I have a xml like
<root xmlns:ns1="http://foo">
<ns1:child1>Text</ns1:child1>
<ns1:child2>Number</ns1:child2>
</root>
Now I get this from different persons, so that for example person 2 sends me another message with the same structure like
<root xmlns:anotherNs="http://foo">
<anotherNs:child1>Another Text</anotherNs:child1>
<anotherNs:child2>Another Number</anotherNs:child2>
</root>
So the only difference is the name of the namespace. How can I select the content of child2 for both xml's with one XPath expression?
Something like "/root/child2" or "//child2" did not work.
Use the local-name() function like so:
//*[local-name()='child2']
You can bind any prefix you like (say banana) to the namespace "http://foo", and the expression /root/banana:child2 will find the child2 element, regardless what namespace prefix has been used in the source document. Only the namespace URI has to match.
Related
I have an XML that has a node with an XML as it's
value(<name> <name1> <name2>value</name2> </name1> </name>),
The problem is that this value is an XML not converted to XML.
How can I access this value by node name2?
I used these two functions:
substring-before(string, string)
substring-after(string, string) to return what i want and it works
The problem is that I can't use this kind of function in the application I'm using, because it has a primitive version of XPath that doesn't accept advanced XPath.
<Input>
<Response>
<name> <name1> <name2>value</name2> </name1> </name>
</Response>
</Input>
<name2>value</name2>
Your code is not well-formed XML.
But you can pre-process the entities with sed, for example:
sed -e "s/</</g; s/>/>/g" input.xml
This command changes all < and > entities to < and >, respectively.
After this conversion, you can apply an XML parser to your data.
I have posted sample XML and expected output kindly help to get the result.
Sample XML
<root>
<A id="1">
<B id="2"/>
<C id="2"/>
</A>
</root>
Expected output:
<A id="1"/>
You can formulate this query in several ways:
Find elements that have a matching attribute, only ascending all the time:
//*[#id=1]
Find the attribute, then ascend a step:
//#id[.=1]/..
Use the fn:id($id) function, given the document is validated and the ID-attribute is defined as such:
/id('1')
I think it's not possible what you're after. There's no way of selecting a node without its children using XPATH (meaning that it'd always return the nodes B and C in your case)
You could achieve this using XQuery, I'm not sure if this is what you want but here's an example where you create a new node based on an existing node that's stored in the $doc variable.
declare variable $doc := <root><A id="1"><B id="2"/><C id="2"/></A></root>;
element {fn:node-name($doc/*)} {$doc/*/#*}
The above returns <A id="1"></A>.
is that what you are looking for?
//*[#id='1']/parent::* , similar to //*[#id='1']/../
if you want to verify that parent is root :
//*[#id='1']/parent::root
https://en.wikipedia.org/wiki/XPath
if you need not just parent - but previous element with some attribute: Read about Axis specifiers and use Axis "ancestor::" =)
I would like to know if the following XPath expression can be simplified:
//map[requester/#type='2' and requester/code]
Some test data:
<root>
<map>
<requester type="2">
<code>a</code>
<code>b</code>
</requester>
</map>
...
</root>
My objective is to get only map elements which have at least one requester with type attribute and value '2' and also have at least one code element.
For your use case, this is probably as simple as it could be. However, it doesn't match what you are describing doing.
Here you are selecting map elements where
There is a requester element with type attribute equal to 2
There is a requester element with a code element
The requester elements in (1) and (2) are not necessarily the same
For example, the map element in the following is selected:
<root>
<map>
<requester type="2"/>
<requester>
<code>a</code>
</requester>
</map>
</root>
If you want the elements in (1) and (2) to be the same, you should use (simplified slightly at the suggestion of kjhughes)
//map[requester[#type='2']/code]
Here we select all map elements which have a requester element which in turn has an attribute type with a value of 2 and a code element.
I am having difficulty figuring out an XPath query that would allow me to return nodes based on the value of the Program attribute in the example below. For example, I would like to be able to search all nodes for a value of the Program attribute = "011.pas". I tried /Items/*[Program="012.pas"] and also /Items/Item*[Program="01.pas"] but neither works. What is the correct expression?
<Items>
<Item0 Program="01.pas"></Item0>
<Item1 Program="011.pas"></Item1>
</Items>
The attribute is selected with #Program, the child elements of the Items element with /Items/*, so you want /Items/*[#Program = '011.pas'].
Try this :
/items/*[#Program='011.pas']
I have the following xml structure:
<?xml version="1.0" encoding="UTF-8"? >
<sql>
<Assoc name="sql">
<RecArray name="contents">
<Record name="contents">
<String name="PackType" > < value actual="P" />< /String >
<String name="SerialNumber" > < value actual="0002" />< /String >
<String name="VersionNumber" > < value actual="02" /></ String >
</Record>
</RecArray>
</Assoc>
</sql>
how can i get the values of each of the String nodes like i need to know the value inside the node of "SerialNumber"
Regards,
If you wan to get all <value> elements inside each <String> element, you can try this XPath query :
/sql/Assoc/RecArray/Record/String/value
precise path will be better performance wise. If you're looking for simpler query, this will also work :
//String/value
or if you mean by values of each of the String nodes is value of actual attribute, you can do this way :
/sql/Assoc/RecArray/Record/String/value/#actual
Finally, if none of above meet your requirement, please update the question and provide expected output from sample XML posted.
i figured it out
as it is multi String elements (that was clear in the question), i should use the following
/sql/Assoc/RecArray/Record/String[2]/value/#actual