CodeIgniter form validation optional based on value - codeigniter

I'm setting up a form with CI and I'm using the form validation to help me with this.
At the moment I have different rules setup, like
$this->form_validation->set_rules('first_name', 'First Name', 'required|xss_clean');
But in my form I have a checkbox, enabling the checkbox will show some new inputs that are required when the checkbox is checked.
When the checkbox is unchecked these fields are not required.
What would be the best method to do this in CI?
// Set validation rules
$this->form_validation->set_rules('first_name', 'First Name', 'required|xss_clean');
$this->form_validation->set_rules('last_name', 'Last Name', 'required|xss_clean');
// Some more rules here
if($this->form_validation->run() == true) {
// Form was validated
}

I faced something just like this a couple months ago. I just added a short if-statement.
It looked something like this (using address for example):
$this->form_validation->set_rules('home_address', '"Home Address"', 'required|trim|xss_clean|strip_tags');
$this->form_validation->set_rules('unit', '"Unit"', 'trim|xss_clean|strip_tags');
$this->form_validation->set_rules('city', '"City"', 'required|trim|xss_clean|strip_tags');
$this->form_validation->set_rules('state', '"State"', 'required|trim|xss_clean|strip_tags');
$this->form_validation->set_rules('zip', '"Zip"', 'required|trim|xss_clean|strip_tags');
//checkbox formatted like this in the view: form_checkbox('has_second_address', 'accept');
if ($this->input->post('has_second_address') == 'accept')
{
$this->form_validation->set_rules('street_address_2', '"Street Address 2"', 'required|trim|xss_clean|strip_tags');
$this->form_validation->set_rules('state_2', '"State 2"', 'required|trim|xss_clean|strip_tags');
$this->form_validation->set_rules('city_2', '"City 2"', 'required|trim|xss_clean|strip_tags');
$this->form_validation->set_rules('zip_2', '"Zip 2"', 'required|trim|xss_clean|strip_tags');
}
if($this->form_validation->run() == true) {
//example
//will return FALSE if empty
$street_address_2 = $this->input->post('street_address_2');
//and so on...
}
I'm not sure if this is the Codeigniter way or not, but last time I checked I couldn't find a "best method" way. This definitely gets the job done, and it at minimum allows you to take control over a users $_POST variables.
Anyways, I hope this helps

if($this->input->post('checkbox_name')){
// add more validation rules here
}

you could use javascript / jquery to set the value of a hidden field to true or false depending of whether the checkbox has been checked.
Then in your controller check with a conditional
if ($hidden_field) {
//run more validation.
}

Related

how to set the radio button's 'checked' attribute dynamically.

I've developed a Joomla 2.5 component that does ALMOST exactly what I want it to do. I have a form that contains a fieldset with 2 radio buttons (for "am" and "pm"). I have been unable to figure out how to set the appropriate button's 'checked' attribute based upon other information. It is trivial to set a default within the xml file that defines the form fields, but I don't see how I to do this dynamically.
It is possible? Have I missed something in the documentation that would explain how to do this??
In case you load the form from the view: in the display() method of view.html you will be loading your form:
$this->form = $this->get('Form');
This is invoking a model which in turns extends joomla.application.component.modelform; its getForm method loads the form:
$form = $this->loadForm('com_yourcomp.model', ...
This is what I gather from your description. If this is not the case you might want to move the suggested code below right after you load the form: this is the complete snippet that allows you to set the value of a field:
/// Load the form from the model:
$this->form = $this->get('Form');
// Check for errors.
if (count($errors = $this->get('Errors'))) {
throw new Exception(implode("\n", $errors));
}
//... some logic ...
$this->form->setValue('businessid',null,$businessId);
$this->form->setFieldAttribute( 'businessid', 'readonly', 'true' );

Laravel 3 - How to validate checkbox array, for at least 1 checked?

