MakeCodeWritable - xcode

good afternoon.
I got the code below on a book. I'm trying to execute it, but I don't know what is the "first" and "last" parameters on the MakeCodeWritable function, or where I can find them. Someone can help? This code is about C obfuscation method. I'm using Xcode program and LLVM GCC 4.2 compiler.
#include <stdio.h>
#include <sys/mman.h>
#include <stdlib.h>
#include <unistd.h>
#include <sys/types.h>
typedef unsigned int uint32;
typedef char* caddr_t;
typedef uint32* waddr_t;
#define Tam_celula 64
#define ALIGN __attribute__((aligned(Tam_celula)))
void makeCodeWritable(char* first, char* last) {
char* firstpage = first - ((int)first % getpagesize());
char* lastpage = last - ((int)last % getpagesize());
int pages = (lastpage-firstpage)/getpagesize()+1;
if (mprotect(firstpage,pages*getpagesize(), PROT_READ|PROT_EXEC|PROT_WRITE)==-1) perror("mprotect");
}
void xor(caddr_t from, caddr_t to, int len){
int i;
for(i=0;i<len;i++){
*to ^= *from; from++; to++;
} }
void swap(caddr_t from, caddr_t to, int len){
int i;
for(i=0;i<len;i++){
char t = *from; *from = *to; *to = t; from++; to++;
} }
#define CELLSIZE 64
#define ALIGN asm volatile (".align 64\n");
void P() {
static int firsttime=1; if (firsttime) {
xor(&&cell5,&&cell2,CELLSIZE);
xor(&&cell0,&&cell3,CELLSIZE);
swap(&&cell1,&&cell4,CELLSIZE);
firsttime = 0; }
char* a[] = {&&align0,&&align1,&&align2,&&align3,&&align4,&&align5};
char*next[] ={&&cell0,&&cell1,&&cell2,&&cell3, &&cell4,&&cell5};
goto *next[0];
align0: ALIGN
cell0: printf("SPGM0\n");
xor(&&cell0,&&cell3,3*CELLSIZE);
goto *next[3];
align1: ALIGN
cell1: printf("SPGM2\n"); xor(&&cell0,&&cell3,3*CELLSIZE);
goto *next[4];
align2: ALIGN
cell2: printf("SPGM4\n"); xor(&&cell0,&&cell3,3*CELLSIZE);
goto *next[5];
align3: ALIGN
cell3: printf("SPGM1\n"); xor(&&cell3,&&cell0,3*CELLSIZE);
goto *next[1];
align4: ALIGN
cell4: printf("SPGM3\n"); xor(&&cell3,&&cell0,3*CELLSIZE);
goto *next[2];
align5: ALIGN
cell5: printf("SPGM5\n");
xor(&&cell3,&&cell0,3*CELLSIZE);
}
int main (int argc, char *argv[]) {
makeCodeWritable(...);
P(); P();
}

The first argument should be (char *)P, because it looks like you want to modify code inside function P. The second argument is the ending address of function P. You can first compile the code, and using objdump -d to see the address of beginning and end of P, then calculate the size of the function, SIZE, then manually specify in the makeCodeWritable( (char *)P, ((char *)P) + SIZE.
The second way is utilizing the as to get the size of function P, but it depends on the assembler language on your platform. This is code snipe I modified from your code, it should be able to compile and run in x86, x86_64 in GCC 4.x on Linux platform.
align5: ALIGN
cell5: printf("SPGM5\n");
xor(&&cell3,&&cell0,3*CELLSIZE);
// adding an label to the end of function P to assembly code
asm ("END_P: \n");
;
}
extern char __sizeof__myfunc[];
int main (int argc, char *argv[]) {
// calculate the code size, ending - starting address of P
asm (" __sizeof__myfunc = END_P-P \n");
// you can see the code size of P
printf("code size is %d\n", (unsigned)__sizeof__myfunc);
makeCodeWritable( (char*)P, ((char *)P) + (unsigned)__sizeof__myfunc);
P(); P();
}
With some modification to support LLVM GCC and as in Mac OS X
int main (int argc, char *argv[]) {
size_t sizeof__myfunc = 0;
asm volatile ("movq $(_END_P - _P),%0;"
: "=r" (sizeof__myfunc)
: );
printf("%d\n", sizeof__myfunc);

