Click on link to hide all other content divs - show-hide

Example: (werkwijze is custom, i also have the same code with other names like -contact)
$(function() {
$('#activator-werkwijze').click(function(){
$('#overlay-werkwijze').fadeIn('fast',function(){
$('#box-werkwijze').animate({'bottom':'0px'},800);
});
});
$('#boxclose-werkwijze').click(function(){
$('#box-werkwijze').animate({'bottom':'-600px'},800,function(){
$('#overlay-werkwijze').fadeOut('fast');
});
});
});
activator shows the content, boxclose closes the content.
clicking all activators opens all content while it needs to open only one and close the others..
edit got it fixed:
This is the script which works, (the overlay is useless) jsfiddle.net/8y7Sr/126/

You need to provide more information about how you are calling the pop-up script. If you are using jquery, you can just close all and then open one
$('.className').slideDown(200);
$('#specificItem').slideUp(200);
But again, you should explain how you are doing the calls in more detail for a better answer

example, put inside function jQuery
if($('.hide').css('display')=='block'){ $('.hide').slideUp(); }else{ $('.hide').slideDown(); }

$(function() {
$('.activator').each(function(){
$(this).click(function(){
showHideAnimation(clickedObj);
});
});
}
function showHideAnimation(clickedObj)
{
$('.activator').each(function(){
if($(this).id == clickedObj.id) {
$(this).fadeIn('fast',function(){
$(this).animate({'bottom':'0px'},800);
});
} else {
$(this).animate({'bottom':'-600px'},800,function(){
$(this).fadeOut('fast');
});
}
}
}
Please try this if it doesn't work properly then replace $(this) with only this

Related

CasperJS: Open a new window

Have a link on the page:
<a id="quote" href="quote.html" target="_blank">Quote</a>
Click it in CasperJS, but I can't capture the page in new window.
casper.start('http://domain.com');
casper.thenClick('#quote');
casper.then(function() {
this.capture('file1.png');
});
casper.run();
see also the documentation in casperjs about:
casper.waitForPopup();
casper.withPopup();
the new window(when clicking on link with target="_blank" attribute) can be considered as Popup.
document at: http://docs.casperjs.org/en/latest/modules/casper.html#waitforpopup
CasperJS doesn't work with new windows. You have to manually remove the "target=_blank" before cliking on the link :
this.evaluate(function () {
[].forEach.call(__utils__.findAll('a'), function(link) {
link.removeAttribute('target');
});
});
casper.start('http://domain.com');
casper.thenClick('#quote');
casper.waitForResource('file1.png' , function() {
this.capture('file1.png');
});
casper.run();
You should try to wait for all the resources to be loaded, then proceed with other job. This will always work.

Prototype.js event.target.id for child elements

I want to hide a div when clicking somewhere else in the page. For this, I have:
$(document.body).observe('click', function(e){
if(e.target.id != 'myDiv') {
$('myDiv').hide();
}
});
Works fine, the only problem is that inside this div I have other elements, and clicking them also closes #myDiv. I want it so that clicking anything inside this div won't trigger the hiding. After searching around, I found the answer here on how to do this with jQuery: https://stackoverflow.com/a/12222263/548524. However, I can't seem to get this working in Prototype, and obviously has() is not valid here.
Any help is much appreciated!
document.observe('click', function(event) {
if (!event.findElement('#myDiv')) {
$('myDiv').hide();
}
});
You don't need $(document.body) - there is already document-wide observe
There is a method to find element from event
Use the 'up' function:
$(document.body).observe('click', function(e){
if(e.target.id != 'myDiv' && !$(e.target.id).up('#myDiv')) {
$('myDiv').hide();
}
});

