I have a Text box Infopath that displays the current time using this function:
(substring-after(now(), "T")
I also have a Drop-Down list called "Location" that has the following values:
1.Boston
2.India
3.London
I want to modify this function to set the current time to always display the current time in Boston whether the user is from India or London.
I believe that inputting an If Statement that follows these conditions:
If Location (Drop down list) = "London" - Then use (substring-after(now(), "T") subtracted by 5 hours.
If Location (Drop down list) = "India" - Then use (substring-after(now(), "T") subtracted by 11 hours.
If Location (Drop down list) = "Boston" - Then use (substring-after(now(), "T").
I'm relatively new to Xpath and require assistance.
The easiest way is to subtract the hours before ripping the time off the end with substring.
substring-after(addSeconds(now(), -3600 * 5), "T")
WARNING: Remember the current time (now()) is calculated from the LOCAL machine. So if a person in London opens the form they will already be at London time and then your code will subtract 5 hours on top of that - making it incorrect.
Related
Good morning,
I have a little problem there.
I would like work with data from two different time interval.
for example, BTC (1 day time interval) and BTC (4 hour time interval) chart.
The main time interval is the 4 hour. The value "HA_C", this is the close value of "BTC 1 Day".
The "close BTC 1 Day time interval" value displayed correct in the 4 hour chart.
But the value "test" with a simple arithmetic problem differs greatly and is wrong.
You can test this as follows:
Loads the strategy in "BTC", time interval "1 Day",
note from one day the "BTC Close" value and the "test" value.
Then switch to "BTC" 4 hour time interval.
You will see, that the "HA_C Close" from the 1 hour time interval is the correct value,
but the "test" value is displayed incorrectly.
Why is the "test" value after a calculation incorrectly, although the "Close" value is correct ???
I have find out, that the problem is the "ta.ema (source, length)" function. Can someone give me a formula, that calculates the same value as the "ta.ema (source, length)" function.
**// This source code is subject to the terms of the Mozilla Public License 2.0 at https://mozilla.org/MPL/2.0/
// © flashpit
//#version=5
strategy("TEST", process_orders_on_close=true, overlay=true, calc_on_every_tick=true, pyramiding=30)
varip test = 0.0
HA_Symbol = ticker.heikinashi("BINANCE:BTCUSDT")
HA_C = request.security(HA_Symbol, "1D", close)
test:= ta.ema(HA_C, 7) * 1.05
plot (HA_C)
plot (test)**
I have finde the correct code. Here is it:
c2_1D = request.security(ticker.heikinashi('BINANCE:BTCUSDT'), "1D", t3_D (close, T3Length_1D, T3FactorCalc_1D))
It is due to the context you have called the ema function. If your chart is H4 and you perform your test calculation in the global scope, it is using 7 x H4 bars of HA_C. On BTCUSDT, over the last 7 H4 bars, it would have been 7 bars made up of multiples of only 2 daily values, hence the incorrect result.
When you change the chart to D1, it shows the correct result because now the global context of the script is now operating in the same timeframe as the security call.
If you want the correct value from the ema using 7 x 1D bars it has to be done within the context of the security call. For example :
test = request.security(ticker.heikinashi("BINANCE:BTCUSDT"), "D", ta.ema(close, 7))
If you need to perform multiple operations using the same ticker, you can also wrap them in a function and just pass the one function to a single security call. For example, this will return the daily close and the daily ema 7 :
f_ema_and_close(_src, _len) =>
_ema = ta.ema(_src, _len)
[_src, _ema]
[D1_close, D1_ema7] = request.security(ticker.heikinashi("BINANCE:BTCUSDT"), "D", f_ema_and_close(close, 7))
plot(D1_close, color = color.yellow)
plot(D1_ema7, color = color.red)
I'm trying to calculate the MAX value of column D of value E which resets for every A Column. Later I just need to show the MAX row of A.
Raw data looks like this:
The desired view would be like this:
Thanks!
This is an excellent example of a question which can/should be answered using LOD Calculations.
To start, find the maximum [Percentage] (Column E) per [Name] (Column B):
{Fixed [Name]: MAX(Percentage)}
Then insert that calculation, call it "Max Per Name", into another calculation which will only show the [Letter] (Column D) if the [Percentage] and the [Max Per Name] match:
IF [Percentage] = [Max Per Name] THEN [Letter] END
The result will be a dimension which shows the [Letter] which matches the largest [Percentage] and 'Null' when not matched.
From here, just filter out 'Null' - the result will be exactly as you desire. You will even be able to take [Percentage] off the view and still see an accurate [Letter].
Please note that while LOD Calculations are extremely powerful, they require a little more work to maintain and operate. They are a little more complex than normal calculations. Please take some time and read through this LOD Overview document to further familiarize yourself with their use/limitations.
I have panel data with different dates and object names.
