Upload files with Jquery File Upload in ASP.NET MVC 3 - asp.net-mvc-3

Question

Does anyone has a clean suggestion of instantiate this jquery's useful library.
I need to submit files and manage the Json response from the server.
I always get none json response within the Js code. I have reviewed some articles mentioning it but the code doesn't fit to the purpose.
The situation is: I achieve the submition and saving in the database but the Json response never arrives.
Thanks in advance.
This is my view code:
<script type="text/javascript">
$("#formUplImg").fileupload({
dataType: "json",
url:'#Url.Action("CreateJson","ProductImage")',
done: function (e, data) {
alert(data.StatusMessage);
}
});
</script>
#using (Html.BeginForm("CreateJson", "ProductImage", FormMethod.Post, new { id = "formUplImg", enctype = "multipart/form-data", #class = "jqtransform" }))
{
#Html.ValidationSummary(true)
<div class="rowElem">
<input type="file" id="Content" name="Content" />
</div>
<div class="rowElem">
#Html.ValidationMessageFor(item => item.Content)
</div>
<div class="rowElem">#Html.JQueryUI().Button("Guardar imagen", ButtonElement.Button, ButtonType.Submit, new { id = "guardar_imagen" })</div>
}
This is my controller action code:
[HttpPost]
public ContentResult CreateJson(UploadedFileInfo fileInfo)
{
try
{
if (fileInfo.Content == null)
throw new Exception("Hubo problemas con el envío. Seleccione un archivo a subir");
var file = new TempDocument
{
CreatedBy = User.Identity.Name,
CreationTime = DateTime.Now,
FileName = fileInfo.Content.FileName,
MimeType = fileInfo.Content.ContentType,
Size = fileInfo.Content.ContentLength,
Content = new byte[fileInfo.Content.ContentLength]//Image content to save
};
fileInfo.Content.InputStream.Read(file.Content, 0, fileInfo.Content.ContentLength);//Reading image content into ProductImage object
DocumentsManager.StorePendingDocuments.Add(file);
DocumentsManager.SaveTempDocuments();//Store each document uploaded to: TempDocument Table
TempData["SuccessMsg"] = "The image was saved successfully";
var json = new JavaScriptSerializer().Serialize(new { Success = true, StatusMessage = "El objeto fue insertado correctamente" });
return Content(json, "application/json");
}
catch (Exception exception)
{
TempData["ErrorMsg"] = exception.Message;
var json = new JavaScriptSerializer().Serialize(new { Success = false, StatusMessage = exception.Message });
return Content(json, "application/json");
}
}

Answer 1

Use return type of Action as ActionResult and use:
`return Json(new { Result = "Success" });`
So that on success you will get Json object containing result value.