In my file I have following structure :-
A | 12 | 10
B | 90 | 112
C | 54 | 34
What I have to do is I have to add column 2 and column 3 and print the result with column 1.
output:-
A | 22
B | 202
C | 88
I retrieve the two columns but dont know how to add
What I did is :-
cut -d ' | ' -f3,5 myfile.txt
How to add those columns and display.
A Bash solution:
#!/bin/bash
while IFS="|" read f1 f2 f3
do
echo $f1 "|" $((f2+f3))
done < file
You can do this easily with awk.
awk '{print $1," | ",($3+$5)'} myfile.txt
wil work perhaps.
You can do this with awk:
awk 'BEGIN{FS="|"; OFS="| "} {print $1 OFS $2+$3}' input_filename
Input:
A | 12 | 10
B | 90 | 112
C | 54 | 34
Output:
A | 22
B | 202
C | 88
Explanation:
awk: invoke the awk tool
BEGIN{...}: do things before starting to read lines from the file
FS="|": FS stands for Field Separator. Think of it as the delimiter that separates each line of your file into fields
OFS="| ": OFS stands for Output Field Separator. Same idea as above, but for output. FS =/= OFS in this case due to formatting
{print $1 OFS $2+$3}: For each line that awk reads, print the first field (the letter), followed by a delimiter specified by OFS, then the sum of field 2 and field 3.
input_filename: awk accepts the input file name as an argument here.
Related
We have to find the difference(d) Between last 2 nos and display rows with the highest value of d in ascending order
INPUT
1 | Latha | Third | Vikas | 90 | 91
2 | Neethu | Second | Meridian | 92 | 94
3 | Sethu | First | DAV | 86 | 98
4 | Theekshana | Second | DAV | 97 | 100
5 | Teju | First | Sangamithra | 89 | 100
6 | Theekshitha | Second | Sangamithra | 99 |100
Required OUTPUT
4$Theekshana$Second$DAV$97$100$3
5$Teju$First$Sangamithra$89$100$11
3$Sethu$First$DAV$86$98$12
awk 'BEGIN{FS="|";OFS="$";}{
avg=sqrt(($5-$6)^2)
print $1,$2,$3,$4,$5,$6,avg
}'|sort -nk7 -t "$"| tail -3
Output:
4 $ Theekshana $ Second $ DAV $ 97 $ 100$3
5 $ Teju $ First $ Sangamithra $ 89 $ 100$11
3 $ Sethu $ First $ DAV $ 86 $ 98$12
As you can see there is space before and after $ sign but for the last column (avg) there is no space, please explain why its happening
2)
awk 'BEGIN{FS=" | ";OFS="$";}{
avg=sqrt(($5-$6)^2)
print $1,$2,$3,$4,$5,$6,avg
}'|sort -nk7 -t "$"| tail -3
OUTPUT
4$|$Theekshana$|$Second$|$0
5$|$Teju$|$First$|$0
6$|$Theekshitha$|$Second$|$0
I have not mentiond | as the output field separator but still it appears, why is this happening and the difference is zero too
I am just 6 days old in unix,please answer even if its easy
your field separator is only the pipe symbol, so surrounding whitespace is part of the field definitions and that's what you see in the output. In combined uses pipe has the regex special meaning and need to be escaped. In your second case it means space or space is the field separator.
$ awk 'BEGIN {FS=" *\\| *"; OFS="$"}
{d=sqrt(($NF-$(NF-1))^2); $1=$1;
print d "\t" $0,d}' file | sort -n | tail -3 | cut -f2-
4$Theekshana$Second$DAV$97$100$3
5$Teju$First$Sangamithra$89$100$11
3$Sethu$First$DAV$86$98$12
a slight rewrite will eliminate the number of fields dependency and fixes the format.
I am new to Unix Programming. Could you please help me to solve the question.
