Shell script do timed task stop and repeat? - bash

I am working with programs that use CTRL-C to stop a task, and what I want to do is to run that task for certain number of minutes and then have it stop like CTRL-C was pressed. The reason why I want it to stop like ctrl+c was pressed is because it auto saves when you stop the program instead of killing it and possibly losing the saved data.
edit; I don't want to use cron unless if it stops my script it will have the program save the data, I am hoping to accomplish this inside the shell script.

The trap statement catches these sequences and can be programmed to execute a list of commands upon catching those signals.
-#!/bin/bash
trap "echo Saving Data" SIGINT
while :
do
sleep 60
done
For Information on Traps : http://tldp.org/LDP/Bash-Beginners-Guide/html/sect_12_02.html

Using timeout command to send SIGINT after 60 seconds:
timeout --signal=INT 60 /path/to/script.sh params

If you need to intercept ctrl+c, you should use the trap builtin, like this :
cleanup(){ # do something...; }
trap 'cleanup' 2
# rest of the code
2 on trap line is the SIGINT signal sended by ctrl+c, see man 7 signals

Try the following:
#!/bin/bash
set -m
/path/to/script.sh params &
set +m
bg_pid=$!
sleep 60
kill -2 $bg_pid
This should allow you to send SIGINT to a backgrounded process using Job Control and the set builtin

Related

How can I send a signal without the shell waiting for the currently running program to finish?

If I send a signal using kill, it seems to wait until the current program (in this example sleep 1000) finishes running. When I instead send SIGINT via pressing Ctrl+C in the shell, it receives the interrupt immediately however.
What I want, however, is for the interrupt to be received immediately after sending the signal via kill. Also, why does it behave like I would want it to when I press Ctrl+C?
#!/usr/bin/env sh
int_after_a_while() {
local pid=$1
sleep 2
echo "Attempting to kill $pid with SIGINT"
# Here I want to kill the process immediately, but it waits until sleep finishes
kill -s INT $pid
}
trap "echo Interrupt received!" INT
int_after_a_while $$ &
sleep 1000
I would appreciate any help on this issue. Thanks in advance!
As noted in the referenced answer https://unix.stackexchange.com/questions/282525/why-did-my-trap-not-trigger/282631#282631 the shell will normally wait for a utility to complete before running a trap. Some alternatives are:
Start the long running process in the background, then wait for it using the wait builtin. When a trapped signal is received during such a wait, the wait is interrupted and the trap is taken. Unfortunately, the exit status of wait does not distinguish between the child process exiting on a signal and a trap occurring. For example
sleep 1000 &
p=$!
wait "$p"
Send a signal to the whole process group via kill -s INT 0. The effect is much like if the user had pressed Ctrl+C, but may be more extreme than you want if your script is run from another script.
Use a shell such as zsh or FreeBSD sh that supports set -o trapsasync which allows running traps while waiting for a foreground job.

stop currently running bash script lazily/gracefully

Say I have a bash script like this:
#!/bin/bash
exec-program zero
exec-program one
the script issued a run command to exec-program with the arg "zero", right? say, for instance, the first line is currently running. I know that Ctrl-C will halt the process and discontinue executing the remainder of the script.
Instead, is there a keypress that will allow the current-line to finish executing and then discontinue the script execution (not execute "exec-program one") (without modifying the script directly)? In this example it would continue running "exec-program zero" but after would return to the shell rather than immediately halting "exec-program zero"
TL;DR Something runtime similar to "Ctrl-C" but more lazy/graceful ??
In the man page, under SIGNALS section it reads:
If bash is waiting for a command to complete and receives a signal for which a trap has been set, the trap will not be executed until the command completes.
This is exactly what you're asking for. You need to set an exit trap for SIGINT, then run exec-program in a subshell where SIGINT is ignored; so that it'll inherit the SIG_IGN handler and Ctrl+C won't kill it. Below is an implementation of this concept.
#!/bin/bash -
trap exit INT
foo() (
trap '' INT
exec "$#"
)
foo sleep 5
echo alive
If you hit Ctrl+C while sleep 5 is running, bash will wait for it to complete and then exit; you will not see alive on the terminal.
exec is for avoiding another fork() btw.

How to send custom signal to bash daemon process?