Related

__seg_fs on GCC. Is it possible to emulate it just in a program?

I've just read about support for %fs and %gs segment prefixes on the Intel platforms in GCC.
It was mentioned that "The way you obtain %gs-based pointers, or control the
value of %gs itself, is out of the scope of gcc;"
I'm looking for a way when I manually can set the value of %fs (I'm on IA32, RH Linux) and work with it. When I just set %fs=%ds the test below works fine and this is expected. But I cannot change the test in order to have another value of %fs and do not get a segmentation fault. I start thinking that changing the value of %fs is not the only thing to do. So I'm looking for an advice how to make a part of memory addressed by %fs that is not equal to DS.
#include <stddef.h>
typedef char __seg_fs fs_ptr;
fs_ptr p[] = {'h','e','l','l','o','\0'};
void fs_puts(fs_ptr *s)
{
char buf[100];
buf[0] = s[0];
buf[1] = s[1];
buf[2] = s[2];
buf[3] = '\0';
puts(buf);
}
void __attribute__((constructor)) set_fs()
{
__asm__("mov %ds, %bx\n\t"
"add $0, %bx\n\t" //<---- if fs=ds then the program executes as expected. If not $0 here, then segmentation fault happens.
"mov %bx, %fs\n\t");
}
int main()
{
fs_puts(p);
return 0;
}
I've talked with Armin who implemented __seg_gs/__seg_fs in GCC (Thanks Armin!).
So basically I cannot use these keywords for globals. The aim of introducing __seg_gs/fs was to have a possibility to dynamically allocate regions of memory that are thread-local.
We cannot use __thread for a pointer and to allocate a memory for it using malloc. But __seg_gs/fs introduce such possibility.
The test below somehow illustrates that.
Note that arch_prctl() was used. It exists as 64-bit version only.
Also note that %fs is used for __thread on 64-bit and %gs is free.
#include <stddef.h>
#include <string.h>
#include <stdio.h>
#include <asm/ldt.h>
#include <stdlib.h>
#include <sys/mman.h>
#include <sys/prctl.h>
#include <asm/prctl.h>
#include <sys/syscall.h>
#include <unistd.h>
typedef __seg_gs char gs_str;
void gs_puts(gs_str *ptr)
{
int i;
char buf[100];
for(i = 0; i < 100; i++)
buf[i] = ptr[i];
puts(buf);
}
int main()
{
int i;
void *buffer = malloc(100 * sizeof(char));
arch_prctl(ARCH_SET_GS, buffer);
gs_str *gsobj = (gs_str *)0;
for (i = 0; i < 100; i++)
gsobj[i] = 'a'; /* in the %gs space */
gs_puts(gsobj);
return 0;
}

Why does the left shift on a unsigned int happens from the 16th bit?

