I use query:
select LAST_LOAD_TIME, ELAPSED_TIME, MODULE, SQL_TEXT elasped from v$sql
WHERE MODULE='JDBC Thin Client'
ORDER BY LAST_LOAD_TIME DESC
elasped:
delete from tableA where fk in (select pk from tableB where tableB.fk=:1
and tableB.date between :2 and :3)
Is it possible find these parameters 1, 2 and 3?
Something like this:
select s.sql_id,
bc.position,
bc.value_string,
s.last_load_time,
bc.last_captured
from v$sql s
left join v$sql_bind_capture bc
on bc.sql_id = s.sql_id
and bc.child_number = s.child_number
where s.sql_text like 'delete from tableA where fk%' -- or any other method to identify the SQL statement
order by s.sql_id, bc.position;
Related
I am trying to use a query to return the count from rows such that the date of the rows matches the maximum date for that column in the table.
Oracle SQL: version 11.2:
The following syntax would seem to be correct (to me), and it compiles and runs. However, instead of returning JUST the count for the maximum, it returns several counts more or less like the "HAIVNG" clause wasn't there.
Select ourDate, Count(1) as OUR_COUNT
from schema1.table1
group by ourDate
HAVING ourDate = max(ourDate) ;
How can this be fixed, please?
You can use:
SELECT MAX(ourDate) AS ourDate,
COUNT(*) KEEP (DENSE_RANK LAST ORDER BY ourDate) AS ourCount
FROM schema1.table1
or:
SELECT ourDate,
COUNT(*) AS our_count
FROM (
SELECT ourDate,
RANK() OVER (ORDER BY ourDate DESC) AS rnk
FROM schema1.table1
)
WHERE rnk = 1
GROUP BY ourDate
Which, for the sample data:
CREATE TABLE table1 (ourDate) AS
SELECT SYSDATE FROM DUAL CONNECT BY LEVEL <= 5 UNION ALL
SELECT SYSDATE - 1 FROM DUAL;
Both output:
OURDATE
OUR_COUNT
2022-06-28 13:35:01
5
db<>fiddle here
I don't know if I understand what you want. Try this:
Select x.ourDate, Count(1) as OUR_COUNT
from schema1.table1 x
where x.ourDate = (select max(y.ourDate) from schema1.table1 y)
group by x.ourDate
One option is to use a subquery which fetches maximum date:
select ourdate, count(*)
from table1
where ourdate = (select max(ourdate)
from table1)
group by ourdate;
Or, a more modern approach (if your database version supports it; 11g doesn't, though):
select ourdate, count(*)
from table1
group by ourdate
order by ourdate desc
fetch first 1 rows only;
You can use this SQL query:
select MAX(ourDate),COUNT(1) as OUR_COUNT
from schema1.table1
where ourDate = (select MAX(ourDate) from schema1.table1)
group by ourDate;
I have a function, which will get greatest of three dates from the table.
create or replace FUNCTION fn_max_date_val(
pi_user_id IN number)
RETURN DATE
IS
l_modified_dt DATE;
l_mod1_dt DATE;
l_mod2_dt DATE;
ret_user_id DATE;
BEGIN
SELECT MAX(last_modified_dt)
INTO l_modified_dt
FROM table1
WHERE id = pi_user_id;
-- this table contains a million records
SELECT nvl(MAX(last_modified_ts),sysdate-90)
INTO l_mod1_dt
FROM table2
WHERE table2_id=pi_user_id;
-- this table contains clob data, 800 000 records, the table 3 does not have user_id and has to fetched from table 2, as shown below
SELECT nvl(MAX(last_modified_dt),sysdate-90)
INTO l_mod2_dt
FROM table3
WHERE table2_id IN
(SELECT id FROM table2 WHERE table2_id=pi_user_id
);
execute immediate 'select greatest('''||l_modified_dt||''','''||l_mod1_dt||''','''||l_mod2_dt||''') from dual' into ret_user_id;
RETURN ret_user_id;
EXCEPTION
WHEN OTHERS THEN
return SYSDATE;
END;
this function works perfectly fine and executes within a second.
-- random user_id , just to test the functionality
SELECT fn_max_date_val(100) as max_date FROM DUAL
MAX_DATE
--------
27-02-14
For reference purpose i have used the table name as table1,table2 and table3 but my business case is similar to what i stated below.
I need to get the details of the table1 along with the highest modified date among the three tables.
I did something like this.
SELECT a.id,a.name,a.value,fn_max_date_val(id) as max_date
FROM table1 a where status_id ='Active';
The above query execute perfectly fine and got result in millisecods. But the problem came when i tried to use order by.
