I have a simple ASP MVC3 #Html.TextBox that I'm using to input search criteria. However, I need to append the value to the URL in an Ajax call as a query string. How would I go about this? Below is the HTML in the view:
<div class="editor-field">
#Html.TextBox("searchString")
<span onclick='GetCompName(searchString);'>
<input type="image" src="#Url.Content("~/Content/Images/Filter.bmp")" alt="Filter" />
</span>
</div>
And here is the Ajax
function GetCompName(searchString) {
var request = $.ajax({
type: 'POST',
url: 'http://quahildy01/OrganizationData.svc/AccountSet?$select=AccountId,Name,neu_UniqueId&$filter=startswith(Name,' + searchString + ')',
dataType: 'html',
success: function (data) {
alert(data);
},
error: function (data) {
alert("Unable to process your resquest at this time.");
}
});
}
I will also want to output the returned value into another text box. If anyone knows how to do that that would be really helpful as well. Thanks!
the basic problem with your code is the searchString in onclick='GetCompName(searchString); always gonna be literally "serchString", you must specified the parameter in base the value in the input, like this $('.searchbox').val()
keep your javascript unobstructive.
HTML code
<div class="editor-field">
#Html.TextBox("searchString", null, new { #class = "serachbox" })
<span class="searchbox-trigger">
<input type="image" src="#Url.Content("~/Content/Images/Filter.bmp")" alt="Filter" />
</span>
</div>
Set de handler for the event span click
$(document).ready(function() {
$('.searchbox-trigger').click(GetProgramDetails);
});
and your ajax request
function GetProgramDetails() {
var request = $.ajax({
type: 'POST',
url: 'http://quahildy01/OrganizationData.svc/AccountSet?$select=AccountId,Name,neu_UniqueId&$filter=startswith(Name,' + $('.searchbox').val() + ')',
dataType: 'html',
success: function (data) {
alert(data);
},
error: function (data) {
alert("Unable to process your resquest at this time.");
}
});
}
Related
I've done this dozens of times before and have been testing all morning, I must be missing something very obvious.
I have a form that submits data and if the data already exists, I just want to overwrite that form using a PartialView. I can debug the code and watch the POST get called and I even watch the PartialView reciev its model and data but the PartialView doesn't get rendered on the screen and my AJAX doesn't return anything to the console so I'm not sure how to Troubleshoot this.
My Controller
[HttpPost]
[Route("Send")]
public PartialViewResult Send([FromBody] InstantAlert InstantAlert)
{
string view = "~/views/shared/_InstantAlert_Exists.cshtml";
}
My View
<!-- Form -->
<div id="DivSubmitForm">
<partial name="~/views/home/_Partials/_SubmitForm.cshtml", model="Model" />
</div>
<!-- End Form -->
My Script
$(function () {
$(document).on("click", '#btnSubmit', function () {
if ($('form').valid()) {
Submit();
}
});
function Submit() {
//JSON data
var InstantAlert = {
url: $('#url').val(),
userId: $('#userId').val(),
institutionId: $('#institutionId').val()
}
var jsonToPost = JSON.stringify(InstantAlert);
$.ajax({
url: '/home/Send',
contentType: "application/json; charset=utf-8",
data: jsonToPost,
type: "POST",
success: function (result) {
console.log("Success");
//$('#DivSubmitForm').html(result);
},
error: function (xhr, ajaxOptions, thrownError) {
alert(xhr.status);
alert(thrownError);
}
});
}
});
PartialView
<div class="form-group">
<div class="alert alert-danger alert-dismissible" role="alert">
<strong>This article has already been submitted</strong>
<hr class="message-inner-separator">
<p>
test
</p>
</div>
</div>
Argh, so I discovered a form tag on my page which means the controller was inevitably always reloading my initial controller....
I'm populating a folder structure using TreeView in .cs file, rendering it in the view.cshtml. When an item is clicked, I call a js function which makes an ajax call to the web api, gets the file content and supposed to display the result in a TextArea or Div.
The result comes back from web api, and displays it in the textarea momentarily and disappears. I guess it's refreshing the page. But I'm not sure how to prevent it. I have done similar stuffs before, didn't behave so. I'm sure I'm missing something, but I can't tell what I'm missing.
