xpath evaluator expression for generic middle path - xpath

/MxML/trades/trade/tradeBody/fxOption/fxVanillaOption/option/optionStyle
/MxML/trades/trade/tradeBody/fxOption/**fxBarrierOption/fxOption**/fxVanillaOption/option/optionStyle
/MxML/trades/trade/tradeBody/fxOption/**fxSwapOption/fxOption**/fxVanillaOption/option/optionStyle
I am looking for a general expression for the various xpath. Though the beginning and end parts are always identical.
Is this the correct XPath?
/MxML/trades/trade/tradeBody/fxOption*//*fxVanillaOption/option/optionStyle

You were close, but you had a few extra asterisks and slashes. Try this:
/MxML/trades/trade/tradeBody/fxOption/*/fxVanillaOption/option/optionStyle

Related

What does /anystring/ mean in ruby?

I came across this: /sera/ === coursera. What does /sera/ mean? Please tell me. I do not understand the meaning of the expression above.
It's a regular expression. The more formal version of same is this:
coursera.match(/sera/)
Or:
/sera/.match(coursera)
These are both functionally similar. Either a string matches a regular expression, or a regular expression can be tested for matches against a string.
The long explanation of your original code is: Are the characters sera can be found in the variable coursera?
If you do this:
"coursera".match(/sera/)
# => #<MatchData "sera">
You get a MatchData result which means it matched. For more complicated expressions you can capture parts of the string using arbitrary patterns and so on. The general rule here is regular expressions in Ruby look like /.../ or vaguely like %r[...] in form.
You may also see the =~ operator used which is something Ruby inherited from Perl. It also means match.

simple symbol regex solution

The problem I'm looking at says only inputs with '+' symbols covering any letters in the string is true so like "+d++" or "+d+==+a+" but not
"f++d+"
"3+a=+b+"
"++d+=c+"
I tried to solve this using regex since it's kind of a string pattern matching problem. /(+[a-z][^+])|([^+.][a-z]+)/ but this does not cover patterns where the letters are at the beginning or end of the string. I need help something more comprehensive.
You should try following
/^\+{0,2}[a-z0-9]+\+{0,2}(=*\+{0-2}[a-z0-9]+\+{0,2})*$/
You could use the below regex.
^(?:[^\w\n]*\+[a-z]+\+)+[^\w\n]*$
DEMO
If you want to match +f+g+ also, then put the following + inside a positive lookahead assertion.
^(?:[^\w\n]*\+[a-z]+(?=\+))+[^\w\n]*$
DEMO

Content Inside Parenthesis Regular Expression Ruby

I'm trying to take out the the content inside the parenthesis. For example, if the string is "(blah blah) This is stack(over)flow", I want to just take out "(blah blah)" but leave "(over)" alone. I'm trying
/\A\(.*\)/
but returns "(blah blah) This is stack(over)", and I'm sure why it's returning that.
Easiest fix:
/\A\(.*?\)/
Normally, * will try to match as much as it possibly can, so it'll match all the way to the last ) in the line. This is called "greedy" matching. Putting ? after +/*/? makes them non-greedy, and they'll match the shortest possible string.
But note that this won't work for nested parentheses. That's rather more complicated. Given your example, I assume this is for a pretty simple ad-hoc format where nesting isn't a concern.

Ruby Regular Expressions: Matching if substring doesn't exist

I'm having an issue trying to capture a group on a string:
"type=gist\nYou need to gist this though\nbecause its awesome\nright now\n</code></p>\n\n<script src=\"https://gist.github.com/3931634.js\"> </script>\n\n\n<p><code>Not code</code></p>\n"
My regex currently looks like this:
/<code>([\s\S]*)<\/code>/
My goal is to get everything in between the code brackets. Unfortunately, it's matching up to the 2nd closing code bracket Is there a way to match everything inside the code brackets up until the first occurrence of ending code bracket?
All repetition quantifiers in regular expressions are greedy by default (matching as many characters as possible). Make the * ungreedy, like this:
/<code>([\s\S]*?)<\/code>/
But please consider using a DOM parser instead. Regex is just not the right tool to parse HTML.
And I just learned that for going through multiple parts, the
String.scan( /<code>(.*?)<\/code>/ ){
puts $1
}
is a very nice way of going through all occurences of code - but yes, getting a proper parser is better...

Locating the node by value containing whitespaces using XPath

I need to locate the node within an xml file by its value using XPath.
The problem araises when the node to find contains value with whitespaces inside.
F.e.:
<Root>
<Child>value</Child>
<Child>value with spaces</Child>
</Root>
I can not construct the XPath locating the second Child node.
Simple XPath /Root/Child perfectly works for both children, but /Root[Child=value with spaces] returns an empty collection.
I have already tried masking spaces with %20, & #20;, & nbsp; and using quotes and double quotes.
Still no luck.
Does anybody have an idea?
Depending on your exact situation, there are different XPath expressions that will select the node, whose value contains some whitespace.
First, let us recall that any one of these characters is "whitespace":
-- the Tab
-- newline
-- carriage return
' ' or -- the space
If you know the exact value of the node, say it is "Hello World" with a space, then a most direct XPath expression:
/top/aChild[. = 'Hello World']
will select this node.
The difficulties with specifying a value that contains whitespace, however, come from the fact that we see all whitespace characters just as ... well, whitespace and don't know if a it is a group of spaces or a single tab.
In XPath 2.0 one may use regular expressions and they provide a simple and convenient solution. Thus we can use an XPath 2.0 expression as the one below:
/*/aChild[matches(., "Hello\sWorld")]
to select any child of the top node, whose value is the string "Hello" followed by whitespace followed by the string "World". Note the use of the matches() function and of the "\s" pattern that matches whitespace.
In XPath 1.0 a convenient test if a given string contains any whitespace characters is:
not(string-length(.)= stringlength(translate(., '
','')))
Here we use the translate() function to eliminate any of the four whitespace characters, and compare the length of the resulting string to that of the original string.
So, if in a text editor a node's value is displayed as
"Hello World",
we can safely select this node with the XPath expression:
/*/aChild[translate(., '
','') = 'HelloWorld']
In many cases we can also use the XPath function normalize-space(), which from its string argument produces another string in which the groups of leading and trailing whitespace is cut, and every whitespace within the string is replaced by a single space.
In the above case, we will simply use the following XPath expression:
/*/aChild[normalize-space() = 'Hello World']
Try either this:
/Root/Child[normalize-space(text())=value without spaces]
or
/Root/Child[contains(text(),value without spaces)]
or (since it looks like your test value may be the issue)
/Root/Child[normalize-space(text())=normalize-space(value with spaces)]
Haven't actually executed any of these so the syntax may be wonky.
Locating the Attribute by value containing whitespaces using XPath
I have a input type element with value containing white space.
eg:
<input type="button" value="Import Selected File">
I solved this by using this xpath expression.
//input[contains(#value,'Import') and contains(#value ,'Selected')and contains(#value ,'File')]
Hope this will help you guys.
"x0020" worked for me on a jackrabbit based CQ5/AEM repository in which the property names had spaces. Below would work for a property "Record ID"-
[(jcr:contains(jcr:content/#Record_x0020_ID, 'test'))]
did you try #x20 ?
i've googled this up like on the second link:
try to replace the space using "x0020"
this seems to work for the guy.
All of the above solutions didn't really work for me.
However, there's a much simpler solution.
When you create the XMLDocument, make sure you set PreserveWhiteSpace property to true;
XmlDocument xmldoc = new XmlDocument();
xmldoc.PreserveWhitespace = true;
xmldoc.Load(xmlCollection);

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