I would like to insert lines into a file in bash starting from a specific line.
Each line is a string which is an element of an array
line[0]="foo"
line[1]="bar"
...
and the specific line is 'fields'
file="$(cat $myfile)"
for p in $file; do
if [ "$p" = 'fields' ]
then insertlines() #<- here
fi
done
This can be done with sed: sed 's/fields/fields\nNew Inserted Line/'
$ cat file.txt
line 1
line 2
fields
line 3
another line
fields
dkhs
$ sed 's/fields/fields\nNew Inserted Line/' file.txt
line 1
line 2
fields
New Inserted Line
line 3
another line
fields
New Inserted Line
dkhs
Use -i to save in-place instead of printing to stdout
sed -i 's/fields/fields\nNew Inserted Line/'
As a bash script:
#!/bin/bash
match='fields'
insert='New Inserted Line'
file='file.txt'
sed -i "s/$match/$match\n$insert/" $file
Or anoter one example with the sed:
Prepare a test.txt file:
echo -e "line 1\nline 2\nline 3\nline 4" > /tmp/test.txt
cat /tmp/test.txt
line 1
line 2
line 3
line 4
Add a new line into the test.txt file:
sed -i '2 a line 2.5' /tmp/test.txt
# sed for in-place editing (-i) of the file: 'LINE_NUMBER a-ppend TEXT_TO_ADD'
cat /tmp/test.txt
line 1
line 2
line 2.5
line 3
line 4
This is definitely a case where you want to use something like sed (or awk or perl) rather than readling one line at a time in a shell loop. This is not the sort of thing the shell does well or efficiently.
You might find it handy to write a reusable function. Here's a simple one, though it won't work on fully-arbitrary text (slashes or regular expression metacharacters will confuse things):
function insertAfter # file line newText
{
local file="$1" line="$2" newText="$3"
sed -i -e "/^$line$/a"$'\\\n'"$newText"$'\n' "$file"
}
Example:
$ cat foo.txt
Now is the time for all good men to come to the aid of their party.
The quick brown fox jumps over a lazy dog.
$ insertAfter foo.txt \
"Now is the time for all good men to come to the aid of their party." \
"The previous line is missing 'bjkquvxz.'"
$ cat foo.txt
Now is the time for all good men to come to the aid of their party.
The previous line is missing 'bjkquvxz.'
The quick brown fox jumps over a lazy dog.
$
sed is your friend:
:~$ cat text.txt
foo
bar
baz
~$
~$ sed '/^bar/\na this is the new line/' text.txt > new_text.txt
~$ cat new_text.txt
foo
bar
this is the new line
baz
~$
Related
I have an TARGET.md file, I'm looking for a string and I want to replace it with the content of other md file, I have tried many combinations but it seems like the newline in the files are the ones sed is not liking, I just need to do this using pure bash(it doesn't have to be sed) because this is how the whole script is running:
This works:
local search="##### Header"
local replace="##### Header\\
\\
Line 1\\
Line 2\\
Line 3\\
Line 4"
sed -i '' -e "s/${search}/${replace}/" TARGET.md
But this won't:
file1.md content:
##### Header
Line 1
Line 2
Line 3
Line 4
Script:
local search="##### Header"
local replace=$(curl "path/to/file/in/other/place/file1.md")
sed -i '' -e "s/${search}/${replace}/" TARGET.md
NOTE: I don't have the file1.md in the same place, I'm doing a curl to get the raw content from it, this is why the replace is in a variable.
I'm assuming the concept is possible but my sed syntax is wrong knowing sed can handle newlines out of the box, but not sure what is the proper way to do this.
I've been searching for some days now, any help, tip or guide is appreciated!
You are using the wrong tool. sed is a line editor at heart. While you can repeatedly append to pattern space in some instances, awk with getline provides a more flexible solution. For example with your file1.md:
##### Header
Line 1
Line 2
Line 3
Line 4
and your TARGET.md as:
##### Unreleased
my dog
has fleas
The to replace "##### Unreleased" with the content of file1.md, you can do:
awk -v replace="file1.md" -v search="##### Unreleased" '
$0 == search {while (getline line < replace ) { print line }; next }
{ print }
' TARGET.md
Above you have your replace and search as with sed, but instead of using the line-editor, you use awk to locate the line containing search and the read all lines from replace using getline`. The second rule just prints all other lines as is.
Example Use/Output
In the directory containing each file, you can simply select-copy the above and middle-mouse paste into the terminal to test:
$ awk -v replace="file1.md" -v search="##### Unreleased" '
> $0 == search {while (getline line < replace ) { print line }; next }
> { print }
> ' TARGET.md
##### Header
Line 1
Line 2
Line 3
Line 4
my dog
has fleas
Look things over and let me know if you have further questions.
Taking TARGET.md file from David's answer:
cat TARGET.md
##### Unreleased
my dog
has fleas
You can run sed with r command like this:
search="##### Unreleased"
sed -e "/$search/{r file1.md" -e ';d;}' TARGET.md
##### Header
Line 1
Line 2
Line 3
Line 4
my dog
has fleas
I am trying to remove the last space of a file.txt which contains many rows.