I am trying to put the values from the vector into the int.
Given vector :'1','0','1','1','1','0','1','1','1','0','1','1','1','0','1','1' :
Expected output (binary representation for the variable out):
00000000000000001011101110111011.
However, I am getting the following output:
10111011101110110000000000000000
Notice: the insertion begun at the 16bit from right end instead of beginning from the leftmost bit
#include<vector>
#include<iostream>
int main() {
std::vector<unsigned char> test = {'1','0','1','1','1','0','1','1','1','0','1','1','1','0','1','1'};
std::vector<unsigned int> out(1);
int j = 0;
for (int i =0; i < test.size(); i++) {
out[j] = out[j] << 1;
if (test[i] == '1') {out[j] |=0x1;}
}
j++;
for (int p = 0; p < j; p++) {
for (int k = 0; k<32; k++ ) {
std::cout << !!((out[p]<<k)&0x8000);
}
std::cout << std::endl;
}
std::cout << "Size Of:" << sizeof(int);
return 0;
}
The reason why this happens is that you are using a wrong constant for the mask: 0x8000 has its 16-bit set, while you probably meant to use 0x80000000 with the 32-nd bit set. To avoid mistakes like that it's best to construct masks with shifts, for example
(1 << 31)
This expression is evaluated at compile time, so the result is the same as if you computed the constant yourself.
Note that both 0x8000 and 0x80000000 constants are system-dependent. Moreover, 0x80000000 assumes 32-bit int, which is not guaranteed.
A better approach would be shifting the number right instead of left, and masking with 1.
The block of code creating out[j] works just fine.
Your problem is in the output block, due to use of 0x8000. Whenever k >= 16, the low 16 bits will be zero, guaranteeing that 0x8000 is zero.
Your code seems overly complicated to me. Here's my version of a C program that transforms a string of 1's and 0's into an int and one going from int to string.
#include <stdlib.h>
#include <stdio.h>
int main(int argc, char **argv);
int main (int argc, char **argv) {
char str [] = "1010101010101010";
int x;
int out;
for (x=0;x<16;x++) {
if (str[x] == '1') {
out |= (1 << x);
}
}
printf("%d", out) ;
}
and
#include <stdlib.h>
#include <stdio.h>
int main(int argc, char **argv);
int main (int argc, char **argv) {
char str [] = "1010101010101010";
int in = 21845;
char out[17] = {0};
for (x=0;x<16;x++) {
if (in & (1<<x)) {
out[x] = '1';
}
else {
out[x] = '0';
}
}
printf("%s", out) ;
}

How to use copy_to_user

I'm trying to add a custom system call into the linux kernel. Here is a simple code:
#include <linux/mysyscall.h>
#include <linux/kernel.h>
#include <asm/uaccess.h>
#include <asm/system.h>
asmlinkage int sys_mysyscall(int *data){
int a = 3;
cli();
copy_to_user(data, &a, 1);
sti();
printk(KERN_EMERG "Called with %d\n", a);
return a;
}
I can compile a kernel with mysyscall added and when I try to access it with a user program like:
#include <linux/mysyscall.h>
int main(void){
int *data;
int r;
int a = 0;
data = &a;
r = mysyscall(data);
printf("r is %d and data is %d", r, *data);
}
*data does not equal to 3 it equals to 0.
How should I use copy_to_user to fix it?
The copy to user line of code copies only one byte from 'a'. In case of little endian systems it is going to be 0. Copy all the 4 bytes to get the correct result.

