Cakephp 2 render multiple elements from 1 controller function - ajax

I call a Js link to update a product status (active/inactive) via ajax
echo $this->Js->link('[X]',
array('action' => 'deactivate', $p['Product']['id']),
array('before'=>$this->Js->get('#loading')->effect('fadeIn'),
'success'=>$this->Js->get('#loading')->effect('fadeOut'),
'update'=> '#'.$divString));
Once the ajax is made, a table row is hidden via the update.
The view is rendered using
$this->render('index_ajax_empty_table_row', 'ajax');
Now i need to update a my menu (via ajax) that holds the categories and counts of active products. So from the same contoller action is am trying
$this->render('index_ajax_menu', 'ajax');
The code will only render the first item or the wrong one in the wrong place.
How do i define multiple success and tell which element to render for each div?

Related

Best strategy to avoid Ajax roundtrips when updating databases in Laravel

Let's say I have a table with data in the rows coming from a database. On each row of this table there are helper buttons. These buttons perform instant operations on the database, such as setting a status code (for example sold, blocked, in progress), changing an invoice date for the row (for example from 18/11/2022 to null) and so on..
What I would like is that when a user clicks on one of these buttons, an ajax function will performs a request to the related controller that will show a modal box asking for confirmation (not a JS alert but HTML code that comes from a blade component).
So, giving a basic example in the case of the change of status code for the row, what I would do is first set up a route of this type:
Route::post('/status', [TableController::class, 'status']);
after that i will build my controller(using the related model Table) in a way that if the action value coming from the ajax request is confirm(the one coming from the confirmation modal), I will continue with the data update, if instead the action is something different such as status(the one coming from the helper button), then I will bring up my confirmation modal
class TableController extends Controller {
// Change status
public function status(Request $request){
if( $request['action'] == 'confirm' ) {
// Update DB
Table::where('id', $request->id)->update(['status' => 822]);
} else {
$id = $request->id;
// Show confirmation modal
return \Blade::render('<x-confirm :title="$title" :action="$action" :id="$id" />',
[
"title" => "Vuoi bloccare le seguenti disponibilità? ".$id ?,
"action" => "status",
"id" => $id
]);
}
}
If you notice the return of component part here
// Show confirmation modal
return \Blade::render('<x-confirm :title="$title" :action="$action" :id="$id" />'
I'm passing to the component the id of the row, and the action to perform, those datas will be usefull for the next ajax request coming from the confirmation modal, that will update the row in the database. But basically what is happening here?
Send data from frontend to the controller(id of the row, status action, status code).
Send back the same data from the backend to modal component to fill the ajax confirmation request.
Resend back to the server the same data to catch the confirm statement and update the database.
This kind of approach always worked for me, but when things becomes complex(let's say that I have different kind of helpers like I said before, in example remove a date, change the owner, set some flags etc) this will become a mess, because I have everytime to send back the same data that I just received.
So my question:
Is there a way to avoid this thing to sending back and forward those datas? like something in the middle that stores what am I doing in the current session and can inform the modal box without this round trip? Also i am really thinking that my approach is completely wrong and out of mind, so i have to see things from a different point of view? This is because I am self-taught so I certainly have some gaps that I would like to fill.

Passing name of button on click to controller in web2py

Basically what i want is that in my view file i have a list of various restaurants,and in front of each of them is a "show" button,which on clicking should display three more buttons(dynamically),where each button performs some action regarding the corresponding restaurant name(like show menu,show reviews)(this action should be dynamic too). Can anybody help me with this implementation.
In the view you can place a link and a target container:
{{=A('the link', callback=URL('controller', 'function', args=[my_arg]), target="callback-target", _class="btn btn-default")}}
<div id="callback-target"></div>
If the link is clicked the function in controller is called and you can read the argument my_arg with:
def function():
data = request.args(0)
response.flash('Data received!')
return DIV('Return anything ...')
The returned data is displayed in <div id="callback-target"></div>

show success message on same page after adding recording without reloadin the site in cakephp 2.x

I want to add a show sucess message using :-
session->flash(); ?> in view and added the message in controller :-
Session->setFlash("Record has been saved successfully."); ?>
But I donot want to reload the whole page.
I am just inserting the new record using ajax.. and refreshing the div having list of all record.
session->flash(); ?> this works if i reload the whole page.
how can I show message once the record is saved using ajax.
Solutions (i recommend the first one):
Create AJAX method in controller that return 200 code with JSON/HTML record's data or any other error code if sth goes wrong. Then in js do:
$.ajax({ ... }).done(function( data ) {
// Success, show the record and message
$('#flash').text('Success!').show();
// ...
}).error( function() {
// Error
$('#flash').text('Error!').show();
});
Refresh the records list by calling ajax method and return not only the view with list of all records, but also a flash message (in the same view). Then show it or move using javascript.

Yii Displaying Image dynamically dependent on dropdown

I'm trying to display an image but is dependent on a dropdown list in Yii. I can get the image from the database and display it, but how to do it dynamically depending on the choice from the dropdown?
Here is the reference: http://www.yiiframework.com/wiki/24/creating-a-dependent-dropdown#hh0 but, let me show you how to do it.
First all all, we need a div where the image will be displayed; I'll create one whose id will be 'img'. Then, the ajax request is specified inside the dropdownlist() as follows:
<?php echo $form->labelEx($model,'attribue'); ?>
<?php echo $form->dropDownList($model,'attribute',
array(/*The options in the DropDownList*/),
array(
'ajax'=>array(
'type'=>'POST',
'url'=>CController::createUrl('YourController/actionWhichEchoesTheImage'),
'update'=>'#img',
)));
?>
<div id="img"> // <---- the result of the ajax call will be displayed here
</div>
In the 'url' attribute we specify the function which will be called when the ajax request triggers. In the 'update' attribute we specified the div where will be displayed the result of calling that function (the image).
Finally, we have to declare the action actionWhichEchoesTheImage(). Let's declare it in the current controller. It would look something like this:
public function actionWhichEchoesTheImage()
{
if(isset($_POST['ModelName']['attribute']))
/*Here goes your code to load the image*/
echo CHtml::image(//Check the reference to see how to set this function);
}
Check CHtml::image() here: http://www.yiiframework.com/doc/api/1.1/CHtml/#image-detail

JSF: Navigation issue (Ajax / Non-Ajax)

When the following (PrimeFaces) button is pressed
<p:commandButton value="Search"
actionListener="#{personController.searchPersons}"
update="resultTable"/>
I load a list of objects and display them in a table on the current page. This is done via an Ajax call.
Now I'd like to do the following: If only one object is found, don't update the result table but link directly to the "detail page". (e.g. detail.xhtml)
How can this be done?
I know that i can control the navigation via the return value of my searchPersons() method. But It doesn't work as it should. I think it has to do with the update="resultTable" of my button. But I currently don't know how to solve this...
You can bring in some JS in oncomplete attribute. It will be executed when the bean action and the partial update is completed. You can change the window location in JS by assigning window.location a new URL.
Here's a random kickoff example, assuming that you've a persons table with id persons and that the detail link look something like <a class="detail" href="detail.xhtml?id=123"> somewhere in the table row.
oncomplete="var $persons = jQuery('#persons tbody tr'); if ($persons.length == 1) window.location = $persons.find('a.detail').attr('href');"

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