bin/bash
while [ "$1" != "" ]; do
case $1 in
-f | --file ) shift
filename=$1
;;
-i ) filename2=$2
;;
esac
shift
done
echo $filename
echo $filename2
There was only a problem with -i | )

Related

Bash subcommands with arguments

I have a script in bash as such:
#!/usr/bin/env bash
set -e
if [[ "$#" == 0 ]]; then
printhelp
exit 1
fi
# process options
while [[ "$1" != "" ]]; do
case "$1" in
-n | --name)
shift
_NAME="$1"
;;
-i | --id)
shift
_ID="$1"
;;
-h | --help)
printhelp
exit 1
;;
*)
printhelp
exit 1
;;
esac
shift
done
This works fine, but I want to add some "actions" that will take the above params. Eg. usage will be:
./run.sh create --name foo --id 1234
./run.sh delete --id 1234
I am not able to figure out the right syntax, and I am unable to phrase this requirement into appropriate words to be able to search.
For sub-command you can handle it this way:
function main(){
if (( ${#} == 0 )); then
main_help 0;
fi
case ${1} in
help | version | encrypt | decrypt )
$1 "${#:2}";
;;
* )
echo "unknown command: $1";
main_help 1;
exit 1;
;;
esac
}
main "$#";
Then wrap each sub-command is a function. And inside each function you will have isolated options and parsing it separately.
For example:
function decrypt(){
if [[ ${#} == 0 ]]; then
decrypt_help;
fi
local __filename='';
local __salt='';
local __anchor=false;
local error_message='';
while [ ${#} -gt 0 ]; do
error_message="Error: a value is needed for '$1'";
case $1 in
-f | --file )
__filename=${2:?$error_message}
shift 2;
;;
-s | --salt )
__salt=${2:?$error_message}
shift 2;
;;
-a | --anchor )
__anchor=${2:?$error_message}
shift 2;
;;
* )
echo "unknown option $1";
break;
;;
esac
done
echo filename: ${__filename:-empty};
echo salt: ${__salt:-empty};
echo anchor: $__anchor;
exit 0;
}
Here is a full version bash-CLI-template I have used in my projects
demo ;)
Sounds like you want something like:
create() {
# actiony stuff here
}
ACTION=$1 ; shift
# put all your argument parsing here
$ACTION # call
However, since different actions probably have different arguments, I'd probably do it differently...
create() {
# argument parsing for create
# then do your create stuff
}
ACTION=$1 ; shift
$ACTION "$#"
This will pass all your arguments to your subfunction, which can then parse its own arguments.

How to use getopt long option in bash script

I want to write one script something like below with the long option to be provided by user in cmd line argument.
example:
./script.sh --user username --branch branchname --start_time yyy-mm-dd
If possible ignore the order. Not sure if we can apply the logic to ignore the order.
Also, force user to provide the value otherwise throw error message that missing value.
Pasting code block
script_name=$(basename "$0")
short=u:c:e:p:b:t:n:
long=user:,component:,engagement:,product:,branch:,tag:,name:,help
TEMP=$(getopt -o $short --long $long --name "$script_name" -- "$#")
eval set -- "${TEMP}"
while :; do
case "${1}" in
-u | --user ) user="$2"; shift 2 ;;
-c | --component ) comp="$2"; COMP=$(echo $comp | tr [:upper:] [:lower:]) ; shift 2 ;;
-e | --engagement ) eng="$2"; ENG=$(echo $eng | tr [:lower:] [:upper:]) ; shift 2 ;;
-p | --product ) product="$2"; PRODUCT=$(echo $product | tr [:lower:] [:upper:]) ; shift 2 ;;
-b | --branch ) branch="$2"; shift 2 ;;
-t | --tag ) tag="$2"; shift 2 ;;
-n | --name ) name="$2"; shift 2 ;;
--help ) usage; exit 0 ;;
-- ) shift; break ;;
* ) echo "invalid option"; exit 1 ;;
esac
done
script_name=$(basename "$0")
short=u:b:s:
long=user:,branch:,start_time:,help
read -r -d '' usage <<EOF
Manually written help section here
EOF
TEMP=$(getopt -o $short --long $long --name "$script_name" -- "$#")
eval set -- "${TEMP}"
while :; do
case "${1}" in
-u | --user ) user=$2; shift 2 ;;
-b | --branch ) branch=$2; shift 2 ;;
-s | --start_time ) start_time=$2; shift 2 ;;
--help ) echo "${usage}" 1>&2; exit ;;
-- ) shift; break ;;
* ) echo "Error parsing"; exit 1 ;;
esac
done
Set your short and long options. A colon implies it needs an option argument.
Short options are written with no delimiter, long options are comma delimited.
The getopt command makes sure items come in an easily parsable order. In this example, we use a case statement to parse each option. All options are parsed first and then removed from $#.
What's left are the passed arguments that is not part of any defined option.