How to check if a button is clicked in JavaScript

How to check if a button is clicked or not in prototype JavaScript?
$('activateButton').observe('click', function(event) {
alert(hi);
});
The code above is not working.
With this button:
<button id="mybutton">Click Me</button>
Use this:
$('mybutton').observe('click', function () {
alert('Hi');
});
Tested and works, here.
You might want to encase it in a document.observe('dom:loaded', function () { }) thingy, to prevent it executing before your page loads.
Also, just an explanation:
The single dollar sign in Prototype selects an element by its id. The .observe function is very similar to jQuery's .on function, in that it is for binding an event handler to an element.
Also, if you need it to be a permanent 'button already clicked' thingy, try this:
$('mybutton').observe('click', function () {
var clicked = true;
window.clicked = clicked;
});
And then, if you want to test if the button has been clicked, then you can do this:
if (clicked) {
// Button clicked
} else {
// Button not clicked
}
This may help if you are trying to make a form, in which you don't want the user clicking multiple times.
How one may do it in jQuery, just for a reference:
$('#mybutton').on('click', function () {
alert('Hi');
});
Note that, the jQuery code mentioned above could also be shortened to:
$('#mybutton').click(function () {
alert('Hi');
});
jQuery is better in Prototype, in that it combines the usage of Prototype's $ and $$ functions into a single function, $. That is not just able to select elements via their id, but also by other possible css selection methods.
How one may do it with plain JavaScript:
document.getElementById('mybutton').onclick = function () {
alert('Hi');
}
Just for a complete reference, in case you need it.
$('body').delegate('.activateButton', 'click', function(e){
alert('HI');
});

jquery .submit live click runs more than once

I use the following code to run my form ajax requests but when i use the live selector on a button i can see the ajax response fire 1 time, then if i re-try it 2 times, 3 times, 4 times and so on...
I use .live because i also have a feature to add a post and that appears instantly so the user can remove it without refreshing the page...
Then this leads to the above problem... using .click could solve this but it's not the ideal solution i'm looking for...
jQuery.fn.postAjax = function(success_callback, show_confirm) {
this.submit(function(e) {
e.preventDefault();
if (show_confirm == true) {
if (confirm('Are you sure you want to delete this item? You can\'t undo this.')) {
$.post(this.action, $(this).serialize(), $.proxy(success_callback, this));
}
} else {
$.post(this.action, $(this).serialize(), $.proxy(success_callback, this));
}
return false;
})
return this;
};
$(document).ready(function() {
$(".delete_button").live('click', function() {
$(this).parent().postAjax(function(data) {
if (data.error == true) {
} else {
}
}, true);
});
});​
EDIT: temporary solution is to change
this.submit(function(e) {
to
this.unbind('submit').bind('submit',function(e) {
the problem is how can i protect it for real because people who know how to use Firebug or the same tool on other browsers can easily alter my Javascript code and re-create the problem
If you don't want a new click event bound every time you click the button you need to unbind the event before re-binding it or you end up with multiple bindings.
To unbind events bound with live() you can use die(). I think the syntax using die() with live() is similar to this (untested):
$(document).ready(function(){
$('.delete_button').die('click').live('click', function(){
$(this).parent().postAjax(function(data){
if (data.error == true){
}else{
}
}, true);
});
});
However, if you are using jQuery 1.7 or later use on() instead of live() as live() has been deprecated since 1.7 and has many drawbacks.
See documentation for all the details.
To use on() you can bind like this (I'm assuming the delete_button is a dynamically added element) :
$(document).ready(function(){
$(document).off('click', '.delete_button').on('click', '.delete_button', function(){
$(this).parent().postAjax(function(data){
if (data.error == true){
}else{
}
}, true);
});
});
If you are using an earlier version of jQuery you can use undelegate() or unbind() and delegate() instead. I believe the syntax would be similar to on() above.
Edit (29-Aug-2012)
the problem is how can i protect it for real because people who know
how to use Firebug or the same tool on other browsers can easily alter
my Javascript code and re-create the problem
You can some-what protect your scripts but you cannot prevent anyone from executing their own custom scripts against your site.
To at least protect your own scripts to some degree you can:
Write any script in an external js file and include a reference to that in your site
Minify your files for release
Write any script in an external js file and include a reference to that in your site
That will make your html clean and leave no trace of the scripts. A user can off course see the script reference and follow that for that you can minify the files for release.
To include a reference to a script file:
<script type="text/javascript" src="/scripts/myscript.js"></script>
<script type="text/javascript" src="/scripts/myscript.min.js"></script>
Minify your files for release
Minifying your script files will remove any redundant spacing and shorten function names to letters and so no. Similar to the minified version of JQuery. The code still works but it is meaningless. Off course, the hard-core user could follow meaningless named code and eventually figure out what you are doing. However, unless you are worth hacking into I doubt anyone would bother on the average site.
Personally I have not gone through the minification process but here are some resources:
Wikipedia - Minification (programming)
Combine, minify and compress JavaScript files to load ASP.NET pages faster
How to minify (not obfuscate) your JavaScript using PHP
Edit (01-Sep-2012)
In response to adeneo's comment regarding the use of one().
I know you already found a solution to your problem by unbinding and rebinding to the submit event.
I believe though it is worth to include a mentioning of one() in this answer for completeness as binding an event with one() only executes the event ones and then unbinds itself again.
As your click event, when triggered, re-loads and rebinds itself anyway one() as an alternative to unbinding and re-binding would make sense too.
The syntax for that would be similar to on(), keeping the dynamic element in mind.
// Syntax should be right but not tested.
$(document).ready(function() {
$(document).one('click', '.delete_button', function() {
$(this).parent().postAjax(function(data) {
if (data.error == true) {} else {}
}, true);
});
});​
Related Resources
live()
die()
on()
off()
unbind()
delegate()
undelegate()
one()
EDIT AGAIN !!!! :
jQuery.fn.postAjax = function(show_confirm, success_callback) {
this.off('submit').on('submit', function(e) { //this is the problem, binding the submit function multiple times
e.preventDefault();
if (show_confirm) {
if (confirm('Are you sure you want to delete this item? You can\'t undo this.')) {
$.post(this.action, $(this).serialize(), $.proxy(success_callback, this));
}
} else {
$.post(this.action, $(this).serialize(), $.proxy(success_callback, this));
}
});
return this;
};
$(document).ready(function() {
$(this).on('click', '.delete_button', function(e) {
$(e.target.form).postAjax(true, function(data) {
if (data.error) {
} else {
}
});
});
});​
jQuery.fn.postAjax = function(success_callback, show_confirm) {
this.bind( 'submit.confirmCallback', //give your function a namespace to avoid removing other callbacks
function(e) {
$(this).unbind('submit.confirmCallback');
e.preventDefault();
if (show_confirm === true) {
if (confirm('Are you sure you want to delete this item? You can\'t undo this.')) {
$.post(this.action, $(this).serialize(), $.proxy(success_callback, this));
}
} else {
$.post(this.action, $(this).serialize(), $.proxy(success_callback, this));
}
return false;
})
return this;
};
$(document).ready(function() {
$(".delete_button").live('click', function() {
$(this).parent().postAjax(function(data) {
if (data.error == true) {
} else {
}
}, true);
});
});​
As for the "people could use Firebug to alter my javascript" argument, it does not hold : people can also see the request that is sent by your $.post(...), and send it twice.
You do not have control over what happens in the browser, and should protect your server side treatment, rather than hoping that "it won't show twice in the browser, so it will prevent my database from being corrupt".

