Collect lines of a buffer - elisp

Question

There's process output that needs to be parsed per line, into structs.
sug skProc strutils.capitalize proc (string): string{.noSideEffect.}
sug skProc strutils.quoteIfContainsWhite proc (string): string
sug skProc system.gorge proc (string, string): string
sug skProc system.of proc (T, S): bool{.noSideEffect.}
sug skProc system.definedInScope proc (expr): bool{.noSideEffect.}
sug skIterator system.items iterator (cstring): char{.inline.}
sug skProc system.ord proc (T): int{.noSideEffect.}
This data is inside a buffer. So how do I read each line and pass it
to a function which returns a parsed representation and collect all
lines in the end?
EDIT: The code for parsing the lines (not debugged):
(defstruct nimrod-sug type namespace name signature)
(defun nimrod-parse-suggestion-line (line)
(let ((split (split-string line "[\t\n]")))
(make-nimrod-sug
:type (nth 1 split)
:namespace (first (split-string (nth 2 split) "\\."))
:name (second (split-string (nth 2 split) "\\."))
:signature (nth 3 split))

Answer 1

With some minor changes to the parser:
(defun nimrod-parse-suggestion-line (line)
(destructuring-bind (_ type fn &rest sig) (split-string line "[[:space:]]+" t)
(make-nimrod-sug :type type
:namespace (first (split-string fn "\\."))
:name (second (split-string fn "\\."))
:signature (apply 'concat sig))))
Assuming the name of the buffer is *output*, you can parse it like so:
(with-current-buffer "*output*"
(mapcar 'nimrod-parse-suggestion-line
(split-string (buffer-string) "[\r\n]" t)))
; => ([cl-struct-nimrod-sug "skProc" "strutils" "capitalize" "proc(string):string{.noSideEffect.}"] ...)
If you're currently visiting the output buffer, you won't need the with-current-buffer wrapper.