Bash script - How to make option priority more important than others

I have my problem in my script with priority.
For example when i invoke my script ./script -q -h it should return the h option which should have more important priority than others. My code is below:
#!/bin/bash
function usage
{
echo "Echoing login, name, surname of the invoker
where:
-h help
-q quit(don't proceed script)"
}
function invalid
{
echo "Invalid argument!
"
usage
}
while [ "$1" != "" ]; do
case $1 in
-h | --help ) usage
exit
;;
-q | --quit ) exit
;;
* ) invalid
exit 1
esac
shift
done
echo $USER
getent passwd $USER | cut -d: -f5 | cut -d, -f1
In your case check, just set variables (e.g. opt_h=1 or opt_q=1).
Then check the variables afterwards in whatever order you want:
if [ -n "$opt_h" ]; then
usage
exit
fi
if [ -n "$opt_q" ]; then
exit
fi
The way I'd do it is by setting a variable in the case) block.
i.e.
while [ "$1" != "" ]; do
case $1 in
-h | --help ) DOHELP=true
;;
-q | --quit ) DOQUIT=true
;;
* ) echo "Invalid arg"
exit 1
esac
shift
done
if [ -n "$DOHELP" ]; then
usage
exit 0
fi
if [ -n "$DOQUIT" ]; then
exit 0
fi