I'm starting to learn Laravel and still on the learning curve. Now I'm starting with Laravel 3 but will most probably switch my project into Laravel 4 once I get something working.
Now the question being, how to validate an array of checkbox, I want to validate that at least 1 inside the group is enable(checked). I read somewhere on Laravel forum that we just validate them using a required, but when I dd(input::all()) I don't see anything else but the inputs field and checkbox are not part of them...
Part of my Blade Create code for the checkbox:
<label class="checkbox">{{ Form::checkbox('changeReasons[]', 'ckbCRCertification', Input::had('ckbCRCertification'), array('id' => 'ckbCRCertification')) }} Certification</label>
<label class="checkbox">{{ Form::checkbox('changeReasons[]', 'ckbCRDesignCorrection', Input::had('ckbCRDesignCorrection'), array('id' => 'ckbCRDesignCorrection')) }} Design Correction</label>
My controller (REST) code is:
public function post_create()
{
print "Inside the post_create()";
// validate input
$rules = array(
'ecoNo' => 'min:4',
'productAffected' => 'required',
'changeReasons' => 'required'
);
$validation = Validator::make(Input::all(), $rules);
if($validation->fails())
{
return Redirect::back()->with_input()->with_errors($validation);
}
$eco = new Eco;
$eco->ecoNo = Input::get('ecoNo');
$eco->productAffected = Input::get('productAffected');
$eco->save();
return Redirect::to('ecos');
}
I also want to know the correct code for getting the checkboxes state after a validation fails, I thought I saw the Input::had(checkBoxName) somewhere but that doesn't seem to work, I'm probably not using it correctly and I'm getting a little confuse on that since all example I see are for inputs and nothing else. I assume the validation is roughly the same in L4, would it be?
Going back on this project and making some more researches, I have found the best way for this problem is the following.
My blade view:
<div class="control-group row-fluid">
<?php $arrChangeReasons = Input::old('changeReasons', array()); // array of enable checkboxes in previous request ?>
<label class="checkbox">{{ Form::checkbox('changeReasons[]', 'certification', in_array('certification', $arrChangeReasons)) }} Certification</label>
<label class="checkbox">{{ Form::checkbox('changeReasons[]', 'designCorrection', in_array('designCorrection', $arrChangeReasons)) }} Design Correction</label>
</div>
The explanation of the blade view is a 2 steps process, after a validation occur, is the following:
Pull the checkbox array (in my case 'changeReasons[]') with Input::old
From that array we can then search for individual checkbox and see if they are in there, if they are then change the checkbox as a checked state. That is the job of the in_array() function, returning a true/false will change the state of the checkbox.
My controller (REST) code is exactly as it was written in my question at the beginning. For more information, defining $rules = array('changeReasons' => 'required'); will make sure that at least 1 of the checkboxes is checked.
Please remember that Checkboxes need a value like .
It the Checkbox is checked Input::get('foo') will return 1, but if it is unchecked it will return nothing, because it is not in the post-array.
I'm using this code:
if(Input::get('foo')){
$bar->is_foo = 1;
}
else{
$bar->is_foo = 0;
}

Drupal Form API : display the same form again with AJAX, but with different values, on submit

