when i post a raw string as an input to JSON REST Service call it is executing ex:
curl -d "{\"input1\": \"as\", \"input2\": \"ad\"}" -i -X POST -H "Content-Type:application/json" http://localhost/rtygies/Service1.svc/rest/receivedata1
But when i am posting as an xml as input it is giveng error as below:
curl -d "{\"input1\": \"<xml></xml>\", \"input2\": \"<xml></xml>\"}" -i -X POST -H "Content-Type:application/json" http://localhost/rtygies/Service1.svc/rest/receivedata1
Error: < was unexpected at this time
I am using curl in windows.
can any one say how to post xml as a string input to Rest service in JSON format from curl
Actually, I don't know what is the case,
but I got an error said < is unexpected this time
when I tried the following command (on windows):
curl -u admin:password -XPOST -H 'Content-type: text/xml' -d '<namespace><prefix>newWorkspace</prefix><uri>http://geoserver.org</uri></namespace>' http://localhost:8080/geoserver/rest/namespaces
Then I changed the single quote into double quotes and it worked.
Redirection symbols can be escaped by "
Try using
curl -d "{\"input1\": \""<xml></xml>"\", \"input2\": \""<xml></xml>"\"}" -i -X POST -H "Content-Type:application/json" http://localhost/rtygies/Service1.svc/rest/receivedata1
I had no luck with double-quotes, however escaping < and > with ^ worked for me.
So your curl becomes..
curl -d "{\"input1\": \"^<xml^>^</xml^>\", \"input2\": \"^<xml^>^</xml^>\"}" -i -X POST -H "Content-Type:application/json" http://localhost/rtygies/Service1.svc/rest/receivedata1
Related
I looked at all previous answers on this subject but just can't get my POST request to work in cURL windows although it works perfectly in PostMan. I exported the code using </> and tried several combinations of export parameters... any help would greatly appreciated!
Here's my cURL code:
curl -L -X POST "https://timingserver.net/api/bridge/generic" -H "cache-control: no-cache" -H "connection: close" -H "content-type: application/json" --data-raw "{
\"username\":\"myusername\",
\"password\":\"mypassword\",
\"event\":\"demo\",
\"checkpoint\":12,
\"detections\":[{\"bib\":100, \"dt\":\"2022-01-12T13:09:23.045\"},
{\"bib\":101, \"dt\":\"2022-01-12T13:09:23.045\"},
{\"bib\":102, \"dt\":\"2022-01-12T13:09:23.045\"},
{\"bib\":199, \"dt\":\"2022-01-12T13:10:23.045\"}]
}"
Getting several errors in the same execution: Code 400, not recognized as an internal or external command... cannot find the path specified...
You need to remove the linebreaks:
curl -L -X POST "https://timingserver.net/api/bridge/generic" -H "cache-control: no-cache" -H "connection: close" -H "content-type: application/json" --data-raw "{ \"username\":\"myusername\", \"password\":\"mypassword\", \"event\":\"demo\", \"checkpoint\":12, \"detections\":[{\"bib\":100, \"dt\":\"2022-01-12T13:09:23.045\"}, {\"bib\":101, \"dt\":\"2022-01-12T13:09:23.045\"}, {\"bib\":102, \"dt\":\"2022-01-12T13:09:23.045\"}, {\"bib\":199, \"dt\":\"2022-01-12T13:10:23.045\"}] }"
To generate curl output for windows using postman click on settings next to curl code section and change line continuation character to ^ and quote double and shown in the image. This should generate output for windows. You can also change the output to single or multiline.
I am very new to bash scripting, please can someone point me in the right direction on how to accomplish my task?
I have a curl call which returns a string, which I want to convert to json.
My curl statement -
curl --insecure -X POST 'https://url/api/IPAM/GetIP' --header 'Content-Type: application/json' --header -d '{"key1": "value1"}'
This curl statement returns a string ,for example: 10.100.100.100
I want to fetch this string and return the output in json format:
{"IP":"10.100.100.100"}
I don't want to use jquery or python to do this because this entire script will be run by a wrapper that only understands bash.
You can use jq to process your IP string into a JSON string and package it into a JSON object of your choice.
ip="10.100.100.100"
jq --arg ip "$ip" -cn '{"IP":$ip}'
Result:
{"IP":"10.100.100.100"}
Now if working with the result of your example curl POST request:
rawip_string=$(curl --insecure -X POST 'https://url/api/IPAM/GetIP' --header 'Content-Type: application/json' --header -d '{"key1": "value1"}')
jq --arg ip "$rawip_string" -cn '{"IP":$ip}'
One way to not rely on external tools like jq, you can get the output ip attribute that to a variable and concatenate it.