I want to create panel var in Stata (function pvar), but I need to "tsset variables"
sort object date
by object: gen t = _n
encode object , gen(icode)
xtset icode t
I get this error message
t ambiguous abbreviation
I can't reproduce this problem. Consider this
. webuse grunfeld
. xtset
panel variable: company (strongly balanced)
time variable: year, 1935 to 1954
delta: 1 year
. gen t = time
. xtset company t
panel variable: company (strongly balanced)
time variable: t, 1 to 20
delta: 1 unit
Here t would be an ambiguous abbreviation for time, but Stata's rules imply that it chooses t, so the ambiguity doesn't bite.
In your case, I would ask for the results of
describe t*
I've created some xpath expressions to locate the first item by it's "index" after "h4". However, I did something wrong that is why it doesn't work at all. I expect someone to take a look into it and give me a workaround.
I tried with:
//div[#id="schoolDetail"][1]/text() --For the Name
//div[#id="schoolDetail"]//br[0]/text() --For the PO Box
Elements within which items I would like the expression to locate is pasted below:
<div id="schoolDetail" style=""><h4>School Detail: Click here to go back to list</h4> GOLD DUST FLYING SERVICE, INC.<br>PO Box 75<br><br>TALLADEGA AL 36260<br> <br>Airport: TALLADEGA MUNICIPAL (ASN)<br>Manager: JEAN WAGNON<br>Phone: 2563620895<br>Email: golddustflyingse#bellsouth.net<br>Web: <br><br>View in AOPA Airports (Opens in new tab) <br><br></div>
By the way, the resulting values should be:
GOLD DUST FLYING SERVICE, INC.
PO Box 75
Try to locate required text nodes by appropriate index:
//div[#id="schoolDetail"]/text()[1] // For "GOLD DUST FLYING SERVICE, INC."
//div[#id="schoolDetail"]/text()[2] // For "PO Box 75"
Locator to get both elements:
//*[#id='schoolDetail']/text()[position()<3]
Explanation:
[x] - xPath could sort values using predicate in square brackets.
x - could be integer, in this case it will automatically be compared with element's position in this way [position()=x]:
//div[2] - searches for 2nd div, similar to div[position()=2]
In case predicate [x] is not an integer - it will be automatically converted to boolean value and will return only elements, where result of x is true, for example:
div[position() <= 4] - search for first four div elements, as 4 <= 4, but on the 5th and above element position will be more than 4
Important: please check following locators on this page:
https://www.w3schools.com/tags/ref_httpmessages.asp
//table//tr[1] - will return every 1st row in each table ! (12 found
elements, same as tables on the page)
(//table//tr)[1] - will return 1st row in the first found table (1 found element)
I need help with the following H.W. problem. I have done everything except the instructions I numbered. Please help!
A furniture manufacturer makes two types of furniture—chairs and sofas.
The cost per chair is $350, the cost per sofa is $925, and the sales tax rate is 5%.
Write a Visual Basic program to create an invoice form for an order.
After the data on the left side of the form are entered, the user can display an invoice in a list box by pressing the Process Order button.
The user can click on the Clear Order Form button to clear all text boxes and the list box, and can click on the Quit button to exit the program.
The invoice number consists of the capitalized first two letters of the customer’s last name, followed by the last four digits of the zip code.
The customer name is input with the last name first, followed by a comma, a space, and the first name. However, the name is displayed in the invoice in the proper order.
The generation of the invoice number and the reordering of the first and last names should be carried out by Function procedures.
Seeing as this is homework and you haven't provided any code to show what effort you have made on your own, I'm not going to provide any specific answers, but hopefully I will try to point you in the right direction.
Your first 2 numbered items look to be variations on the same theme... string manipulation. Assuming you have the customer's address information from the order form, you just need to write 2 separate function to take the parts of the name and address, take the data you need and return the value (which covers your 3rd item).
To get parts of the name and address to generate the invoice number, you need to think about using the Left() and Right() functions.
Something like:
Dim first as String, last as String, word as String
word = "Foo"
first = Left(word, 1)
last = Right(word, 1)
Debug.Print(first) 'prints "F"
Debug.Print(last) 'prints "o"
Once you get the parts you need, then you just need to worry about joining the parts together in the order you want. The concatenation operator for strings is &. So using the above example, it would go something like:
Dim concat as String
concat = first & last
Debug.Print(concat) 'prints "Fo"
Your final item, using a Function procedure to generate the desired values, is very easily google-able (is that even a word). The syntax is very simple, so here's a quick example of a common function that is not built into VB6:
Private Function IsOdd(value as Integer) As Boolean
If (value Mod 2) = 0 Then 'determines of value is an odd or even by checking
' if the value divided by 2 has a remainder or not
' (aka Mod operator)
IsOdd = False ' if remainder is 0, set IsOdd to False
Else
IsOdd = True ' otherwise set IsOdd to True
End If
End Function
Hopefully this gets you going in the right direction.