TbJsonGridView + TbJsonCheckBoxColumn - how call action for multi rows? (screen) - ajax

Question

I have situation like on this screen:
I have column where user check rows. After that user can call some actions like example delete data.
To show menu with multi actions for users i use button dropdown in yii-booster TbButtonGroup. I tried all possible buttonType and all doesnt work.
All what i need is send information about what rows are selected, do some action inside controller and after that reload grid. I dont have any idea how...
To generate button dropdown i use code:
Yii::app()->controller->widget('bootstrap.widgets.TbButtonGroup', array(
'size'=>'mini',
'type'=>'link',
'buttons'=>array(
array('icon'=>'edit', 'items'=>$this->filter),
),
));
To generate grid i use code:
$this->widget('bootstrap.widgets.TbJsonGridView', array(
'dataProvider' => $model->search(),
'filter' => $model,
'type' => 'striped condensed',
'summaryText' => false,
'cacheTTL' => 10, // cache will be stored 10 seconds (see cacheTTLType)
'cacheTTLType' => 's', // type can be of seconds, minutes or hours
'selectableRows'=>2,
'columns' => array(
array(
'class'=>'ext._TbJsonCheckBoxColumn._TbJsonCheckBoxColumn',
'id'=>'selectedTickets',
'filter'=>array(
array('label'=>'close', 'url'=>'javascript:'.CHtml::ajax(array('type'=>'POST', 'url'=>array('','multi_action'=>'close'), 'success'=>'function(data, status){ console.log(data); console.log(status); }', 'error'=>"function(data, status){ console.log(data); console.log(status); }")) ),
array('label'=>'Another action', 'url'=>'#'),
array('label'=>'Something else', 'url'=>'#'),
'---',
array('label'=>'Separate link', 'url'=>'#'),
),
),
'id',
'email_from',
'subject',
'status',
array(
'name'=>'last_update',
'value'=>'$data->last_update_from_now',
//'filter'=>false,
),
array(
'header' => Yii::t('ses', 'Edit'),
'class' => 'bootstrap.widgets.TbJsonButtonColumn',
'template' => '{view} {update} {delete}',
),
),
));
To generate form i use code:
$this->widget('bootstrap.widgets.TbButton',array(
'label' => 'Add new ticket',
'type' => 'primary',
'size' => 'medium',
'url' => $this->createUrl('create'),
));
<?php
$form = $this->beginWidget('bootstrap.widgets.TbActiveForm', array(
'id'=>'tickets',
'type'=>'horizontal',
'enableAjaxValidation'=>true,
));
echo $this->renderPartial('_grid', array('model'=>$model));
echo CHtml::ajaxSubmitButton('Activate',array('menu/ajaxupdate','act'=>'doActive'), array('success'=>'reloadGrid'));
$this->endWidget();

Answer 1

After many spent hours i wrote something like that and it solved my problem:
Yii::app()->clientScript->registerScript('multi_button', "
$('[data-multi=action]').delegate('li a', 'click', function(event){
event.preventDefault();
var th = $(this),
action = th.attr('href').substr(1);
if( action=='delete' && !confirm('Are you sure you want to delete selected items?') ) return true;
".
CHtml::ajax(array(
'type'=>'POST',
'data'=>'js:th.closest("form").serialize()',
'url'=>'js:location.href+(/\?/.test(location.href) ? "&" : "?")+"multi_action="+action',
'success'=>'function(data, status){ th.closest("div.grid-view").yiiJsonGridView("update"); }',
'error'=>'function(data, status){ alert(status); }',
'cache'=>false
))."
});
");