I have a formula like this : =ArrayFormula(sort(INDEX($B$1:$B$10,MATCH(E1,$A$1:$A$10,0))))
in columns A:B:
a 1
b 2
c 3
d 4
e 5
f 6
g 7
h 8
i 9
j 10
and
the data to convert in E:H
a c f e
f a c b
b a c d
I get the following results using the above formula
in columns L:O:
1 3 6 5
6 1 3 2
2 1 3 4
My desired output is like this:
1 3 5 6
1 2 3 6
1 2 3 4
I'd like to arrange the numbers from smallest to biggest in value. I can do this with additional helper cells. but if possible i'd like to get the same result without any additional cells. can i get a little help please? thanks.
To sort by row, use SORT BYROW. But unfortunately, nested array results aren't supported in BYROW. So, we need to JOIN and SPLIT the resulting array.
=ARRAYFORMULA(SPLIT(BYROW(your_formula,LAMBDA(row,JOIN("🌆",SORT(TRANSPOSE(row))))),"🌆"))
Here's another way using Makearray with Index to get the current row and Small to get the smallest, next smallest etc. within the row:
=ArrayFormula(makearray(3,4,lambda(r,c,small(index(vlookup(E1:H3,A1:B10,2,false),r,0),c))))
Or you could change the order (might be a little faster) as you don't need to vlookup the entire array, just the current row:
=ArrayFormula(makearray(3,4,lambda(r,c,small(vlookup(index(E1:H3,r,0),A1:B10,2,false),c))))
It's interesting (to me at any rate) that you can interrogate the row and column number of the current cell using Map or Scan, so this is also possible:
=ArrayFormula(map(E1:H3,lambda(cell,small(vlookup(index(E1:H3,row(cell),0),A1:B10,2,false),column(cell)-column(E:E)+1))))
Thanks to #JvdV for this insight (which may be obvious to some but wasn't to me) shown here in Excel.
try:
=INDEX(TRIM(SPLIT(FLATTEN(QUERY(QUERY(QUERY(SPLIT(FLATTEN(E1:H3&"×​"&ROW(E1:H3)), "​"),
"select max(Col1) group by Col1 pivot Col2"), "offset 1", 0),,9^9)), "×")))
or if you want numbers:
=INDEX(IFNA(VLOOKUP(TRIM(SPLIT(FLATTEN(QUERY(QUERY(QUERY(SPLIT(FLATTEN(E1:H3&"×​"&ROW(E1:H3)), "​"),
"select max(Col1) group by Col1 pivot Col2"), "offset 1", 0),,9^9)), "×")), A:B, 2, 0)))
I need some help to determine the best approach on how I can use VBA to find duplicates in a column 2 and swap the rows that have the duplicates in Column 2 (in this example the row 5 with row 6). Please see below sample.
Column 1 Column 2 Column 3
A 1 yes
B 2 no
C 3 no
D 4 yes
E 5 no
F 5 yes
The exercise question asks:
Consider a relation R(A, B, C) and S(A, B, D) containing the
following tuples:
A B C A B D
------- -------
6 8 7 5 8 7
6 6 7 6 6 7
7 8 6 6 8 6
What to be produced from the expression
πA,D(R⋈σB=8 (S))
And gives the answer as:
A D
----
6 6
Why is this?
I understand that pi is the projection so it will only output tables A and D. First thing I don't understand is why is it not AAD in the new table as there are 2 A's and Second thing is I don't understand what the selection criteria means.
Selection B=8 from S will give
A B D
5 8 7
6 8 6
Join with R will give
A B C D
6 8 7 6
since A=6 and B=8 in R table(1st row) and resulting S table(2nd row)
From the projection you will see the answer
Let's work from the inside out. First, consider σB=8 (S). This is a selection. We use S as our source but we only allow through tuples that match the B=8 condition. So lets label this new relation T(A, B, D):
A B D
-------
5 8 7
6 8 6
The 6,6,7 tuple didn't get selected since its B value doesn't equal 8.
Now lets consider R⋈T. This is a natural join between my above T tuple and R. Natural join is based on all columns with the same name being used to join the relations. We don't get two As or Bs in this result because a) they're always equal, and b) tuple elements are distinguished by name so you cannot have multiple elements with the same name. So, we produce U(A,B,C,D):
A B C D
----------
6 8 7 6
(Because only tuple (6,8,7) from R and (6,8,6) from T have matching A and B values).
Finally, we project to only retain A and D from U. Hopefully I don't have to explain that.
I have the following mock up table
#n a b group
1 1 1 1
2 1 2 1
3 2 2 1
4 2 3 1
5 3 4 2
6 3 5 2
7 4 5 2
I am using SAS for this problem. In column group, the rows that are interconnected through a and b are grouped. I will try to explain why these rows are in the same group
row 1 to 2 are in group 2 since they both have a = 1
row 3 is in group 2 since b = 2 in row 2 and 3 and row 2 is in group 1
row 3 and 4 are in group 1 since a = 2 in both rows and row 3 is in group 1
The overall logic is that if a row x contains the same value of a or b as row y, row x also belongs to the same group as y is a part of.
Following the same logic, row 5,6 and 7 are in group 2.
Is there any way to make an algorithm to find these groups?
Case I:
Grouping defined as to be item linkage within contiguous rows.
Use the LAG function to examine both variables prior values. Increase the group value if both have changed. For example
group + ( a ne lag(a) and b ne lag(b) );
Case II:
Grouping determined from pair item slot value linkages over all data.
From grouping pairs by either key
General statement of problem:
-----------------------------
Given: P = p{i} = (p{i,1},p{i,2}), a set of pairs (key1, key2).
Find: The distinct groups, G = g{x}, of P,
such that each pair p in a group g has this property:
key1 matches key1 of any other pair in g.
-or-
key2 matches key2 of any other pair in g.
Demonstrates
… an iterative way using hashes.
Two hashes maintain the groupId assigned to each key value.
Two additional hashes are used to maintain group mapping paths.
When the data can be passed without causing a mapping, then the groups have
been fully determined.
A final pass is done, at which point the groupIds are assigned to each
pair and the data is output to a table.
Hi I am trying to do get some data displayed using FILTER function in google sheets.
What i want is the minimum value across 3 columns on 1 row.
Is this possible?
For example:
A 1 6 10
B 3 5 9
C 4 4 8
D 5 3 7
A 2 1 6
Filter on A should give:
A 1
A 1
Filter on B should give:
B 3
I would really like to use filter function but =filter({A:A,min(B:D)},A:A="A") doesn't work.
Maybe, if your three (labelled) columns are A, B and C:
=filter(A2:C2,A2:C2=min(A2:C2))
but in that case filter would be overkill.