I've just been writing some code, that renders a locale property redundant. Because of that, I'd like it to be able to remove that property from every locale file of the project, but I simply couldn't find a way of doing that, and I ended up doing it by hand in vim.
Now, I'm no UNIX black-belt, but I know that there must be a pretty simple solution to such a trivial problem, probably hidden in the depths of sed or awk. So I managed to match the property (the property being no_outline):
sed -e '/no_outline=/d' l10n/*/viewer.properties
But this only prints out the contents of each file, without the no_outline line. Isn't it possible to write the "result" of the sed command to the same file as it was executed on?
you could:
sed -i '/no_outline=/d' l10n/*/viewer.properties
from man page:
-i[SUFFIX], --in-place[=SUFFIX]
edit files in place (makes backup if SUFFIX supplied)
Related
I am trying to use a list that looks like this:
List file:
1mAF
2mAF
4mAF
7mAF
9mAF
10mAF
11mAF
13mAF
18mAF
27mAF
33mAF
36mAF
37mAF
38mAF
39mAF
40mAF
41mAF
45mAF
46mAF
47mAF
49mAF
57mAF
58mAF
60mAF
61mAF
62mAF
63mAF
64mAF
67mAF
82mAF
86mAF
87mAF
95mAF
96mAF
to grab out lines that contain a word-level match in a tab delimited file that looks like this:
File_of_interest:
11mAF-NODE_111-g7687-JEFF-tig00000037_arrow-g7396-AFLA_058530 11mAF cluster63
17mAF-NODE_343-g9350 17mAF cluster07
18mAF-NODE_34-g3647-JEFF-tig00000037_arrow-g7396-AFLA_058530 18mAF cluster20
22mAF-NODE_36-g3735 22mAF cluster28
36mAF-NODE_107-g7427 36mAF cluster77
45mAF-NODE_151-g9067 45mAF cluster14
47mAF-NODE_30-g3242-JEFF-tig00000037_arrow-g7396-AFLA_058530 47mAF cluster21
67mAF-NODE_54-g4372 67mAF cluster06
69mAF-NODE_27-g2754 69mAF cluster39
71mAF-NODE_44-g4178 71mAF cluster25
73mAF-NODE_47-g4895 73mAF cluster57
78mAF-NODE_4-g688 78mAF cluster53
but when I do grep -w -f list file_of_interest these are the only ones I get:
18mAF-NODE_34-g3647-JEFF-tig00000037_arrow-g7396-AFLA_058530 18mAF cluster20
36mAF-NODE_107-g7427 36mAF cluster77
45mAF-NODE_151-g9067 45mAF cluster14
and this misses a bunch of the values that are in the original list for example note that "67mAF" is in the list and in the file but it isn't returned.
I have tried removing everything after "mAF" in the list and trying again -- no change. I have rewritten the list in a completely new file to no avail. Oddly, I get more of them if I "sort" the list into a new file and then do the grep, but I still don't get all of them. I have also removed all invisible characters using sed (sed $'s/[^[:print:]\t]//g'). no change.
I am on OSX and both files were created on OSX, but normally grep -f -w works in the fashion i'm describing above.
I am completely flummoxed. Is I thought grep -w -f would look for all word-level matches of items in the file in the target file... am I wrong?
Thanks!
My guess is at least one of these files originates from a Windows machine and has CRLF line endings. file(1) might be used to tell you. If that is the case do:
fromdos FILE
or, alternatively:
dos2unix FILE
This question already has answers here:
Editing/Replacing content in multiple files in Unix AIX without opening it
(2 answers)
Closed 6 years ago.
I wonder know if there is a way to edit a conf file without getting in the file and changing the lines?
In my case, I need to edit zabbix-agent conf file (located in /etc/zabbix/zabbix_agentd.conf) and there are some parameters in the file that I need to change, such as Server Name, DebugLevel, and others.
Normally I edit the file using vim and change the lines, but my idea is to edit the file directly from bash, but I don`t know if this is possible.
For example, if I need to change the parameter DebugLevel, at bash I would run:
# /etc/zabbix/zabbix_agentd.conf.DebugLevel=3
This actually doesn`t works, but I would like something like this for my problem...
