I am trying to search content of file 1 into file 2 and if the content is found then store in found.csv file or store in notfound.csv file
Below is my code,
cd /mnt/data/dobiminer/scripts
usage="Usage:sh scriptname.sh 'ToSearchFile' 'MainSearchFile' 'CR' "
Date=`date +%m%d%y%H%M%S`
File=$(<$2)
echo "File Input $2"
echo $File
if [ $# != 3 ]
then
echo $usage
exit 1
else
echo > "$3-Found-$Date.csv"
echo > "$3-NotFound-$Date.csv"
for MasterClip in `cat $1`
do
echo $MasterClip
String=$(echo "$File" | grep -x $MasterClip)
echo $String
if [ -z $String ];
then
echo "NotFound"
echo $MasterClip >> "$3-NotFound-$Date.csv"
else
echo "Found"
echo $MasterClip >> "$3-Found-$Date.csv"
fi
done
fi
My guess is that the below line of code is not working, as whenever I am running the code, the string value is empty only. It is not catching the search value into it.
String=$(echo "$File" | grep -x $MasterClip)
echo $String
I tried multiple things but not sure where I am going wrong.
THanks for helping me out
I have many javascript files in my solaris server which have some debug, print and trace statements which I want to comment. There are hundreds of file like this.
I have found a script to do this but the problem is the script is removing the urhk_b2k_printRepos statement instead of commenting it. The script is as below:
if [ $# -ne 2 ]
then
echo "usage: prdel <script file name> <directory in which scripts are present>"
exit 1
fi
file=$1
dir=$2
if [ ! -s ${file} ]
then
echo "script file ${file} either does not exist or is empty (zero bytes)"
echo "Exiting..."
exit 1
fi
if [ ! -d ${dir} ]
then
echo "Invalid directory ${dir} entered"
echo "Exiting..."
exit 1
fi
cordir="./corrected"
prlogdir="./prlog"
if [ -d ${cordir} ]
then
echo "The corrected directory exist in the path, Please remove and run the tool again"
echo "Exiting..."
exit 1
else
mkdir ${cordir}
fi
if [ -d ${prlogdir} ]
then
echo "The prlog directory exist in the path, Please remove and run the tool again"
echo "Exiting..."
exit 1
else
mkdir ${prlogdir}
fi
errFile="$prlogdir/scr_err.rpt"
sucFile="$prlogdir/scr_suc.rpt"
Lines=`wc -l $file`
cntr=1
while [ $cntr -le $Lines ]
do
src=`head -$cntr $file|tail -1`
echo "$cntr. Processing $src...."
srcPath="${dir}/${src}"
if [ ! -s ${srcPath} ]
then
echo "Script file ${src} does not exist in the path given" >> ${errFile}
else
cp $srcPath $cordir/$src.tmp
srctemp="$cordir/$src.tmp"
srccor="$cordir/$src.corrected"
printcnt=`grep -ci "^[ ]*print" $srctemp`
if [ $printcnt -ne 0 ]
then
cat $srctemp|sed 's/^[ ]*[ ]*print[ ]*(/#print(/'|sed 's/^[ ]*[ ]*PRINT[ ]*(/#PRINT(/' > $srccor
mv $srccor $srctemp
fi
prreposcnt=`grep -ci "printrepos" $srctemp`
if [ $prreposcnt -ne 0 ]
then
cat $srctemp|sed 's/^.*urhk_b2k_printRepos.*/#Printrepos statement removed/'|sed 's/^.*urhk_B2k_PrintRepos.*/#Printrepos statement removed/'|sed 's/^.*urhk_B2k_printRepos.*/#Printrepos statement removed/'|sed 's/^.*urhk_b2k_PrintRepos.*/#Printrepos statement removed/' > $srccor
else
cp $srctemp $srccor
fi
echo "Script file $src correction is done" >> ${sucFile}
rm $srctemp
diff $srcPath $srccor >> $prlogdir/$src.diff.rpt
fi
cntr=`expr $cntr + 1`
done
echo "done"
I am completely new to shell scripting. Can anyone help me to modify this script to comment "urhk_b2k_printRepos" lines and also comment "TRACE ON" lines.
for var in "$#"
do
if test -z $var
then
echo "missing operand"
elif [ -d $var ]
then
echo "This is a directory"
elif [ ! -f $var ]
then
echo "The file does not exist"
else
basename=$(basename $var)
dirname=$(readlink -f $var)
inodeno=$(ls -i $var| cut -d" " -f1)
read -p "remove regular file $#" input
if [ $input = "n" ]
then exit 1
fi
mv $var "$var"_"$inodeno"
echo "$basename"_"$inodeno":"$dirname" >> $HOME/.restore.info
mv "$var"_"$inodeno" $HOME/deleted
fi
done
**Hello, the above code is trying to mimic the rm command in unix. Its purpose is to remove the file .
Eg if I type in bash safe_rm file1 , it works however if type in
bash safe_rm file1 file 2 , it prompts me to remove file 1 twice and gives me a unary operater expected for line 27(if [ $input = "n" ]).