SELECT a.id,a.name,a.value,a.status_id,last_modified_dt,fn_max_date_val(id) as max_date
FROM table1 where status_id ='Active' a
order by status_id desc,last_modified_dt desc ;
-- It took almost 300 seconds to complete
I tried using index also all the values of the status_id and last_modified, but no luck. Can this be done in a right way?
How about if your query is like this?
select a.*, fn_max_date_val(id) as max_date
from
(SELECT a.id,a.name,a.value,a.status_id,last_modified_dt
FROM table1 where status_id ='Active' a
order by status_id desc,last_modified_dt desc) a;
What if you don't use the function and do something like this:
SELECT a.id,a.name,a.value,a.status_id,last_modified_dt x.max_date
FROM table1 a
(
select max(max_date) as max_date
from (
SELECT MAX(last_modified_dt) as max_date
FROM table1 t1
WHERE t1.id = a.id
union
SELECT nvl(MAX(last_modified_ts),sysdate-90) as max_date
FROM table2 t2
WHERE t2.table2_id=a.id
...
) y
) x
where a.status_id ='Active'
order by status_id desc,last_modified_dt desc;
Syntax might contain errors, but something like that + the third table in the derived table too.
Want to add column to Table A
Table_A
ID,
ZONE
I want to add ACCNT HAVING VALUE NEW
Just in SELECT statement:
SELECT A.*, B.* FROM TABLE_A A , (SELECT "NEW" AS ACCNT FROM DUAL) B
You dont need a select statement to add a column with constant name, just write query as below:
SELECT *, 'New' as Zone
FROM TABLE_A
If you need to rename a particular column, then you could do it as follows:
SELECT id, accnt as New
FROM TABLE_A
Using below Query i am able to do the above task .
SELECT A.*, B.* FROM TABLE_A A , (SELECT "NEW" AS ACCNT FROM DUAL) B
Very old thread, but giving answer to close it.
You can directly use it in your query as following:
SELECT A.*, 'NEW' as acct FROM TABLE_A A
Cheers!!
I need to make a conversion from Oracle SQL to PostgreSQL.
select * from table1 inner join table2 on table1.id = table2.table1Id
where table1.col1 = 'TEST'
and rownum <=5
order by table2.col1
If I delete and rownum <=5 and put at the end limit 5, there are differences between the 2 dialects. In Oracle, first are selected the 5 elements, and after that, they are sorted by table2.col1 . In Postgres, first all the list is sorted, and AFTER there are selected the first 5 elements.
How can I obtain the same result in Postgres as in Oracle?
Thanks!
To get the behavior you desire, you can use a subquery like this:
SELECT * FROM (
SELECT table1.col1 as t1col1, table2.col1 as t2col1
FROM table1 INNER JOIN table2 ON table1.id = table2.table1Id
WHERE table1.col1 = 'TEST'
LIMIT 5
) AS sub
ORDER BY t2col1;
I named the columns there because in your example both tables had a col1.
Note however that without any ordering on the inner query, the selection of 5 rows you get will be purely random and subject to change.
Depending on the version you are using, PostgreSQL 8.4 and above have Window functions. Window function ROW_NUMBER() is capable of implementing the functionality of Oracle pseudo column rownum.
select row_number() over() as rownum,* from table1 inner join table2 on table1.id = table2.table1Id where table1.col1 = 'TEST' and rownum <=5 order by table2.col1;
which column i need to use to join V$session and V$sqlarea?
My main aim is to find top 5 queries with most disk_reads and generate a report containing relevant information.
Thanks
Try below one, I think it satisfy your requirement.
Find top 5 queries with most disk_reads.
SELECT SESION.SID,
SESION.USERNAME,
OPTIMIZER_MODE,
HASH_VALUE,
ADDRESS,
CPU_TIME,
ELAPSED_TIME,
DISK_READS,
DIRECT_WRITES,
SQL_TEXT
FROM V$SQLAREA SQLAREA, V$SESSION SESION
WHERE SESION.SQL_HASH_VALUE = SQLAREA.HASH_VALUE
AND SESION.SQL_ADDRESS = SQLAREA.ADDRESS
AND SESION.USERNAME IS NOT NULL
AND ROWNUM < 6
ORDER BY DISK_READS DESC,ELAPSED_TIME DESC;
This SQL does the join:
select s.sid, s.serial#, a.sql_text
from v$session s
join v$sqlarea a on a.hash_value = s.sql_hash_value;