Search for file formats + options

I was fiddling around with bash last month and am trying to create a script.
I want the script to search through the folders for files with some kind of extension defined by the argument -e. The folders are defined without -option. The output is 2 columns where in the first it prints the found files, and in the second the respective folders.
Is this the most efficient and/or flexible way to go?
I also can't manage to let the -l command work. Any idea what's wrong? When I enter -name \${CHAR}*, it simply doesn't work. Also, how can I make it recognize a range being used? With an if-function looking for the "-" character or something?
I think I managed to mount a block device, but how can I add the path as a parameter so it can be used as a folder? Setting a number as a var doesn't work, it tells me it doesn't recognize the command.
For some reason the 'no recursion' tag works, but the 'no numbers' doesn't. I have no idea why this would be different.
When using the 'no recursion' (nn) and 'no numbers' (nr) tags I use a long tag --tag for the arguments. Is it possible to use only 1 -tag? This is possible with get opts, but then I can't manage to use the other tags after the get opts has been used. Someone a solution?
Finally, is it possible, when finding 2 files with the same file name, instead of printing the file twice, can it just show the file once. But for every file with the same name keep a white space, so it can still show all the folders in the second column?
#!/bin/bash
#FUNCTIONS
#Error
#Also written to stderr
err() {
echo 1>&2;
echo "Error, not enough arguments" 1>&2;
echo "Usage: $0 [-e <file extension>] [<folder>]";
echo "Please enter the argument -e and at least 1 folder.";
echo "More: Please chek Help by using -h or --help.";
echo 1>&2;
exit
}
#Help
help() {
echo
echo "--- Help ---"
echo
echo "This script will look for file extentions in 1 or more directories. The output shows the found files with the according folder where it's located."
echo
echo "Argument -e <ext> is required."
echo "Other arguments the to-look-trough folders."
echo
echo "These are also usable options:"
echo "-h or --help shows this."
echo "-l <character> looks for files starting with the character."
echo "-l <character1>-<character2> does the same, but looks trough a range of characters."
echo "-b <block-device> mounts a partition to /mnt and let it search through."
echo "--nn (no numbers) makes sure there are no numbers in the file name."
echo "--nr (no recursion) doesn't look trough subdirectories."
echo "-r of –-err <file> writes the errors (f.e. corrupted directory) to <file>."
echo "-s <word> searches the word through the files and only shows the files having that word."
echo
exit
}
#VARS
#execute getopt
OPTS=$(getopt -o e:hl:b:r:s: -l "help,nn,nr,err" -n "FileExtensionScript" -- "$#");
#Bad arguments
if [ $? -ne 0 ];
then
err;
exit
fi
#Rearrange arguments
eval set -- "$OPTS";
#echo "AFTER SET -- \$OPTS: $#";
while true; do
case "$1" in
-e)
shift;
if [ -n "$1" ]; then
EXT=$1;
shift;
fi
;;
-h|--help)
shift;
help;
;;
-l)
shift;
if [ -n "$1" ]; then
CHAR=$1;
shift;
fi
;;
-b)
shift;
if [ -n "$1" ]; then
sudo mkdir /mnt/$1;
sudo echo -e "/dev/$1 /mnt/$1 vfat defaults 0 0 " >> /etc/fstab;
sudo mount -a;
999=/mnt/$1;
shift;
fi
;;
--nn)
shift;
NONUM=" ! -name '*[0-9]*'";
;;
--nr)
shift;
NOREC="-maxdepth 1";
;;
-f|--err)
shift;
if [ -n "$1" ]; then
ERROR="| 2>filename | tee -a $1";
shift;
fi
;;
-s)
shift;
if [ -n "$1" ]; then
SEARCH="-name '*$1*'";
shift;
fi
;;
--)
shift;
break;
;;
esac
done
#No folder or arguments given
if [ $# -lt 1 ];
then
err;
exit
fi
#Debug
echo "Folder argumenten: $#" >2;
echo \# $# >2;
#Create arrays with found files and according folders
FILES=( $(find $# $NOREC $SEARCH $NONUM -name \*.${EXT} $ERROR | rev | cut -d/ -f 1 | rev) )
FOLDERS=( $(find $# $NOREC $SEARCH $NONUM -name \*.${EXT} $ERROR | rev | cut -d/ -f 1 --complement | rev) )
#Show arrays in 2 columns
for ((i = 0; i <= ${#FILES[#]}; i++));
do
printf '%s %s\n' "${FILES[i]}" "${FOLDERS[i]}"
done | column -t | sort -k1 #Make columns cleaner + sort on filename
I am not native English speaker and am hoping to get some tips to finish my script :) Thanks in advance!

parsing parameters in shell script

I have a myscript.sh which starts like this:
#!/usr/bin/env bash
set -e
usage(){
echo "Show Usage ... Blah blah"
exit 1
}
if [ $# = 0 ]; then
usage;
fi
while true; do
case "$1" in
-l | --build-lib ) BUILD_LIB=true;
--other-option ) OTHER_OPTION=$2; shift; shift;;
-h | --help ) usage; shift;;
* ) break ;;
esac
done
# I do my thing here ....
echo "Do my thing"
I am not sure if this is the best way to parse the parameters but so far I have a problem. I am not correctly breaking/failing when the user passes wrong or unknown parameters. How can I address this correctly?
for example I want to avoid calls like:
$ ./myscript.sh unknownParameter
You need to exit when an incorrect option is given, not just break out of the loop. Easiest way is to call your usage function.
while [ $# -gt 0 ]; do
case "$1" in
-l | --build-lib ) BUILD_LIB=tru ;;
--xcode-dev-path ) XCODE_DEV_PATH=${2%/}; shift ;;
-h | --help ) usage;;
* ) usage ;;
esac
shift
done

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