I tried two options (which could find in internet) and no progress:
//in controller
$show_all = TRUE;
$view->assignRef('show', $show_all);
//in default.php and viev.html.php
$this->show;
//result
Notice: Undefined property: componentViewcomponent::$show
//in controller
$show_all = TRUE;
$view->assign('show', $show_all);
//in default.php and viev.html.php
$this->get('show');
//result
NULL
$model = $this->getModel('mymodel'); //get the model
$data_list = $model->getSomeData();//get data from the model
$view = $this->getView('view_name', 'html'); // get the view
$view->assignRef('data_list', $data_list); // set the data to the view
$view->display(); // show the view
This is what I have been using for past 1 year and it always works for me.
Related
I'm following a tutorial on Laravel, adding to a DB via a form. At the end of a function that saves to a DB, it returns back to the page where the form is, but I want to be taken to another page where the information is displayed. In the tutorial I created a controller with a function that returns a view containing all the database info - that element works fine however I can't seem to find a way of calling this function directly after saving to the database. I can also return any other view which just displays static view ( just html with no data handling ). Is what I'm trying to achieve possible?
public function store(){
$li = new \App\LTest1();
$li->creator = request('creator');
$li->title = request('title');
$li->views = request('views');
$li->save();
return back(); // this works
// return view('info'); // this works
//return ('Listings#showList'); this doesnt work = how do i call a function in a controller???
}
// routing
Route::get('info', function () {
return view('info'); // i can get to this static page from my store() function
});
Route::get('thedataviewpage', 'Listings#showList'); // you can route to this but not from the store() function
Redirect is the thing you need here
public function store() {
$li = new \App\LTest1();
$li->creator = request('creator');
$li->title = request('title');
$li->views = request('views');
$li->save();
return redirect('info'); // Redirect to the info route
}
Take this example. Be sure to add the proper route name and a proper message.
return redirect()->route('put here the route name')->with('success', 'Created.');'
to return to a controller action just use
return redirect()->action('Listings#showList');
or you can use route to call that controller action
return redirect('/thedataviewpage');
I wanto to display blog detail from database by clicking on specific blog item.I have created a controller and modal for that but no idea hot o display data by id in detail page.
Controller-
function blogContent(){
$data['info'] = $this->auth_model->blogDetails($id);
$popular['popular'] = $this->auth_model->getPopularcourses();
$this->load->view('nulearnFront/blog_details', $data);
$this->load->view('nulearnFront/header', $data);
$this->load->view('nulearnFront/footer', $popular);
}
Modal-
public function blogDetails($id) {
$q = $this->db->select('*')->from('blog')->where('id',$id)->get();
return $q->result();
}
but i've no idea how to display data by id on frontend. please check the above code also.
You can add a route for the controller in the config/routes.php file like this:
$route['blog/(:any)'] = 'controller/blogContent/$1';
and modified controller
function blogContent($id){
$data['info'] = $this->auth_model->blogDetails($id);
$popular['popular'] = $this->auth_model->getPopularcourses();
$this->load->view('nulearnFront/blog_details', $data);
$this->load->view('nulearnFront/header', $data);
$this->load->view('nulearnFront/footer', $popular);
}
after that, you should only create a correct link to a blog, like this:
My Blog
and you should get blog id in your controller
//Anyone can help to create a view data with same id? it is a multiple viewing.
this is my Controller. i dont khow apply in Model and View
function Get_Pitch($id){
$this->load->model('users_model');
$data['query'] = $id;
$this->load->view('view_pitch', $data);
}
Example this is my url "http://localhost/SMS_System/home/sample/102"
in my database is
id=1 name=erwin user_id=102
id=2 name=flores user_id=102
id=3 name=sample user_id=202
how to view the same user_id?
First of all with what you've supplied your URL won't work, you aren't following the normal conventions for CI so it won't know where to look. I am assuming your controller is called sample then you need to tell the application which function you're calling in that controller, finally URL names should be lower case so I changed that, so your URL should read:
"http://localhost/SMS_System/home/sample/get_pitch/102"
Also you need to get your data from a model, you loaded the model then didn't use it. The line after loading the model calls a function from that model and passes it the id you got from your url. Notice the if not isset on the id, this ensures that if someone goes to that page without the id segment there are no errors thrown from the model having a missing parameter, it will just return nothing, that is handled in the view.
Controller:
function get_pitch($id){
//the following line gets the id based on the segment it's in in the URL
$id=$this->uri_segment(3);
if(!isset($id))
{
$id = 0;
}
$this->load->model('users_model');
$data['query'] = $this->users_model->getUserData($id);
$this->load->view('view_pitch', $data);
}
Your model takes the id passed from the controller and uses that to retrieve the data from the database. I normally create the array I am going to return as an empty array and handle that in the view, this makes sure you get no errors if the query fails. The data then returns to the controller in the last line and is passed to the view in your load view call.
