I have been all over the interwebs and cannot seem to find out how to access an array within a hash. Plenty of ways to iterate through as well as flatten but no plain access.
hash = Hash.new()
data1 = "foo"
data2 = "bar"
hash["foobar"] = {data1, data2}
This all works, now how can I access data1 and data2 individually within the hash?
I was thinking puts hash["foobar"][0] should output foo but it returns nil.
Note: Every array in the hash will have Exactly 2 elements.
I know the answer is a simple 1 liner, I just cannot seem to find it.
As I commented on the question, array literals are square brackets [ ], not curly braces { }. Change your last line to:
hash["foobar"] = [data1, data2]
(You were getting nil presumably because the hash literal had no 0 key. Testing here reveals that , can apparently function as => (*shudder*), so your iteral was equivalent to {data1 => data2}.)
Related
I'm trying to get the index of a key in a hash.
I know how to do this in an array:
arr = ['Done', 13, 0.4, true]
a = arr.index('Done')
puts a
Is there a method or some sort of way to do this something like this with a key in a hash? Thanks!
Hashes aren't usually treated as ordered structures, they simply have a list of keys and values corresponding to those keys.
It's true that in Ruby hashes are technically ordered, but there's very rarely an actual use case for treating them as such.
If what you want to do is find the key corresponding to a value in a hash, you can simply use the Hash#key method:
hash = { a: 1, b: 2 }
hash.key(1) # => :a
I suppose you could use hash.keys.index(hash.key(1)) to get 0 since it's the first value, but again, I wouldn't advise doing this because it's not typical use of the data structure
There are at least a couple ways you can get this information, the 2 that come to mind are Enumerable's find_index method to pass each element to a block and check for your key:
hash.find_index { |key, _| key == 'Done' }
or you could get all the keys from your hash as an array and then look up the index as you've been doing:
hash.keys.index('Done')
When I do :symbol == :symbol I find that its true. They are the same.
If this is the case, how can we create arrays like this:
a = [{:name=>"Michael"},{:name=>"John"}]
Look the below code :
a = [{:name=>"Michael"},{:name=>"John"}]
a.map(&:object_id) # => [70992070, 70992050]
This is because a is an array of Hash, but they are 2 different hash objects. In Ruby, Hash must have uniq key. But 2 different hash can have same named symbols as keys.
You seem to be confused about hash keys. One hash cannot contain the same key twice, but two different hashes can have the same object as a key. For example:
a_key = "hello"
spanish = { a_key => "hola" }
french = { a_key => "bonjour" }
some_array = [spanish, french]
On top of that, it is possible for arrays to contain duplicate objects (e.g. [1, 2, 1] is valid) -- but these aren't even duplicates. Two hashes that contain the same key are still different objects.
There's nothing at all unusual about an array like that. In fact, it's normal for hashes in an array to have keys in common, because usually if you want to put things in an array, it means they have something in common that you can use to deal with them in the same way.
I have been using Ruby for a while, but this is my first time doing anything with a database. I've been playing around with MongoDB for a bit and, at this point, I've begun to try and populate a simple database.
Here is my problem. I have a text file containing data in a particular format. When I read that file in, the data is stored in nested arrays like so:
dataFile = ["sectionName", ["key1", "value1"], ["key2", "value2", ["key3", ["value3A", "value3B"]]]
The format will always be that the first value of the array is a string and each subsequent value is an array. Each array is formatted in as a key/value pair. However, the value can be a string, an array of two strings, or a series of arrays that have their own key/value array pairs. I don't know any details about the data file before I read it in, just that it conforms to these rules.
Now, here is my problem. I want to read this into to a Mongo database preserving this basic structure. So, for instance, if I were to do this by hand, it would look like this:
newDB = mongo_client.db("newDB")
newCollection = newDB["dataFile1"]
doc = {"section_name" => "sectionName", "key1" => "value1", "key2" => "value2", "key3" => ["value3A", "value3B"]}
ID = newCollection.insert(doc)
I know there has to be an easy way to do this. So far, I've been trying various recursive functions to parse the data out, turn it into mongo commands and try to populate my database. But it just feels clunky, like there is a better way. Any insight into this problem would be appreciated.
The value that you gave for the variable dataFile isn't a valid array, because it is missing an closing square bracket.