Does anyone knows??
I tested what David said, but it didn`t solved my problem... There are some lines in the file that is commented and I need to uncomment them, and there are some lines that I just need to change.
For example, the line above:
# DebugLevel=3
I need to change to:
DebugLevel=3
And this line:
Server=127.0.0.1
I need to change for the IP of zabbix server name, like this:
Server=172.217.28.142
Is there any other way?
If I understand your question correctly, then you want sed -i (the -i option allows sed to edit the file in place, and -i.bak will do the same but create a backup of the original file with the .bak extension)
To change DebugLevel=3 to DebugLevel=4 in file /etc/zabbix/zabbix_agentd.conf, you can do:
# sed -i.bak "/DebugLevel/s/[0-9][0-9]*$/4/" /etc/zabbix/zabbix_agentd.conf
If I misinterpreted your question, please let me know.
To Change Values at the End
Example Input File
$ cat file.txt
DebugLevel=3
Example Use
$ sed -i "/DebugLevel/s/[0-9][0-9]*$/4/" file.txt
$ cat file.txt
DebugLevel=4
To Remove Comments
You can do virtually the same thing to uncomment the parameters of interest, for example:
# sed -i.bak "/DebugLevel/s/^#//" /etc/zabbix/zabbix_agentd.conf
In each case, sed is searching for the label in the first set of forward slashes /.../, next the substitute command is called s and then the expression between the next set of forward slashes, e.g. /^#/ (^ match at the beginning), if matched, is replaced by what follows in the next set // (nothing in the remove comment case).
You will need to adjust the values as required to match each parameter you need to find and replace. Let me know if you have further problems and exactly what the problem is.
I'm trying to remove an ID number from a text file using a series of commands (using terminal), but they don't seem to be working. I need to remove the number and the associated "ID" text
Text in File:
{"id":"098765432"}
Commands I've been using (but don't seem to be working):
sed -i.bak 's/"id":[0-9]\{1,\},//g' ./Filename.txt
sed -i.bak 's/"id":"[0-9]\{1,\}",//g' ./Filename.txt
sed -i.bak 's/"id":"[0-9]\{9,\}",//g' ./Filename.txt
sed -i.bak 's/"id":[0-9]\{9,\},//g' ./Filename.txt
sed -i.bak 's/"[0-9]\{1,\}",//g' ./Filename.txt
Thanks for the help :)
As #Wintermute already noted in the comment, the problem is in the comma before //. However, I am going to explain the whole line, just so the others may understand it completely, in case something is not clear to those who come across this question later.
So, the proper command that will satisfy your requirement is:
sed -i.bak 's/"id":"[0-9]\{1,\}"//g' ./Filename.txt
sed is the command that calls stream editor.
Flag -i is the flag used to represent editing files in place (it makes backup if extension is supplied). In this case, extension written is .bak and indeed the backup file (containing initial context of our file) is created with the original name + the extension provided.
Argument 's/"id":"[0-9]{1,}"//g' is the argument given to the sed command.
Since this argument (regular expression in it) was the cause of the problem, I am going to explain it in detail.
First part we should notice is that its structure is s/Regex/Replacement/g where
Regex = "id":"[0-9]{1,}"
Replacement = nothing (literally nothing, not even blank space)
So basically, as described by Bruce Barnett, s stands for substitution. Regex is the part we will replace with the Replacement. At the end, letter g means that we will change more than just one occurrence of this regex per line (without g, it would replace just the first occurrence in every line, no matter how many are there).
And at the end we have ./Filename.txt, which is the source file we are applying this command on (./ means that the file is in the same directory from where we are running this command).
About the regex used ("id":"[0-9]{1,}"):
It starts with the literals ("id":") and this part will match literally any part in the file which is exactly the same as this one. Next, we have ([0-9]{1,}), which means that we want to, in addition to the first part, look for the at least one occurrence of a number (but it can be more of them, as the matched example from the question shows).
Now you may understand why comma caused this problem. There is no comma in the original text in the file. Thus, none of the commands tried (since all of them contain comma) worked. Of course, some of them have even more reasons.