For example, If the input file has the below content
RollNo Name Score
234 ABC 70
567 QWE 12
457 RTE 56
234 XYZ 80
456 ERT 45
The output will be
ABC
I tried something like this
sort -k3,3 -rn -t" " | head -n2 | awk '{print $2}'
Using awk
awk 'NR>1{arr[$3]=$2} END {n=asorti(arr,arr_sorted); print arr[arr_sorted[n-1]]}'
Demo:
$cat file.txt
RollNo Name Score
234 ABC 70
567 QWE 12
457 RTE 56
234 XYZ 80
456 ERT 45
$awk 'NR>1{arr[$3]=$2} END {n=asorti(arr,arr_sorted); print arr[arr_sorted[n-1]]}' file.txt
ABC
$
Explanation:
NR>1 --> Skip first record
{arr[$3]=$2} --> Create associtive array with marks as index and name as value
END <-- read till end of file
n=asorti(arr,arr_sorted) <-- Sort array arr on index value(i.e marks) and save in arr_sorted. n= number of element in array
print arr[arr_sorted[n-1]]} <-- n-1 will point to second last value in arr_sorted (i.e marks) and print corresponding value from arr
Your attempt is 90% correct just a single change
Try this...it will work.
sort -k3,3 -rn -t" " | head -n1 | awk '{print $2}'
Instead of using head -n2 replace it with head -n1
I'd like to concatenate column2 until column4.
Example (first.txt):
|ID|column2|column3|column4|
|1 | a | b | c |
|2 | d | e | f |
To this (mynewfile.txt) :
ID|column2
1 | a b c
2 | d e f
This is my script in cygwin : $ awk '{print $2" "$3" "$4 }' first.txt > mynewfile.txt
Of course, it is not working out well.. How do I improve the script?
You need to set the field separator so that a pipe with optional whitespace around it is the field delimiter.
The pipe at the beginning of the line causes an empty field 1 before the pipe, so the ID is field 2, and columns 2-4 are fields 3-5. So it should be:
awk -F' *\\| *' 'NR == 1 {print "ID|column2|"} NR > 1 {printf("%d | %s %s %s |\n", $2, $3, $4, $5)}' first.txt > mynewfile.txt
Not especially general GNU sed method:
sed 's/^[|]//;1s/2.*/2/;1!{s/|/ /g2;s/ */ /2g}' first.txt
Output:
ID|column2
1 | a b c
2 | d e f
I have a .txt file with strings in arrays which looks like these:
id | String1 | String2 | Counts
1 | Abc | Abb | 0
2 | Cde | Cdf | 0
And i want to add counts, so i need to replace last digit, but i need to change it only for the one line.
I am getting new needed value by this function:
$(awk -F "|" -v i=$idOpen 'FNR == i { gsub (" ", "", $0); print $4}' filename)"
And them I want to replace it with new value, which will be bigger for 1.
And im doing it right in there.
counts=(("$(awk -F "|" -v i=$idOpen 'FNR == i { gsub (" ", "", $0); print $4}' filename)"+1))
Where IdOpen is an id of the array, where i need to replace string.
So i have tried to replace the whole array by these:
counter="$(awk -v i=$idOpen 'BEGIN{FNqR == i}{$7+=1} END{ print $0}' bookmarks)"
N=$idOpen
sed -i "{N}s/.*/${counter}" bookmarks
But it doesn't work!
So is there a way to replace only last string with value which i have got earlier?
As result i need to get:
id | String1 | String2 | Counts
1 | Abc | Abb | 1 # if idOpen was 1 for 1 time
2 | Cde | Cdf | 2 # if idOpen was 2 for 2 times
And the last number will be increased by 1 everytime when i will activate these commands.
awk solution:
setting idOpen variable(for ex. 2):
idOpen=2
awk -F'|' -v i=$idOpen 'NR>1{if($1 == i) $4=" "$4+1}1' OFS='|' file > tmp && mv tmp file
The output(after executing the above command twice):
cat file
id | String1 | String2 | Counts
1 | Abc | Abb | 0
2 | Cde | Cdf | 2
NR>1 - skipping the header line
I need to implement the if condition in the below nawk command to process input file if the third column has more that three digit.Pls help with the command what i am doing wrong as it is not working.
inputfile.txt
123 | abc | 321456 | tre
213 | fbc | 342 | poi
outputfile.txt
123 | abc | 321### | tre
213 | fbc | 342 | poi
cat inputfile.txt | nawk 'BEGIN {FS="|"; OFS="|"} {if($3 > 3) $3=substr($3, 1, 3)"###" print}'
Try:
awk 'length($3) > 3 { $3=substr($3, 1, 3)"###" } 1 ' FS=\| OFS=\| test1.txt
This works with gawk:
awk -F '[[:blank:]]*\\\|[[:blank:]]*' -v OFS=' | ' '
$3 ~ /^[[:digit:]]{4,}/ {$3 = substr($3,1,3) "###"}
1
' inputfile.txt
It won't preserve the whitespace so you might want to pipe through column -t