#{
Layout = "~/Views/Shared/_Layout.cshtml";
}
<form>
<div style="width: 100%; overflow: hidden;">
<div style="width: 600px; float: left;">
<ul>
#foreach (var node in Model.Nodes[0].ChildNodes)
{
<li>#node.Text</li>
<ul>
#foreach (var f in node.ChildNodes)
{
<li>#f.Text</li>
}
</ul>
}
</ul>
</div>
<div id="divLog" style="margin-left: 620px;overflow:auto;"><textarea id="txtLog" rows="10" cols="50"></textarea></div>
</div>
</form>
<script>
function getLog(fileref) {
var baseURL = window.location.protocol + '//' + window.location.host + '#Url.Content("~")';
var apiUrl = baseURL + "/api/logapi?fileref=" + fileref;
document.getElementById("txtLog").innerText = "";
$(document).ready(function () {
$.ajax({
url: apiUrl,
type: "GET",
success: function (data, textStatus, jqXHR) {
document.getElementById("txtLog").innerText = data;
//document.getElementById("txtLog").innerHTML = data;
//$("#txtLog").val(data);
alert(data);
}
});
});
}
</script>
Maybe another solution for any people coming here. I had the same issue in my Razor pages project when trying to call an Ajax function from a form. The page would call the correct page handler and return the Json result, however the page would always refresh, and the success part in the ajax call would not be called. What worked FOR ME was to REMOVE the form element and replace it with a div. Now the Ajax call returns correctly for me.
<div id="first" class="section"> //WHEN THIS WAS FORM THE PAGE REFRESHED
<div class="section">
#Html.HiddenFor(m => m.PersonId)
#Html.HiddenFor(m => m.ProviderId)
#Html.AntiForgeryToken()
<div class="container2">
<input type="radio" name="group1" id="radio-1" checked="checked">
<label for="radio-1"><span style="font-size:16px;" class="radio">I want to recieve all Emails (personal and marketing)</span></label>
</div>
<button onclick="setPreferences()" class="btn btn-save">Save <i class="fa fa-save"></i></button>
</div>
</div>
And the ajax:
$.ajax({
url: '/UserPreferences?handler=SetPreferences',
type: 'POST',
contentType: "application/json; charset=utf-8",
dataType: "json",
data: JSON.stringify(model),
headers: {
RequestVerificationToken: $('input:hidden[name="__RequestVerificationToken"]').val()
},
success: function (response) {
console.log(response);
}
});
I used button instead of anchor link, it works as expected, it doesn't refresh the screen.
<style>
.btn1 {
background-color: transparent;
border: hidden;
}
</style>
<li><input type="button" id="a" value="#f.Text" onclick="getLog('#f.Value')" class="button btn1"></li>
First, remove the Ajax call from the document ready function:
function getLog(fileref) {
var baseURL = window.location.protocol + '//' + window.location.host + '#Url.Content("~")';
var apiUrl = baseURL + "/api/logapi?fileref=" + fileref;
document.getElementById("txtLog").innerText = "";
$.ajax({
url: apiUrl,
type: "GET",
success: function (data, textStatus, jqXHR) {
document.getElementById("txtLog").innerText = data;
//document.getElementById("txtLog").innerHTML = data;
//$("#txtLog").val(data);
alert(data);
}
});
}
Secondly, replace the empty href attribute of the anchor link by href="javascript:;" or href="#".
I have an ajax+jquery navigation system with $.ajax, and I`m trying to do a second call to $.ajax to send a contact form infos, but, when I add the second $.ajax all just stop working.
First Call -
function loadPage(url)
{
url=url.replace('#!','');
$('#loading').css('visibility','visible');
$.ajax({
type: "POST",
url: "loader.php",
data: 'page='+url,
dataType: "html",
success: function(msg){
if(parseInt(msg)!=0)
{
$('#conteudo').html(msg);
$('#loading').css('visibility','hidden');
}
}
});
}
Second Call
$("#enviar").click(function() {
var str = $("form").serializeArray();
$.ajax({
type: "POST",
url: "update.php",
data: str,
success: function(mn) {
if(parseInt(mn)!=0)
{
$("#conteudo").html(mn);
$("#enviado").css('visibility','visible');
}
}
return false;
});
#EDIT
Very good! The first ajax is not stucking anymore, but this second is not working as expected.