this is my first post on Stackoverflow, after reading perhaps hundreds of thoughtful questions and no less useful answers.
My point is, today, I never found an (even dirty) way to do what I intend to do, and never managed to find an answer, although it seems quite improbable that no one ever had the same request and/or problem.
Which is, by the way...
Calling the same form again with AJAX, but with different values than those previously entered by the user
The idea
I've got a Drupal Form (a normal form built with Drupal Form API) with textfields and an AJAX-ified submit button. This form is displayed through an AJAX call and is itself AJAX-ified, so.
When I click on 'Submit', I want to do some stuff like looking in the database, updating some values, etc, based on what the user entered in the form. And then, I want to ajax-display the same form again, but with different values than those entered by the user in the first instance of the form.
Everything goes fine with doing whatever I want during the processing, but whatever I do, no matter what, I face the same problem again and again :
The problem
When the new instance of the form is displayed, it is displayed with the previous values (those entered by the user). I never was able to display other values than those previously here in the form when "Submit" was clicked in the previous instance of the form.
Simple example
What I'm actually trying to do is quite complex, with several ajax_commands and a bit of processing, but here is a simpler example that faces exactly the same problem :
function ajax_first_callback_to_my_form($type = 'ajax') {
// here the first instance of the form is ajax-called. No problem with that.
$mail = 'example#mail.com';
$first_message = 'Please enter an email address...';
$commands = array();
$commands[] = ajax_command_replace('#my_ajax_wrapper', display_my_form($mail, $first_message));
$page = array('#type' => 'ajax', '#commands' => $commands);
return($page);
}
function display_my_form($mail, $message) {
// the function used to display the form.
// it can be called by the first ajax callback (the previous function in this example)
// or by the ajax callback triggered by clicking 'submit' on the form itself.
$form = drupal_get_form('my_form', $mail, $message);
$display = '<div id="my_ajax_wrapper">';
$display .= render($form);
$display .= '</div>';
return $display;
}
function my_form($form, &$form_state, $mail, $message) {
// the form constructor
$form = array (
'email' => array (
'#type' => 'textfield',
'#default_value' => $mail,
'#suffix' => '<div id="my_message">'.$message.'</div>',
),
'submit' => array (
'#type' => 'submit',
'#ajax' => array (
'callback' => 'my_ajax_callback', ),
),
);
}
function my_ajax_callback($form, &$form_state) {
// triggered by clicking 'submit' in the form
$mail = $form_state['values']['email'];
if ($mail == 'correct_mail#gmail.com') {
$new_mail = 'different_mail#gmail.com';
$new_message = 'You entered a correct email and here is your new one';
} else {
$new_mail = $mail;
$new_message = 'You entered an incorrect mail, please correct it';
}
$commands = array();
$commands[] = ajax_command_replace('#my_ajax_wrapper', display_my_form($new_mail, $new_message));
$page = array('#type' => 'ajax', '#commands' => $commands);
return($page);
}
function my_form_submit($form, &form_state) {
// my_form submit handler
$form_state['rebuild'] = true; // appears necessary, otherwise won't work at all
}
Okay, it was quite a long piece of code but it seemed useful to fully understand my question.
Processing stuff happens correctly...
All the stuff I want to do in my_form_submit or in my_ajax_callback is properly done. If I check the variables in display_my_form() they are correctly updated.
... but the new instance of the form doesn't take it into account
But whatever I can try, the next time the form is displayed with AJAX, the email field will be 'example#mail.com' as its default value (or any different mail entered by the user), and the message div will be filled with 'Please enter an email address...'.
I tried MANY ways of doing this differently, putting the after-submit processing in the ajax callback, in the my_form_submit function, using $_SESSION variables instead of passing them through the different functions, using the database... None of this works.
What to do ?
Quite annoying. This is not the first time I encountered this problem. Last time I could find a workaround, simply by giving up this idea of re-displaying the same form through AJAX, but now I really would appreciate being able to do this.
Could the problem be related to $form_state['rebuild'] ?
By the way, I'm curious about it : have you encountered this problem before ? Is it something simple which I'm missing out ? If it's a bug, could this bug be Drupal-related, or AJAX-related... ?
Any help or ideas will be truly appreciated. Thank you for your time.
I came up with a solution to this one :
If you are to display the same form again with AJAX, for instance with this function (called by your AJAX callback), no matter what you'll do, it will display the same values again and again :
// It doesn't work :
function display_my_form($mail, $message) {
$form = drupal_get_form('my_form', $mail, $message);
$display = '<div id="my_ajax_wrapper">';
$display .= render($form);
$display .= '</div>';
return $display;
}
If you want to change the fields values when refreshing the form, you have to update the form manually, after having called it again, by adding this kind of line :
// It works :
function display_my_form($mail, $message) {
$form = drupal_get_form('my_form', $mail, $message); // $variables are simply ignored if the form is already displayed. Rebuilding it won't change a thing.
$form['email']['#default_value'] = $mail; // update a part of the form
$form['email']['#suffix'] = $message; // update another part of the form
$display = '<div id="my_ajax_wrapper">';
$display .= render($form);
$display .= '</div>';
return $display; // sends $display to our AJAX callback, and everything's fine now
}
Contrary to easy belief one (such as... me) can first have about it, the form doesn't take into account the variables it's being sent with drupal_get_form, when already constructed and recalled by AJAX.
It's just not enough to update the variables, and do drupal_get_form again. You have to do drupal_get_form, and afterwards manually update the parts of the form you want updated.
Hope this will help someone.
Well I am quite confident about your issue if this is the case:
$commands[] = ajax_command_replace('#my_ajax_wrapper', display_my_form($new_mail, $new_message));
The problem is not anything else its just the id you are passing.You need a class and not the id "#my_ajax_wrapper", because id might get changed but class won't in this case.
Try with this you should get the result as you want.
Note: to make it work, one needs to add this in form_submit handler:
function my_form_submit($form, &$form_state)
{
$form_state['rebuild'] = true;
}

