Create a table of dates in rows - oracle

Question

I have a Oracle Database;
and I want to create a table with two columns, one contain id and the other contain incremented dates in rows.
i want to specify in my PL/SQL code the limit dates, and the code will generate the rows between the two limit dates (from and to).
This is an example output result :
+-----+--------------------+
| id |dates |
+-----+--------------------+
| 1 |01/02/2011 04:00:00 |
+-----+--------------------+
| 2 |01/02/2011 05:00:00 |
+-----+--------------------+
| 3 |01/02/2011 06:00:00 |
+-----+--------------------+
| 4 |01/02/2011 07:00:00 |
+-----+--------------------+
| 5 |01/02/2011 08:00:00 |
....
...
..
| 334 |05/03/2011 023:00:00|
+-----+--------------------+

Answer 1

You haven't exactly deluged us with details, but this is the sort of construct you want:
select level as id
, &&start_date + ((level-1) * (1/24) as dates
from dual
connect by level <= ((&&end_date - &&start_date)*24)
/
This assumes your input values are whole days, You will need to adjust the maths if your start or end date contains a time component.

Answer 2

You would need to start with a date baseline:
vBaselineDate := TRUNC(SYSDATE);
OR
vBaselineDate := TO_DATE('28-03-2013 12:00:00', 'DD-MM-YYYY HH:MI:SS');
Then increment the baseline by adding fractions of a day depending on how large you want the range, eg: 1 minute, 1 hour etc.
FOR i IN 1..334 LOOP
INSERT INTO mytable
(id, dates)
VALUES
(i, (vBaselineDate + i/24));
END LOOP;
COMMIT;
1/24 = 1 hour.
1/1440 = 1 minute;
Hope this helps.