I'm currently generating breadcrumbs on an object's Details page by calling a GetBreadcrumbs() method in the object's controller - in this method, the object's parent/grandparent are used to generate an unordered list. What's the best way to pull the HTML out of the controller to follow the Separation of Concerns paradigm? Should a partial view be used here?
Typical example of partial view is Breadcrum itself. For example, in your controller you can have
//
//GET: News/Article/x
public ActionResult Article(int id)
{
//get parentid of article
ViewBag.id = id;
ViewBag.parentid;
return View();
}
So, your partial view will be as below:
#{
ViewBag.Title = "Article";
}
<h2>Viewing Article #ViewBag.parentid >> #ViewBag.id</h2>
You could use partial views or display templates. Your controller should only build the model that will be passed to the view and then inside the view you could use a display template that will build the desired output based on the model.
Related
MVC/ASP.NET/C#/html/javascript newbie question:
I'm trying to move some legacy software into an MVC solution. I have an MVC controller ViewResult method that makes an API call to the legacy system and returns a string which is a fully formed HTML page (including the HTML start and end tags). Some time in the future, I'll rewrite the logic as an MVC view, but for right now I need to just display that page (preferably in a new tab).
I've tried this in the controller:
return View((object)calendar);
(where "calendar" is the string containing the HTML document)
In my view I have
#model string
#{ Layout = null; }
#Model
But that didn't work.
Any ideas?
Model binding is binding the object of your model class.
For example, ([Solution].[Models].[Model class]),
#model PassDatainMVC.Models.Record
To pass the data from controller to view,
Approach 1: ViewBag
Controller:
string data = "testing";
ViewBag.see = data;
return View();
View:
#using PassDatainMVC.Models
#ViewBag.see
Or:
Approach 2: Model binding
Controller (Class):
public string recordProperty;
View:
#model PassDatainMVC.Models.Record
#Model.recordProperty
While you have to set the property under the model class in the data field for the second approach.
Ref. https://www.c-sharpcorner.com/article/asp-net-mvc-passing-data-from-controller-to-view/
If you want to just one data you can use a ViewBag. This is simple.
Also you want to send with model. You should use this code.
Class
public class Calendar
{
public string CalendarName { get; set; }
}
Controller
Calendar newModel = new Calendar();
newModel.CalendarName = "test name...";
return View(newModel);
View
#model ModelNamespace.Calendar
<h1> #Model.CalendarName </h1>
Thanks Reha! But unfortunately neither of your suggestions did the trick.
For your first suggestion I used ViewBag. In the controller I replaced
return View((object)calendar);
to
ViewBag.calendar = calendar;
return View();
And replaced the view with just
#{ Layout = null; }
#ViewBag.calendar
The result was that the user is left looking at the actual HTML code instead of what the HTML code is supposed to render.
For your 2nd suggestion, I did exactly as you suggested (except I changed
Model.CalendarName = "test name...";
to
Model.CalendarName = calendar;
The result is the same, the user is left looking at the HTML code.
I currently have a _layout.cshtml used by every page of my website.
I need to put a form on each page displayed as a popin.
So, i created a new PartialView (the content of my form) with its corresponding ViewModel and called it in _layout.cshtml.
However, i have a model conflict between ViewModels of pages using the layout and the ViewModel used by the new form (since we can't have directly two models for the same view).
The model item passed into the dictionary is of type 'XXX', but this
dictionary requires a model item of type 'YYY'.
How can we include a form in _layout without this conflict ?
The following has worked for me with a sidebar on every page.
Create a controller for your partial view
In that controller, create a method for the view you want to return, and be sure to use the [ChildActionOnly] filter
public class PartialController : Controller
{
[ChildActionOnly]
public PartialViewResult Alerts()
{
return PartialView("Alerts", messages);
}
}
In your _layout view, you'll have the following:
#Html.Action("Alerts", "Partial")
(instead of #Html.RenderPartial or #Html.Partial)
It sounds like you already have what you need for the view.
I have not used this with a form, but it should work similarly. Hope this helps.
I am looking at an example of how to use MVC Contrib Grid :
https://web.archive.org/web/20211020001718/https://www.4guysfromrolla.com/articles/031611-1.aspx
I am already using a #model on the page for something else, and I want to be able to create up to 6 grids on my page. Is it possible to pass a method that returns the grid contents to the Grid object?
You can pass any number of collections from the controller action to the view through ViewData or ViewBag.
public ActionResult Index()
{
ViewData["foos"] = GetFoos();
ViewData["bars"] = GetBars();
ViewData["bazz"] = GetBazz();
return View(/*model*/);
}
And in the view
#Html.Grid((IEnumerable<Foo>)ViewData["foos"]).Columns(...)
#Html.Grid((IEnumerable<Bar>)ViewData["bars"]).Columns(...)
#Html.Grid((IEnumerable<Bazz>)ViewData["bazz"]).Columns(...)
In my asp.net mvc3 application i have created two partial views for two different action that is,
partialviewresult setcomment and
partialviewresult getcomment
i have created partial view using create a strongly type view and different scaffold template
for _setcomment i am using create template and for _getcomment i am using List template.
Now i want to call both _setcomment and _getcomment partial view in one view.
in my view file .cshtml
_setcomment -
#model <NAMESPACE>.<MODELNAME>
<some code>
_getcomment -
#model IEnumerable<<NAMESPACE>.<MODELNAME>>
<some code>
how can i call diiferent partial view in one view?
any suggestions?