I have simple bash daemon running (with root privileges ) in background which suppose to do action1 or/and action2 when notified.
How do I notify it/send some kind of signal on which it will react?
I've tried scenarios with checking file change every 1 sec or more often, but that's kind of less-desirable solution.
You can send signals to a process using the kill command. There is a range of standard signals as well as two user defined signals, which you can let your script handle whichever way you prefer. Here is how this could look in a script
#!/bin/bash
handler(){
echo "Handler was called"
}
trap handler USR1
while sleep 1
do
date
done
To send a signal to the script you first need to find the pid of the script and then use the kill command. It could look like this kill -USR1 24962.
You can use the kill command to send a process a signal. In bash, you can use the trap command to create a signal handler.
#!/bin/bash
# traptest.sh
trap "echo Booh!" SIGINT SIGTERM
echo "pid is $$"
while : # This is the same as "while true".
do
sleep 60 # This script is not really doing anything.
done

How does trap / kill work in bash on Linux?

My sample file
traptest.sh:
#!/bin/bash
trap 'echo trapped' TERM
while :
do
sleep 1000
done
$ traptest.sh &
[1] 4280
$ kill %1 <-- kill by job number works
Terminated
trapped
$ traptest.sh &
[1] 4280
$ kill 4280 <-- kill by process id doesn't work?
(sound of crickets, process isn't killed)
If I remove the trap statement completely, kill process-id works again?
Running some RHEL 2.6.18-194.11.4.el5 at work. I am really confused by this behaviour, is it right?
kill [pid]
send the TERM signal exclusively to the specified PID.
kill %1
send the TERM signal to the job #1's entire process group, in this case to the script pid + his children (sleep).
I've verified that with strace on sleep process and on script process
Anyway, someone got a similar problem here (but with SIGINT instead of SIGTERM): http://www.vidarholen.net/contents/blog/?p=34.
Quoting the most important sentence:
kill -INT %1 sends the signal to the job’s process group, not the backgrounded pid!
This is expected behavior. Default signal sent by kill is SIGTERM, which you are catching by your trap. Consider this:
#!/bin/bash
# traptest.sh
trap "echo Booh!" SIGINT SIGTERM
echo "pid is $$"
while : # This is the same as "while true".
do
a=1
done
(sleep really creates a new process and the behavior is clearer with my example I guess).
So if you run traptest.sh in one terminal and kill TRAPTEST_PROCESS_ID from another terminal, output in the terminal running traptest will be Booh! as expected (and the process will NOT be killed). If you try sending kill -s HUP TRAPTEST_PROCESS_ID, it will kill the traptest process.
This should clear up the %1 confusion.
Note: the code example is taken from tldp
Davide Berra explained the difference between kill %<jobspec> and kill <PID>, but not how that difference results in what you observed. After all, Unix signal handlers should be called pretty much instantaneously, so why does sending a SIGTERM to the script alone not trigger its trap handler?
The bash man page explains why, in the last paragraph of the SIGNALS section:
If bash is waiting for a command to complete and receives a signal for
which a trap has been set, the trap will not be executed until the
command completes.
So, the signal was delivered immediately, but the handler execution was deferred until sleep exited.
Hence, with kill %<jobspec>:
Both the script and sleep received SIGTERM
bash registered the signal, noticed that a trap was set for it, and queued the handler for future execution
sleep exited immediately
bash noted sleep's exit, and ran the trap handler
whereas with kill <script_PID>:
Only the script received SIGTERM
bash registered the signal, noticed that a trap was set for it, and queued the handler for future execution
sleep exited after 1000 seconds
bash noted sleep's exit, and ran the trap handler
Obviously, you didn't want long enough to see that last bit. :)
If you're interested in the gory details, download the bash source code and look in trap.c, specifically the trap_handler() and run_pending_traps() functions.

Run command when bash script is stopped

How can i, in a bash script, execute a command when the user stops the script (with ctrl - c)?
Currently, i have this:
afplay file.mp3
while true:
do osascript -e "set volume 10"
end
But i would like it to execute killall afplay when the user is finished with it, regardless if it is command-c or another keypress.
trap 'killall afplay' EXIT
Use trap.
trap "kill $pid" INT TERM EXIT
Also avoid killall or pkill, since it could kill unrelated processes (for instance, from another instance of your script, or even a different script). Instead, put the player's PID in a variable and kill only that PID.
You need to put a trap statement in your bash script:
trap 'killall afplay' EXIT
Note however that this won't work if the bash process is sent a KILL signal (9) as it's not possible for processes to intercept that signal.

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