Model:
function getUserData($id)
{
$this->db->where('id',$id);
$result = $this->db->get('users') //assuming the table is named users
$data = array(); //create empty array so we aren't returning nothing if the query fails
if ($result->num_rows()==1) //only return data if we get only one result
{
$data = $result->result_array();
}
return $data;
}
Your view then takes the data it received from the model via the controller and displays it if present, if the data is not present it displays an error stating the user does not exist.
View:
if(isset($query['id']))
{
echo $query['id']; //the variable is the array we created inside the $data variable in the controller.
echo $query['name'];
echo $query['user_id'];
} else {
echo 'That user does not exist';
}
Code sample below,
function product($parameter){
$crud = new grocery_CRUD();
...
$crud->callback_add_field('dropdown_field_name',array($this,'_add_field_callback'));
...
$output = $crud->render();
}
Can I do something like this ?
function _add_field_callback($parameter){
//load db model
//call the result and return as dropdown input field with selected selection when value = $parameter
}
Actually this is easy to do it by using the controller. For example you can simply do:
function product($parameter){
$this->my_test_parameter = $parameter;
$crud = new grocery_CRUD();
...
$crud->callback_add_field('dropdown_field_name',array($this,'_add_field_callback'));
...
$output = $crud->render();
}
And the callback:
function _add_field_callback($parameter){
//load db model
//call the result and return as dropdown input field with selected selection when value = $parameter
$value = !empty($this->my_test_parameter) ? $this->my_test_parameter : '';
...
//here you can also use the form_dropdown of codeigniter (http://ellislab.com/codeigniter/user-guide/helpers/form_helper.html)
}
I know that you are desperately looking forward for the default value for grocery CRUD so I added an issue to the github https://github.com/scoumbourdis/grocery-crud/issues/138 . This is will be a reminder that this thing has to be fixed.
I had implemented Grocery Crud in one of my web application.
Check this link on " How to create dependent dropdowns"
http://demo.edynamics.co.za/grocery_crud/index.php/examples/customers_management/add
I'm not sure if I'm approaching this fundamentally wrong or if I'm just missing something.
I have a controller and within it an index function that is, obviously, the default loaded when that controller is called:
function index($showMessage = false) {
$currentEmployee = $this->getCurrentEmployee();
$data['currentEmp'] = $currentEmployee;
$data['callList'] = $currentEmployee->getDirectReports();
$data['showMessage'] = $showMessage;
$this->load->view('main', $data);
}
I have another function within that controller that does a bulk update. After the updates are complete, I want the original page to show again with the message showing, so I tried this:
/**
* Will save all employee information and return to the call sheet page
*/
function bulkSave() {
//update each employee
for ($x = 0; $x < sizeof($_POST['id']); $x++) {
$success = Employee::updateEmployeeManualData($_POST['id'][$x], $_POST['ext'][$x], $_POST['pager'][$x], $_POST['cell'][$x], $_POST['other'][$x], $_POST['notes'][$x]);
}
$this->index($success);
}
What is happening is that the original page is accessed using:
localhost/myApp/myController
after the bulk update it is showing as:
localhost/myApp/myController/bulkSave
when I really want it to show the url as the index page again, meaning that the user never really sees the /bulkSave portion of the URL. This would also mean that if the user were to refresh the page it would call the index() function in the controller and not the bulkSave() function.
Thanks in advance.
Is this possible?
You are calling your index() funciton directly, within bulkUpdate() hence the uri does not change back to index because you are not making a new server request, you are just navigating within your controller class.
I usually use the same Controller function for tasks like this, directing traffic based on whether or not $_POST data has been passed or not like this...
function index() {
if($_POST) {
//process posted data
for ($x = 0; $x < sizeof($_POST['id']); $x++) {
$data['showMessage'] = Employee::updateEmployeeManualData($_POST['id'][$x], $_POST['ext'][$x], $_POST['pager'][$x], $_POST['cell'][$x], $_POST['other'][$x], $_POST['notes'][$x]);
}
}
else {
//show page normally
$data['showMessage'] = FALSE;
}
//continue to load page
$currentEmployee = $this->getCurrentEmployee();
$data['currentEmp'] = $currentEmployee;
$data['callList'] = $currentEmployee->getDirectReports();
$this->load->view('main', $data);
}
Then if it is a form that you are submitting, just point the form at itself in your view like this...
<?= form_open($this->uri->uri_string()) ?>
This points the form back at index, and because you are posting form data via $_POST it will process the data.
I usually do a redirect to the previous page as it prevent users to refresh (and submit twice) their data.
You can use the redirect() helper function of CI.
http://codeigniter.com/user_guide/helpers/url_helper.html (at the bottom)