There are different ways to do it.
If you already have the model class data in the Main view you can use like
In the main view call
#Html.Partial("PartialViewName1",model1)
#Html.Partial("PartialViewName1",model2)
If you do not have the model class data in the mail view then you can call the action on the controller and from there return the partial view.
#Html.Action("Controller","Action1")
#Html.Action("Controller","Action2")
In the Controller class
PartialResult Action1()
{
model = new ModelClass();
return PartialView(model);
}
Hope this helps.
The answer to your question is to use the following within a single view:
#{ Html.RenderAction("ActionName", "ControlerName"); }
#{ Html.RenderAction("ActionName2", "ControlerName2"); }
This would do what you are trying to achieve, however, I think there is a problem with design. What are you trying to achieve?
I am using MVC 3 with the Razor view engine. I want to set some values in the ViewBag inside a Partial View and want retrieve those values in my _Layout.cshtml. For example, when you setup a default ASP.NET MVC 3 project you get a _Layout.cshtml file in the "/Views/Shared" folder. In that _Layout.cshtml the Page Title is set like this:
<title>#ViewBag.PageTitle</title>
Then in "/Views/Home/About.cshtml" view the contents of the ViewBag are modified:
#{
ViewBag.Title = "About Us";
}
This works fine. When the About view is rendered the page title is "About Us". So, now I want to render a Partial view inside my About view and I want to modify the ViewBag.Title inside my Partial view. ("/Views/Shared/SomePartial.cshtml")
#Html.Partial("SomePartial")
In this Partial view I have this code:
#{
ViewBag.Title = "About Us From The Partial View";
}
When I debug this code I see the ViewBag.Title get set to "About Us" and then in the Partial view I see it get reset to "About Us From The Partial View", but when the code hits the _Layout.cshtml it goes back to "About Us".
Does this mean that if the contents of the ViewBag are modified in a Partial view, those changes will not appear(be accessible) in the main view (About.cshtml) or the _Layout.cshtml?
Thanks in advance!
If you pass the ViewBag into the partial's viewdatadictionary, then pull it out (and cast), you can do whatever you want and the reference is kept. The cool part is that since it's dynamic, you can even add properties and then they'll show up on the parent page's Viewbag.
Page:
//set the viewbag into the partial's view data
#{Html.RenderPartial("Elaborate", Model, new ViewDataDictionary { {"vb", ViewBag}});}
Partial:
#{
var vb = ((dynamic)ViewData["vb"]);
vb.TheTitle = "New values";
}
Page
#ViewBag.TheTitle = "New value"
I also had this problem, and couldn't find any neat and obvious solution.
The solution I came up with was to implement an Html extension method that returns a 'PageData' class that you define, containing whatever data you need:
[ThreadStatic]
private static ControllerBase pageDataController;
[ThreadStatic]
private static PageData pageData;
public static PageData GetPageData(this HtmlHelper html) {
ControllerBase controller = html.ViewContext.Controller;
while (controller.ControllerContext.IsChildAction) {
controller = controller.ControllerContext.ParentActionViewContext.Controller;
}
if (pageDataController == controller) {
return pageData;
} else {
pageDataController = controller;
pageData = new PageData();
return pageData;
}
}
It finds the top-level controller for the current request, and returns the same PageData object every time the method is called within the same HTTP request. It creates a new PageData object the first time it is called in a new HTTP request.
The partial view gets its own ViewBag.
You can get the page's ViewBag from ((WebViewPage) WebPageContext.Current.Page).ViewBag
You can do this trick in your partial view to override the title in your _Layout.cshtml:
#{
ViewBag.Title = "About Us From The Partial View";
}
......
<script type="text/javascript">
document.title = "#ViewBag.Title";
</script>
As others have pointed out Layout, Views and Partials get their own ViewBag. However, I was able to get it to work with the following:
In the View or Partial.
#{ Html.ViewContext.ViewBag.Title = "Reusable Global Variable"; }
Then in _Layout
#Html.ViewContext.ViewBag.Title
By explicitly using the ViewContext, the views 're-use' the same ViewBag.
If anyone is still looking for a solution to this it appears that you can do it with TempData:
TempData["x"] = x;
TempData is persisted until it is read so you can just read it in your _Layout. You just have to be careful that you read everything so that it is cleared for the next request.
I've tried the following and it works:
In the (parent) view...
#Html.Partial("SomePartial", ViewData, null)
Note: ViewData is passed as the model argument, but you have to specify null for the viewData argument to use the correct overload. You can't use ViewBag because Html.Partial doesn't like dynamics.
Then , in the partial view...
#model ViewDataDictionary
#{
Model["Title"] = "About us from the partial view";
}
Of course, if you need to use the model argument for a real model, you'll have to be more creative.
try #SLaks code with
(((WebViewPage) WebPageContext.Current.Page).ViewBag).PropertyName
I encountered the same problem when I use mvc3, and I found that
this.ViewBag.ViewBag.PropertyName
works in your custom control.
I this is what page data is designed for. Pop this into your view.
#Page.somePropertyName = "Whatever you want";
And then access it in your layout view. Be sure to check that its not null first.
#{
if(Page.somePropertyName != null)
{
//Do stuff
}
}