This is intended to parse $_POST values to a php script and if ok just turn div visible..
How I`m doing that -
<form name="formcontato" id="form">
<fieldset>
<label>Seu nome</label>
<input type="text" name="nome" class="input-block-level">
<label>Email</label>
<input type="email" name="email" placeholder="seu#email.com" class="input-block-level">
<div class="form-actions">
<input type="button" name="enviar" value="Enviar" id="enviar" class="btn btn-baixar" />
</div>
</fieldset>
</form>
This is the form.
$("#enviar").click(function () {
var str = $("#form").serialize();
$.ajax({
type: "POST",
url: "update.php",
data: str,
success: function (mn) {
alert("Ok!");
if (parseInt(mn) != 0) {
$("#conteudo").html(mn);
$("#enviado").css('visibility', 'visible');
}
}
});
return false;
});
This is the js
if($_POST) {
$nome = trim($_POST['nome']);
echo $nome;
}
This is the update.php
In what you posted, the second function does not properly close the $.ajax() function with a }); so it would generate a parse error and none of the code in this block would be available.
Try this where the $.ajax() call is succesfully closed.
$("#enviar").click(function () {
var str = $("form").serializeArray();
$.ajax({
type: "POST",
url: "update.php",
data: str,
success: function (mn) {
if (parseInt(mn) != 0) {
$("#conteudo").html(mn);
$("#enviado").css('visibility', 'visible');
}
}
});
return false;
});
FYI, proper and consistent indentation is essential to spotting these issues.
I have a form in my view page.it contains 5 text boxes,one search button.while the user enters values in textbox(Entering all fields are not mandatory)and click on the search button,the values I have to store it in an array and pass it to the controller and depending upon the search results i have to display the results of those searched records.
I am able to store the searched values in an array,now i want how to pass this array to the controller and how to access these values in the controller.
as Jose referred , your request may look like this :
$("#submit").click(function () {
var searchData = new Array();
$(".search-input").each(function () {
searchData.push($(this).attr('value'));
});
$.ajax({
type: "POST",
url: "/Home/Index",
data: {"searchData" : searchData},
success: function (data) {
// do something on success
},
traditional: true,
dataType: "json"
});
return false;
});
and your controller action could be :
[AcceptVerbs(HttpVerbs.Post)]
public ActionResult Index([Bind(Prefix="searchData")] List<string> searchData)
{
return Index();
}
and your form have to have markup like this:
<form id="myform">
<input type="text" class='search-input' />
<input type="text" class='search-input' />
<input type="text" class='search-input' />
<input type="text" class='search-input' />
<input type="submit" id="submit" />
</form>
Use ajax. If jQuery is an option you could write something like this
$(form).submit(function()
{
var ;
$.ajax({
type: "POST",
url: "/Controller/Action",
data: JSON.stringify(_yourArrayObject),
success: function(data){
alert(data.Result);
},
dataType: "json"
});
})
I have a site i'm working on and i'm trying to make an ajax request to a controller (codeigniter framework). I see in firebug that my controller is receiving my post value just fine but for some reason it is not sending back a response. I've set it up to be VERY simple without a database call at this point just for testing and its still not working. Any ideas?
Here is my form in my view:
<div class="purchaseState">
<input type="text" name="city" id="city" class="grayGrad"/>
</div>
<div>
<ul id="cityResults">
<!-- AJAX results here -->
</ul>
</div>
Here is my controller returning the value:
function citySearch() {
echo '<li>test</li>';
}
Here is my Jquery ajax
//New City Search
$('#city').keyup( function() {
var city = $('#city').val();
$.ajax({
type: "POST",
url: "page/citySearch",
data: { city: city },
}).done(function( data ) {
$('ul#cityResults').append(data);
});
});
you should use ajax success callback:
$('#city').keyup(function() {
var city = $('#city').val();
$.ajax({
type: "POST",
url: "page/citySearch",
data: { city: city },
success: function(data) {
$('ul#cityResults').append(data);
}
});
});
Please change the url in the AJAX function in the following way.
$('#city').keyup(function() {
var city = $('#city').val();
$.ajax({
type: "POST",
url: "<?php echo base_url; ?>page/citySearch",
data: { city: city },
success: function(data) {
$('ul#cityResults').append(data);
}
});
});