I just need to remove "only the last space" after the third column/each line.
My file looks like this:
3 180 120
3 123 145
6 234 0
4 122 12
I have been trying with the following script but it does not work, so far. Somebody can help me, please?
#!/bin/bash
var="val1 val2 val3 "
var="${var%"${var##*[![:space:]]}"}"
echo "===$var===" <Antart_csv1_copy.txt> trimmed.txt
You can use sed:
sed -i -e 's/ $//g' filename.txt
-i will make the command inplace (change the original file)
-e 's/ $//g' will take regular expression <space><endline> and change it to nothing. Modifier g makes it for all lines in the file
You can try it first without -i and redirect output:
sed -e 's/ $//g' filename.txt > trimmed.txt
Another solution removing all trailing spaces from each line :
while read line; do echo "${line%%*( )}" >> trimmed.txt; done < Antart_csv1_copy.txt
I have two files and would like to insert the contents of one file into the other, replacing a specified line.
File 1:
abc
def
ghi
jkl
File 2:
123
The following code is what I have.
file1=numbers.txt
file2=letters.txt
linenumber=3s
echo $file1
echo $file2
sed "$linenumber/.*/r $file1/" $file2
Which results in the output:
abc
def
r numbers.txt
jkl
The output I am hoping for is:
abc
def
123
jkl
I thought it could be an issue with bash variables but I still get the same output when I manually enter the information.
How am I misunderstanding sed and/or the read command?
Your script replaces the line with the string "r $file1". The part in sed in s command is not re-interpreted as a command, but taken literally.
You can:
linenumber=3
sed "$linenumber"' {
r '"$file1"'
d
}' "$file2"
Read line number 3, print file1 and then delete the line.
See here for a good explanation and reference.
Surely we can make that a oneliner:
sed -e "$linenumber"' { r '"$file2"$'\n''d; }' "$file1"
Life example at tutorialpoints.
I would use the c command as follows:
linenumber=3
sed "${linenumber}c $(< $file1)" "$file2"
This replaces the current line with the text that comes after c.
Your command didn't work because it expands to this:
sed "3s/.*/r numbers.txt/" letters.txt
and you can't use r like that. r has to be the command that is being run.
I have two separate text files, one with 4 letter words and one with 4 digit numbers, all on individual lines. The words in the on file correspond to the numbers on the same line in the other file. For example:
CATS
RATS
HATS
matches up with
2287
7287
4287
What I would like is to append the numbers to the end of their matching word, so it looks like this:
CATS2287
RATS7287
HATS4287
so far what I have is this:
for i in $(cat numbers); do
sed 's/$/'$i'/' words;
done
but the problem is a) that doesn't print/echo out to a new file and b) it loops through each word every time the first loop comes to a new number so in the end, all the words are paired up with the last number in the number file. Thanks in advance for the help.
paste -d "" /path/to/letters /path/to/numbers
Proof of Concept
$ paste -d "" CATS NUMS
CATS2287
RATS7287
HATS4287
You can use the excellent little paste(1) utility:
$ cat a
CATS
RATS
HATS
$ cat b
2287
7287
4287
$ paste -d "" a b
CATS2287
RATS7287
HATS4287
$
-d specifies a list of delimiters; I gave it a blank list: no delimiters, no delimiters.
Hmm, my version of paste with -d"" just results in numbers, the words get overwritten (GNU paste 8.10 on cygwin). my input files have no carriage returns.
paste words numbers | tr -d '\t'
Also, just with shell builtins
exec 3<words
exec 4<numbers
while read -u3 word; do
read -u4 num
echo $word$num
done
exec 3<&-
exec 4<&-
On Mac OS X:
paste -d "\0" <(echo abc) <(echo def)
there are a few ways to do that
Paste:
paste -d "" file1 file2
awk
awk '{ getline f<"file2" ; print $0f}' file1
Bash:
exec 6<"file2"
while read -r line
do
read -r S <&6
printf "${line}${S}\n"
done <"file1"
exec >&6-
Ruby(1.9+)
ruby -ne 'BEGIN{f=File.open("file1")};print $_.chomp+f.readline;END{f.close}' file
I've got a text file, and using Bash I wish to insert text into into a specific line.
Text to be inserted for example is !comment: http://www.test.com into line 5
!aaaa
!bbbb
!cccc
!dddd
!eeee
!ffff
becomes,
!aaaa
!bbbb
!cccc
!dddd
!comment: http://www.test.com
!eeee
!ffff
sed '4a\
!comment: http://www.test.com' file.txt > result.txt
i inserts before the current line, a appends after the line.
you can use awk as well
$ awk 'NR==5{$0="!comment: http://www.test.com\n"$0}1' file
!aaaa
!bbbb
!cccc
!dddd
!comment: http://www.test.com
!eeee
!ffff
Using man 1 ed (which reads entire file into memory and performs in-place file editing without previous backup):
# cf. http://wiki.bash-hackers.org/doku.php?id=howto:edit-ed
line='!comment: http://www.test.com'
#printf '%s\n' H '/!eeee/i' "$line" . wq | ed -s file
printf '%s\n' H 5i "$line" . wq | ed -s file