Why does it not work for two files, ideally I would like it to prompt me to remove file1 and file 2.
Thanks
read -p "remove regular file $#" input
should probably be
read -p "remove regular file $var" input
That's the basic.
And this is how I'd prefer to do it:
for T in "$#"; do
if [[ -z $T ]]; then
echo "Target is null."
elif [[ ! -e $T ]]; then
echo "Target does not exist: $T"
elif [[ -d $T ]]; then
echo "Target can't be a directory: $T"
else
BASE=${T##*/}
DIRNAME=$(exec dirname "$T") ## Could be simpler but not sure how you want to use it.
INODE_NUM=$(exec stat -c '%i' "$T")
read -p "Remove regular file $T? "
if [[ $REPLY == [yY] ]]; then
# Just copied. Not sure about its logic.
mv "$T" "${T}_${INODE_NUM}"
echo "${BASE}_${INODE_NUM}:${DIRNAME}" >> "$HOME/.restore.info"
mv "${T}_${INODE_NUM}" "$HOME/deleted"
fi
fi
done
#!/bin/bash
a=coop; b=(`echo $a | sed 's/\(.\)/\1\n/g'`)
for i in ${b[#]}
do
echo -n $i
count=$((count+1))
if [ $count = 2 ]; then
echo -e '\e[0;34m'$i
shift
echo -ne $*'\e[0m'
fi
done
Output: cooop (the middle one is in blue). What I want the script to do is show the exact word stored in the variable named "a". But as you can see, another "o" is added next to "p". So how can i go about removing the extra letter?
Try this:
#!/bin/bash
blue='\e[0;34m'
nc='\e[0m'
a=coop
b=($(echo $a | sed 's/\(.\)/\1\n/g'))
count=0
for i in ${b[#]}; do
if [ $count = 2 ]; then
echo -ne "${blue}${i}"
echo -ne "${nc}"
else
echo -n "$i"
fi
count=$((count+1))
done
Following is a source code which takes in only 'files',lists the file permissions of a file and prints the output by replacing
r=READ,w-WRITE,x-EXECUTABLE.
It should also echo "User".But the My problem here is that I have replaced '-' by User but then if the file has a permission of r--x,it also prints "User" # that point.I know its not a correct way to go about it.Can anyone suggest me a better way of echoing "User".
I have also tried printing it before the loop but then it won't serve my purpose, as My program only works withe file permissions of a FILE and not any block/socket/pipe/directory/etc.
#!/bin/bash
if [ $# -lt 1 ];then
echo "USAGE: $0 file-name"
exit 1
fi
ls -l $1 | cut -c1-4 | tr "\012" "." > fp
i=1
while(($i <= 4))
do
p=`cat fp | cut -c$i`
case $p in
[dbsplc] | t) echo "not a file";
exit 1;;
-) echo "User";;
r) echo "READ";;
w) echo "WRITE";;
x) echo "EXECUTE";;
esac
((++i))
done
exit 0
Too complicated. You don't have to rely on ls at all:
#!/bin/bash
if [[ $# -lt 1 ]]; then
echo "USAGE: $(basename "$0") filename ..."
exit 1
fi
exit_status=0
for file in "$#"; do
if [[ ! -f "$file" ]]; then
echo "not a file: $file" >&2
exit_status=$(( exit_status + 1 ))
continue
fi
echo "$file:"
echo "User"
[[ -r "$file" ]] && echo "READ"
[[ -w "$file" ]] && echo "WRITE"
[[ -x "$file" ]] && echo "EXECUTE"
done
exit $exit_status
I'd just use stat -c %a and process that instead.
an exemple using awk (easily adaptable to your program)
ll |awk '{
rights=substr($1, 2, 3);
sub(/r/, "READ ", rights);
sub(/w/, "WRITE ", rights);
sub(/x/, "EXECUTE ", rights);
print rights $3
}'
Explanations :
rights=substr($1, 2, 3);
$1 contains rights of your program and we only takes the 3 first rights (user one)
sub(/r/, "READ ", rights);
Substiture "r" with READ in rights (and so on).
print rights $3
Print rights (substituated) and $3 that contains the user name.
This served my purpose,I separated the first condition into a different case-statement.:
#!/bin/bash
if [ $# -lt 1 ];then
echo "USAGE: $0 file-name"
exit 1
fi
ls -l $1 | cut -c1-4 | tr "\012" "." > fp
i=1
while(($i == 1))
do
p=`cat fp | cut -c$i`
case $p in
[dbsplc] | t) echo "not a file";
exit 1;;
esac
echo "User"
((++i))
done
while(($i <= 4))
do
p=`cat fp | cut -c$i`
case $p in
r) echo "READ";;
w) echo "WRITE";;
x) echo "EXECUTE";;
esac
((++i))
done
exit 0