EDIT: As #ghoti pointed out, replacement is not a regex. It is the string we will put at the place(s) that are found by our regex expression. So in this case, our replacement is blank string (since we want to delete the specified part).
I am essentially trying to use sed to remove a few lines within a text document. To clean it up. But I'm not getting it right at all. Missing something and I have no idea what...
#!/bin/bash
items[0]='X-Received:'
items[1]='Path:'
items[2]='NNTP-Posting-Date:'
items[3]='Organization:'
items[4]='MIME-Version:'
items[5]='References:'
items[6]='In-Reply-To:'
items[7]='Message-ID:'
items[8]='Lines:'
items[9]='X-Trace:'
items[10]='X-Complaints-To:'
items[11]='X-DMCA-Complaints-To:'
items[12]='X-Abuse-and-DMCA-Info:'
items[13]='X-Postfilter:'
items[14]='Bytes:'
items[15]='X-Original-Bytes:'
items[16]='Content-Type:'
items[17]='Content-Transfer-Encoding:'
items[18]='Xref:'
for f in "${items[#]}"; do
sed '/${f}/d' "$1"
done
What I am thinking, incorrectly it seems, is that I can setup a for loop to check each item in the array that I want removed from the text file. But it's simply not working. Any idea. Sure this is basic and simple and yet I can't figure it out.
Thanks,
Marek
Much better to create a single sed script, rather than generate 19 small scripts in sequence.
Fortunately, generating a script by joining the array elements is moderately easy in Bash:
regex=$(printf '\|%s' "${items[#]}")
regex=${regex#'\|'}
sed "/^$regex/d" "$1"
(Notice also the addition of ^ to the final regex -- I assume you only want to match at beginning of line.)
Properly, you should not delete any lines from the message body, so the script should leave anything after the first empty line alone:
sed "1,/^\$/!b;/$regex/d" "$1"
Add -i if you want in-place editing of the target file.
Looking for help creating a script that will replace the last line of an XML file with a tag. I have a few hundred files so I'm looking for something that will process them in a loop. I've managed to rename the files sequentially like this:
posts1.xml
posts2.xml
posts3.xml
etc...
to make it easier to loop through. But I have no idea how to write a script to do this. I'm open to using either Linux or Windows (but i would guess that Linux is better for this kind of task).
So if you want to append a line to every file:
sed -i '$a<YOUR_SHINY_NEW_TAG>' *xml
To replace the last line:
sed -i '$s/.*/<YOUR_SHINY_NEW_TAG>/' *xml
But do note, sed is not the ideal tool to modify xml.
XMLStarlet is a command-line toolkit for performing XML parsing and manipulations. Note that as an XML-aware toolkit, it'll respect XML structure, character encoding and entity substitution.
Check out the ed command to see how to modify documents. You can wrap this in a standard bash loop.
e.g. in a doc consisting of a chain of <elem>s, you can add a following <added>5</added>:
mkdir new
for x in *.xml; do
xmlstarlet ed -a "//elem[count(//elem)]" -t elem -n added -v 5 $x > new/$x
done
Linux way using sed:
To edit the last line of the file in place, you can use sed:
sed -i '$s_pattern_replacement_' filename
To change the whole line to "replacement" use $s_.*_replacement_. Be sure to escape any _'s in replacement with a \.
To loop over files, just use for:
for f in /path/posts*.xml; do sed -i '$s_.*_replacement_' $f; done
This, however, is a dirty way as it's not aware of the XML structure, whereas the XML structure is not affected by newlines. You have to be sure the last line of the files contains exactly what you expect it to.
It makes little to no difference whether you're on Linux, Windows or MacOS
The question is what language do you want to use?
The following is an example in c# (not optimized, but read it as speudocode):
string rootDirectory = #"c:\myfiles";
var files = Directory.GetFiles(rootDirectory, "*.xml");
foreach (var file in files)
{
var lines = File.ReadAllLines(file);
lines[lines.Length - 1] = "whatever you want here";
File.WriteAllLines(file, lines);
}
You can compile this and run it on Windows, Linux, etc..
Or you could do the same in Python.
Of course this method does not actually parse the XML,
but you just wanted to replace the last line right?