If we made the definition of dataFile a valid line of ruby code, the following code would yield the hash that you described. It uses map.with_index to visit each element of the array and transforms this array into a new array of key/value hashes. This transformed array of hashes is flatted and converted into single hash using the inject method.
dataFile = ["sectionName", ["key1", "value1"], ["key2", "value2", ["key3", ["value3A", "value3B"]]]]
puts dataFile.map.with_index {
|e, ix|
case ix
when 0
{ "section_name" => e }
else
list = []
list.push( { e[0] => e[1] } )
if( e.length > 2 )
list.push(
e[2..e.length-1].map {|p|
{ p[0] => p[1] }
}
)
end
list
end
}.flatten.inject({ }) {
|accum, e|
key = e.keys.first
accum[ key ] = e[ key ]
accum
}.inspect
The output looks like:
{"section_name"=>"sectionName", "key1"=>"value1", "key2"=>"value2", "key3"=>["value3A", "value3B"]}
For input that looked like this:
["sectionName", ["key1", "value1"], ["key2", "value2", ["key3", ["value3A", "value3B"]], ["key4", ["value4A", "value4B"]]], ["key5", ["value5A", "value5B"]]]
We would see:
{"section_name"=>"sectionName", "key1"=>"value1", "key2"=>"value2", "key3"=>["value3A", "value3B"], "key4"=>["value4A", "value4B"], "key5"=>["value5A", "value5B"]}
Note the arrays "key3" and "key4", which is what I consider as being called a series of arrays. If the structure has array of arrays of unknown depth then we would need a different implementation - maybe use an array to keep track of the position as the program walks through this arbitrarily nested array of arrays.
In the following test, please find two solutions.
The first converts to a nested Hash which is what I think that you want without flattening the input data.
The second stores the key-value pairs exactly as given from the input.
I've chosen to fix missing closing square bracket by preserving key values pairs.
The major message here is that while the top-level data structure for MongoDB is a document mapped to a Ruby Hash
that by definition has key-value structure, the values can be any shape including nested arrays or hashes.
So I hope that test examples cover the range, showing that you can match storage in MongoDB to fit your needs.
test.rb
require 'mongo'
require 'test/unit'
require 'pp'
class MyTest < Test::Unit::TestCase
def setup
#coll = Mongo::MongoClient.new['test']['test']
#coll.remove
#dataFile = ["sectionName", ["key1", "value1"], ["key2", "value2"], ["key3", ["value3A", "value3B"]]]
#key, *#value = #dataFile
end
test "nested array data as hash value" do
input_doc = {#key => Hash[*#value.flatten(1)]}
#coll.insert(input_doc)
fetched_doc = #coll.find.first
assert_equal(input_doc[#key], fetched_doc[#key])
puts "#{name} fetched hash value doc:"
pp fetched_doc
end
test "nested array data as array value" do
input_doc = {#key => #value}
#coll.insert(input_doc)
fetched_doc = #coll.find.first
assert_equal(input_doc[#key], fetched_doc[#key])
puts "#{name} fetched array doc:"
pp fetched_doc
end
end
ruby test.rb
$ ruby test.rb
Loaded suite test
Started
test: nested array data as array value(MyTest) fetched array doc:
{"_id"=>BSON::ObjectId('5357d4ac7f11ba0678000001'),
"sectionName"=>
[["key1", "value1"], ["key2", "value2"], ["key3", ["value3A", "value3B"]]]}
.test: nested array data as hash value(MyTest) fetched hash value doc:
{"_id"=>BSON::ObjectId('5357d4ac7f11ba0678000002'),
"sectionName"=>
{"key1"=>"value1", "key2"=>"value2", "key3"=>["value3A", "value3B"]}}
.
Finished in 0.009493 seconds.
2 tests, 2 assertions, 0 failures, 0 errors, 0 pendings, 0 omissions, 0 notifications
100% passed
210.68 tests/s, 210.68 assertions/s
I am new to ruby and don't have much experience with hashes, I have a variable named tweets and it is a hash as such:
{"statuses"=>[{"metadata"=>{"result_type"=>"recent", "iso_language_code"=>"tl"}, "lang"=>"tl"}]}
I would like to save the array of information as a separate variable in an array. How would I go about this?
Hash's have 2 very nice methods,
hash.values
hash.keys
in your case -
h = {"statuses"=>[{"metadata"=>{"result_type"=>"recent", "iso_language_code"=>"tl"}, "lang"=>"tl"}]}
p h.values
p.keys
These output arrays of each type. This might be what you want.
Also, this question will very well be closed. 1 Google search reported several Hash to Array SO questions.