How do I repopulate fields BEFORE validation is passed?

The fields I am making required to fill out, should repopulate the correctly filled out fields, while NOT submitting the form and posing errors for the incorrectly filled out fields. What is the best way to do that?
Please note that with this code, I am repopulating the fields as they should be upon submitting the form correctly and they are all displaying when page is reloaded.
<div class="dropdown_structure">
<?php
if($user['location'] == "empty")
{
echo country_dropdown('location');
}
else
{
echo country_dropdown('location',$user['location']);
}
?>
</div>
Also please note that I've tried inserting the value in the input fields.
$data = array( 'name' => 'location', 'value' => $this->input->post('location'));
echo relation_dropdown('location');
Thanks in advance
Hi if you are using the following country dropdown helper you can set value validation in following way
Country dropdown helper
country_dropdown('location',array(),set_value('location'))
even in your second dropdown use set_value('field_name') will work. if validation is failed your selected value will be remain.

Drupal Webform Validation (webform_form_alter)

I'm doing some webform validation using webform_form_alter. I'm using webform_form_alter because I switch certain content on a "select" field.
In my webform-form-317.tpl.php I defined new fieldsets I set my fields into this new fieldset and unset the original from the webform.
$form['submitted']['ContactInfo'] = array(
'#type' => 'fieldset',
'#prefix' => '<div id="ContactInfo">',
'#suffix' => '</div>',
'#weight' => -10,
'#title' => 'Contact Information'
);
$form['submitted']['ContactInfo']['phone_home'] = $form['submitted']['phone_home'];
unset($form['submitted']['phone_home']);
in my webform_form_alter I have the following code:
switch ($form_id)
{
case 'webform_client_form_317':
{
$form['#validate'][] = 'validate_form';
}
}
My Validate_form function looks like:
function validate_form($form_id, $form_values)
{
if ($form_values['submitted_tree']['ContactInfo']['phone_home'] == "")
{
form_set_error('phone_error', t('Please enter a home phone number.'));
}
}
The issue is that the $form_values['submitted_tree']['ContactInfo']['phone_home'] comes back as nothing even is the user has inputted something into the textfield.
Any suggestions on what i'm doing wrong?
As a second question in case somebody also the answers, how do I modify the of these textfields to set the class for "form-text required error" so they show up in red with the rest of the mandatory fields.
Thanks
I hope you don't write this code in the webform module, but have made your a custom module for it.
In the first case, your function should be
function validate_form($form, &$form_state) {
if ($form_state['values']['submitted_tree']['ContactInfo']['phone_home'] == "") {
form_set_error('phone_home', t('Please enter a home phone number.'));
}
}
If you are talking about the error class, Drupal add it to all fields that has an error set like is done on the above code. You need to pass in the name of the form field as first param to the form_set_error function.

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