Why are the jQuery functions only working the first time they're called?

There is a link that, when clicked, toggles between loading HTML into a div and emptying the div. When the div is clicked to load the html, I use the jQuery ajax load() function. When the text is loading, I want to display "Please wait...", so I tried using the jQuery ajaxStart() and ajaxStop() methods, but they only seemed to work the first time the load() function was called. So I switched to ajaxSend() and ajaxSuccess, but that also only seems to work the first time the load function is called. What's wrong?
HTML:
<p id="toggleDetail" class="link">Toggle Inspection Detail</p>
<p id="wait"></p>
<div id="inspectionDetail"></div>
jQuery:
$(
function(){
$('#toggleDetail').click(function(){
if($.trim($('#inspectionDetail').text()).length)
{
$('#inspectionDetail').empty();
}
else
{
$('#inspectionDetail').load('srInspectionDetailFiller.cfm');
}
});
}
);
$(
function(){
$('#wait').ajaxSend(function() {
$(this).text('Please wait...');
});
}
);
$(
function(){
$('#wait').ajaxSuccess(function() {
$(this).text('');
});
}
);
You should put up the 'Please wait...' message in your click function, then clear the message upon successful completion of your load:
$('#toggleDetail').click(function(){
if($.trim($('#inspectionDetail').text()).length)
{
$('#inspectionDetail').empty();
}
else
{
$('#wait').text('Please wait...');
$('#inspectionDetail').load('srInspectionDetailFiller.cfm', function() {
$('#wait').text('');
});
}
});
Edit: Although ajaxSend should technically work here, I don't recommend it. With ajaxSend, "All ajaxSend handlers are invoked, regardless of what Ajax request is to be sent". It seem overkill to me to hook all Ajax requests on the page which you're really only trying to deal with this single click.

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