Ruby Hash to array of values
Converting Ruby hashes to arrays
If you have a Hash like so:
hash = {:numbers => [1,2,3,4]}
And you need to capture the array into a new variable. You can just access the key and assign it to a new variable like so:
one_to_five = hash[:numbers]
However, note that the new variable actually holds the array that is in the hash. So altering the hash's array alters the new variable's array.
hash[:numbers] << 6
puts one_to_five #=> [1,2,3,4,5,6]
If you use dup, it will create a copy of the array so it will be two separate arrays.
one_to_five = hash[:numbers].dup
hash[:numbers] << 6
puts one_to_five #=> [1,2,3,4,5]
So, in your case:
hash = {'statuses' => [{"metadata"=>{"result_type"=>"recent", "iso_language_code"=>"tl"}, "lang"=>"tl"}]}
new_array = hash['statuses'].dup
However, it would be interesting to see what it is you are wishing to accomplish with your code, or at least get a little more context, because this may not be the best approach for your final goal. There are a great many things you can do with Arrays and Hashes (and Enumerable) and I would encourage you to read through the documentation on them.
I have a Ruby array like this
q_id = [1,2,3,4,5,...,100]
I want to iterate through the array and convert into a hash like this
{
:1 => { #some hash} ,
:2 => { #another hash},
...
:100 => {#yet another hash}
}
What is the shortest and most elegant way to accomplish this?
[EDIT : the to_s.to_sym while being handy is not how I want it. Apologies for not mentioning it earlier.]
For creating a symbol, either of these work:
42.to_s.to_sym
:"#{42}"
The #inspect representation of these shows :"42" only because :42 is not a valid Symbol literal. Rest assured that the double-quotes are not part of the symbol itself.
To create a hash, there is no reason to convert the keys to symbols, however. You should simply do this:
q_id = (1..100).to_a
my_hash_indexed_by_value = {}
q_id.each{ |val| my_hash_indexed_by_value[val] = {} }
Or this:
my_hash = Hash[ *q_id.map{ |v| [v,{}] }.flatten ]
Or this:
# Every time a previously-absent key is indexed, assign and return a new hash
my_hash = Hash.new{ |h,val| h[val] = {} }
With all of these you can then index your hash directly with an integer and get a unique hash back, e.g.
my_hash[42][:foo] = "bar"
Unlike JavaScript, where every key to an object must be a string, Hashes in Ruby accept any object as the key.
To translate an integer into a symbol, use to_s.to_sym .. e.g.,:
1.to_s.to_sym
Note that a symbol is more related to a string than an integer. It may not be as useful for things like sorting anymore.
Actually "symbol numbers" aren't a thing in Ruby (try to call the to_sym method on a number). The benefit of using symbols in a hash is about performance, since they always have the same object_id (try to call object_id on strings, booleans, numbers, and symbols).
Numbers are immediate value and, like Symbol objects, they always have the same object_id.
Anyway, using the new hash syntax implies using symbols as keys, but you can always use the old good "hash rocket" syntax
awesome_hash = { 1 => "hello", 2 => "my friend" }
Read about immediate values here:
https://books.google.de/books?id=jcUbTcr5XWwC&pg=PA73&lpg=PA73&dq=immediate+values+singleton+method&source=bl&ots=fIFlAe8xjy&sig=j7WgTA1Cft0WrHwq40YdTA50wk0&hl=en&sa=X&ei=0kHSUKCVB-bW0gHRxoHQAg&redir_esc=y#v=onepage&q&f=false
If you are creating a hard-coded constant numeric symbol, there's a simpler way:
:'99'
This produces the same results as the more complex methods in other answers:
irb(main):001:0> :'99'
=> :"99"
irb(main):002:0> :"#{99}"
=> :"99"
irb(main):003:0> 99.to_s.to_sym
=> :"99"
Of course, this will not work if you're dynamically creating a symbol from a variable, in which case one of the other two approaches is required.
As already stated, :1 is not a valid symbol. Here's one way to do what you're wanting, but with the keys as strings:
Hash[a.collect{|n| [n.to_s, {}] }]
An array of the objects you want in your hash would be so much easier to use, wouldn't it? Even a hash of integers would work pretty well, wouldn't it?
u can use
1.to_s.to_sym
but this will make symbols like :"1"
You can make symbolic keys with Hash[]:
a = Hash[(1..100).map{ |x| ["#{x}".to_sym, {}] }]
Check type of hash keys:
puts a.keys.map(&:class)
=>
Symbol
...
Symbol
Symbol