fftw3 proper using

#include <stdio.h>
#include <Windows.h>
#include <string.h>
#include <stdlib.h>
#include "fftw3.h"
int main(void)
{
FILE *fp;
int rozmiar_pliku;
char standard[5] = {0};
char format[5] = {0};
int samplerate;
int k,i;
fftw_complex in[128];
fftw_complex out[128];
fftw_plan p;
fp = fopen("Kalimba.wav","rb" );
//printf("%d\n",fp);
if (fp)
{
fread(standard,1,4,fp);
printf("%s\n",standard);
printf("RIFF\n");
if (!strcmp(standard,"RIFF" ))
{
fread(&rozmiar_pliku,4,1,fp);
printf("size: %d\n", rozmiar_pliku);
}
fread(format,1,4,fp);
printf("format: %s\n",format);
fseek(fp,24,SEEK_SET);
fread(&samplerate,1,4,fp);
printf("sample rate: %d\n",samplerate);
fseek(fp,44,SEEK_SET);
for(i=0;i<128;++i)
{
in[i][0]=getc(fp);
in[i][1]=in[i][0];
}
/*
p = fftw_plan_dft_1d(128, in, out, FFTW_FORWARD, FFTW_ESTIMATE);
fftw_execute(p);
for(int j=0;j<128;++j)
printf("%lf+i*%lf",out[j][0],out[j][1]);
fftw_destroy_plan(p);
fftw_free(in);
fftw_free(out);
*/
}
return 0;
}
I'm trying to read wave file and perform FFT by using FFTW3. If i uncomment part which is commented there's nothing show on screen. If I leave it commented :
RIFF
RIFF
size: 61392422
format: WAVE
sample rate: 44100
If uncommented nothing appears. I don't know why it is going like this. Any use of fftw3 cause this situation.
in and out are statically declared arrays. Try passing &in[0] and &out[0] to match the type expected by fftw_plan_dft_1d.
As it is recommended in the documentation, you should declare in and out using fftw_malloc.
You can allocate them in any way that you like, but we recommend using fftw_malloc.
Then, you'll need to initialize in after creating the plan.
You must create the plan before initializing the input, because FFTW_MEASURE overwrites the in/out arrays. (Technically, FFTW_ESTIMATE does not touch your arrays, but you should always create plans first just to be sure.)
The result with some other modifications, is
#include <stdio.h>
#include <stdlib.h>
#include "fftw3.h"
int main(void)
{
FILE *fp;
int rozmiar_pliku;
char standard[5] = {0};
char format[5] = {0};
int samplerate;
int i;
fftw_complex *in, *out;
fftw_plan p;
fp = fopen("audioFile1.wav","rb" );
if (fp)
{
fread(standard,1,4,fp);
printf("%s\n",standard);
printf("RIFF\n");
if (!strcmp(standard,"RIFF" ))
{
fread(&rozmiar_pliku,4,1,fp);
printf("size: %d\n", rozmiar_pliku);
}
fread(format,1,4,fp);
printf("format: %s\n",format);
fseek(fp,24,SEEK_SET);
fread(&samplerate,1,4,fp);
printf("sample rate: %d\n",samplerate);
fseek(fp,44,SEEK_SET);
// Allocate in and out buffers using fftw_alloc
in = (fftw_complex*) fftw_malloc(sizeof(fftw_complex) * 128);
out = (fftw_complex*) fftw_malloc(sizeof(fftw_complex) * 128);
// Create plan before initializing in
p = fftw_plan_dft_1d(128, in, out, FFTW_FORWARD, FFTW_ESTIMATE);
// Initialize in after creating plan
for(i=0;i<128;++i)
{
in[i][0]=getc(fp);
in[i][1]=in[i][0];
}
fftw_execute(p);
for(int j=0;j<128;++j)
printf("%lf+i*%lf\n",out[j][0],out[j][1]);
fftw_destroy_plan(p);
fftw_free(in); fftw_free(out);
}
return 0;
}

Page faults on OS X when reading with MMAP

I am trying to benchmark file system I/O on Mac OS X using mmap.
#include <unistd.h>
#include <fcntl.h>
#include <dirent.h>
#include <sys/stat.h>
#include <sys/types.h>
#include <sys/mman.h>
#include <stdio.h>
#include <math.h>
char c;
int main(int argc, char ** argv)
{
if (argc != 2)
{
printf("no files\n");
exit(1);
}
int fd = open(argv[1], O_RDONLY);
fcntl(fd, F_NOCACHE, 1);
int offset=0;
int size=0x100000;
int pagesize = getpagesize();
struct stat stats;
fstat(fd, &stats);
int filesize = stats.st_size;
printf("%d byte pages\n", pagesize);
printf("file %s # %d bytes\n", argv[1], filesize);
while(offset < filesize)
{
if(offset + size > filesize)
{
int pages = ceil((filesize-offset)/(double)pagesize);
size = pages*pagesize;
}
printf("mapping offset %x with size %x\n", offset, size);
void * mem = mmap(0, size, PROT_READ, 0, fd, offset);
if(mem == -1)
return 0;
offset+=size;
int i=0;
for(; i<size; i+=pagesize)
{
c = *((char *)mem+i);
}
munmap(mem, size);
}
return 0;
}
The idea is that I'll map a file or portion of it and then cause a page fault by dereferencing it. I am slowly losing my sanity since this doesn't at all work and I've done similar things on Linux before.
Change this line
void * mem = mmap(0, size, PROT_READ, 0, fd, offset);
to
void * mem = mmap(0, size, PROT_READ, MAP_PRIVATE, fd, offset);
And, don't compare mem with -1. Use this instead:
if(mem == MAP_FAILED) { ... }
It's both more readable and more portable.
General advice: if you're on a different UNIX platform from what you're used to, it's a good idea to open the man page. For mmap on OS X, it can be found here. It says
Conforming applications must specify either MAP_PRIVATE or MAP_SHARED.
So, specifying 0 on the fourth
argument is not OK in OS X. I believe
this is true for BSD in general.

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