$ return=$(echo 10.100.100.100)
$ echo "{\"IP\":\"${return}\"}"
{"IP":"10.100.100.100"}
Like this
printf '{"IP":"%s"}' "$(curl --insecure -X POST 'https://url/api/IPAM/GetIP' --header 'Content-Type: application/json' --header -d '{"key1": "value1"}')"
I 'd like to post directly a json object from a url(json) to another url
so the command goes as follows:
curl "<resource_link>.json" -o sample.json
curl -X POST "<my_link>" "Content-type: application/json" -d #sample.json
I 'd like to avoid this, so what is the solution? Is it something like that?
curl -X POST "<my_link>" "Content-type: application/json" -d "curl <resource_link>.json"
But it does not work? Also, this one post Stream cURL response to another cURL command posting the result
does not explain thouroughly and it is not working
Yes,
curl
manual explains the '#' but it does not explain about using another curl
Alternatievely, if I could save somewhere temporarily the 1st cURL response and use it in the other command(but not in a file)
You don't want -x POST in there so let's start with dropping that.
Send the results from the first transfer to stdout by not using -o, or telling -o to use stdout with -o-, and
Make sure your second transfer accepts the data to send on stdin, by using -d#-.
curl "<link>.json" | curl "<link2>" -H "Content-type: application/json" -d #-
With curl 7.82.0 and later
Starting with curl 7.82.0 you can do it even easier with the new --json option:
curl "<link>.json" | curl "<link2>" --json #-
I want to create a script to test some web service.
Here the base of my script:
XAuthToken=$(curl -i -s -X POST -H "Content-Type: application/json" -d '{"login": "apitest","password": "apitest"}' http://url:8080/rest-api-web/api/admin | grep -i '^X-Auth-Token:' | sed 's/^[Xx]-Auth-Token: //g')
curl -X GET --header 'Accept: application/json' http://url:8080/rest-api-web/api/admin/delivery_companies?token=$XAuthToken
Result of the first command is:
eyJjdHkiOiJKV1QiLCJlbmMiOiJBMTI4R0NNIiwiYWxnIjoiUlNBLU9BRVAifQ.KmhGpDsor4I7VVPfN1gENzcQb8Yll-wewTRorFu6qfUeaIjKNIAm5lkTkPIpuuOuSpT2U4RgXz9NhwLrYIheW45Du6LnjsyUEjjWGKB4jIW0CMO-79f_-O80pQMq0P09uwmZaqUOmARPjs8UvQYQcuCHhcHd2dB-4WMnfUl-J6USI2LdI-CeOtWDDMw5YEKHGrgnHRzxgUePNWVs-Vc-BR-tXnpkEjIfKmrYy19QUfnwxcWLEWgKisrJw5d7sz7ihfzSueyrh188GiGHTeqqiNiSIkIH8UEyZfW-5BH1Y856IkXlyUaC3abHBRYHuz-O30KwvCKhtCKkaTPVR-uqNw.89jCGtawkkWuyRtq.pQmYHaWZN-XOlbvUthjK76ewqIGd1TBF0Pt7EbA2bDnxsTsXQXyot495-u4Rsvm8-y-rscAZUZFacebMvcvZ-LhUH-jHZH6L5PALY7uvGj_SGApg_Hu8D-adNDlI1rVxNcnHjpOLuOeBdUzKAznbOytquzQNODsjP877IbLTDkWTTj0IC0OWfDu-e4rYxpf2jzZBuEbnRcC8DuvbplNB2tnbRxMjpqnKjicLY9DpYdV1T-tKUt5-sI0Bhlk6tUJ0e28g1McQReUT-sB8pO3vQreEAEsVQlysVq9rC6LiW6RNRHAZP7d6PiuhLS_D_DKVmi85junbMVimYqbvszaJ.1b7PKcZfWmVmNBbTg54nFA
But the second curl in the script, this error occurs: curl: (3) Illegal characters found in URL
And after a check, the content of "XAuthToken" is changed.
Can you help me to escape the character modification?
Thanks you for your comment.
As you can see in the following output, both declare are egal. But the oupt of the command with set -x activate, the Authtoken is changed.
Here the result :
First delare -p :
eyJjdHkiOiJKV1QiLCJlbmMiOiJBMTI4R0NNIiwiYWxnIjoiUlNBLU9BRVAifQ.BTri-oCE-DHYx7UZo8Kib_RoO5bx9lv7BRhEYv2yizyX2n8cwzWWhMPPA-0rDHumaESgc0LmT71NLIJEyZkwN-pXH2MgYdo2vTQhnVdFOL7rZq1rHSJvUxPvhJTbAkabnTNz-s1-Vc7WNQXmWEkngaCISdnsFQU12YfJfzhgwGZi9OOf5gmHnNtXaAxTOrDcjl84s1QI0tY5HIQ_3MEB18V4UMfcR5SSk4v_5K2yVZk-AUys3bPDw1GEZkr3rypxytNZ6wCyrOEXtGh1s8w3fFQziNnnOcgwaSkpDOdhhJWUfgN3R1Cr5tnD77vG01SZw7k844LZxiK8HXhQUj3_sQ.KAhqX5YkZPXDtVlI.d-TxeoNsuemKRfDpQe9khaYym1KACAXS9MhYfGtoIwhPomZ85hKvILeT8jXxBgIw6r4XUpgSSVNtjUzA7A-_hpu0i7ffd-Ap-YDohbCfJfCYffVO557tCuIhVvybT4qQ5EgjsX8h1V5NqIyDVIPAiDIc6hnrxWsjbwE3dmfMLxqmDLXLiYTaCUMvsxtweo-fsdIymK-REuy4DdPk8YsaITpfYj57Ee5ZphZiNfvUPixkLAXj97ycEnXbP2d6q6Aw1rYVIrE3ijGYIgW618kMs5PBvjWe"yh-76mOq9_0QnKzblZWJytHsM6DM8kbkGRHhwFhQSvjq9HUQVNmmKCI.Q4rq7-uzPW3Yewc8Wyl01A
Resut of "set -x' :
eyJjdHkiOiJKV1QiLCJlbmMiOiJBMTI4R0NNIiwiYWxnIjoiUlNBLU9BRVAifQ.BTri-oCE-DHYx7UZo8Kib_RoO5bx9lv7BRhEYv2yizyX2n8cwzWWhMPPA-0rDHumaESgc0LmT71NLIJEyZkwN-pXH2MgYdo2vTQhnVdFOL7rZq1rHSJvUxPvhJTbAkabnTNz-s1-Vc7WNQXmWEkngaCISdnsFQU12YfJfzhgwGZi9OOf5gmHnNtXaAxTOrDcjl84s1QI0tY5HIQ_3MEB18V4UMfcR5SSk4v_5K2yVZk-AUys3bPDw1GEZkr3rypxytNZ6wCyrOEXtGh1s8w3fFQziNnnOcgwaSkpDOdhhJWUfgN3R1Cr5tnD77vG01SZw7k844LZxiK8HXhQUj3_sQ.KAhqX5YkZPXDtVlI.d-TxeoNsuemKRfDpQe9khaYym1KACAXS9MhYfGtoIwhPomZ85hKvILeT8jXxBgIw6r4XUpgSSVNtjUzA7A-_hpu0i7ffd-Ap-YDohbCfJfCYffVO557tCuIhVvybT4qQ5EgjsX8h1V5NqIyDVIPAiDIc6hnrxWsjbwE3dmfMLxqmDLXLiYTaCUMvsxtweo-fsdIymK-REuy4DdPk8YsaITpfYj57Ee5ZphZiNfvUPixkLAXj97ycEnXbP2d6q6Aw1rYVIrE3ijGYIgW618kMs5PBvjWeTyh-76mOq9_0QnKzblZWJyt'sM6DM8kbkGRHhwFhQSvjq9HUQVNmmKCI.Q4rq7-uzPW3Yewc8Wyl01A
Second declare :
eyJjdHkiOiJKV1QiLCJlbmMiOiJBMTI4R0NNIiwiYWxnIjoiUlNBLU9BRVAifQ.BTri-oCE-DHYx7UZo8Kib_RoO5bx9lv7BRhEYv2yizyX2n8cwzWWhMPPA-0rDHumaESgc0LmT71NLIJEyZkwN-pXH2MgYdo2vTQhnVdFOL7rZq1rHSJvUxPvhJTbAkabnTNz-s1-Vc7WNQXmWEkngaCISdnsFQU12YfJfzhgwGZi9OOf5gmHnNtXaAxTOrDcjl84s1QI0tY5HIQ_3MEB18V4UMfcR5SSk4v_5K2yVZk-AUys3bPDw1GEZkr3rypxytNZ6wCyrOEXtGh1s8w3fFQziNnnOcgwaSkpDOdhhJWUfgN3R1Cr5tnD77vG01SZw7k844LZxiK8HXhQUj3_sQ.KAhqX5YkZPXDtVlI.d-TxeoNsuemKRfDpQe9khaYym1KACAXS9MhYfGtoIwhPomZ85hKvILeT8jXxBgIw6r4XUpgSSVNtjUzA7A-_hpu0i7ffd-Ap-YDohbCfJfCYffVO557tCuIhVvybT4qQ5EgjsX8h1V5NqIyDVIPAiDIc6hnrxWsjbwE3dmfMLxqmDLXLiYTaCUMvsxtweo-fsdIymK-REuy4DdPk8YsaITpfYj57Ee5ZphZiNfvUPixkLAXj97ycEnXbP2d6q6Aw1rYVIrE3ijGYIgW618kMs5PBvjWe"yh-76mOq9_0QnKzblZWJytHsM6DM8kbkGRHhwFhQSvjq9HUQVNmmKCI.Q4rq7-uzPW3Yewc8Wyl01A
I am using below code to Post a curl command. But it is not taking any space or line-break as message input.
I tried with %20 and other answers that is already in SO regarding this problem. None is working. It is giving error as
"$error":"Unexpected end-of-input: was expecting closing quote for a string value\n
line="abc def"
curl --user "USER":"Password" -H "Content-Type: application/json" -X POST -d '{"message":"'${line}'"}}' --url http://${host}:${port}${REST_URL}
There is a an unnecessary extra close brace } for your data segment. Also, the variables in the middle of the data argument should be quoted. Also double-quote your --url string to prevent word-splitting by the shell.
curl --user "USER":"Password" \
-H "Content-Type: application/json" \
-X POST -d '{"message":"'"${line}"'"}' \
--url "http://${host}:${port}${REST_URL}"