QTabBar.setTabButton() inside subclass crashes the Application - pyside

In the following Python snippet, The application is crashed when I run it. I tested it on Mac OS X, Windows and Ubuntu:
import sys
from PySide.QtCore import *
from PySide.QtGui import *
class TabbedWindow(QTabWidget):
def __init__(self):
super(TabbedWindow, self).__init__()
self.setWindowTitle(u"Tabs Test")
self.resize(800, 600)
self.addTab(QTextEdit(), "Tab 1")
self.addTab(QCalendarWidget(), "Tab 2")
self.setTabsClosable(True)
tabBar = self.tabBar()
menuButton = QPushButton('')
menuButton.resize(0,0)
tabBar.setTabButton(1, QTabBar.RightSide, menuButton)
def main():
app = QApplication(sys.argv)
window = QMainWindow()
tabs = TabbedWindow()
window.setCentralWidget(tabs)
window.show()
sys.exit(app.exec_())
if __name__ == '__main__':
main()
When I remove this line tabBar.setTabButton(1, QTabBar.RightSide, menuButton) it works!
Also, If I moved this line to main function: it works too! I mean when I added this to main function:
tabBar = tabs.tabBar()
menuButton = QPushButton('')
menuButton.resize(0,0)
tabBar.setTabButton(1, QTabBar.RightSide, menuButton)
What I want to do is hiding Close Button on some tabs.
Is there any workaround to perform this?

Finally, I found the answer to make it work!
You have to declare the button as a member of the class.
self.menuButton = QPushButton('')
instead of
menuButton = QPushButton('')
I hope someone will find this solution is useful.

Related

Microsoft Azure Speech-to-Text MVC application

I'm working on an application that uses the Microsoft Cognitive services Speech-to-Text API. I'm trying to create a GUI where the transcribed text should show up in a textbox once the start button is pushed and the transcription is stopped once a stop-button is pressed. I'm pretty new to creating GUI's and have been using PyQt5. I have divided the application according to MVC (Model-View-Controller). The code for the GUI is as follows:
import sys
import time
from functools import partial
import azure.cognitiveservices.speech as speechsdk
from PyQt5.QtCore import *
from PyQt5.QtWidgets import *
from PyQt5.QtGui import *
class test_view(QMainWindow):
def __init__(self):
super().__init__()
self.generalLayout = QVBoxLayout()
self._centralWidget = QWidget(self)
self.setCentralWidget(self._centralWidget)
self._centralWidget.setLayout(self.generalLayout)
self._createApp()
def _createApp(self):
self.startButton = QPushButton('Start')
self.stopButton = QPushButton('Stop')
buttonLayout = QHBoxLayout()
self.startButton.setFixedWidth(220)
self.stopButton.setFixedWidth(220)
buttonLayout.addWidget(self.startButton)
buttonLayout.addWidget(self.stopButton)
self.text_box = QTextEdit()
self.text_box.setReadOnly(True)
self.text_box.setFixedSize(1500, 400)
layout_text = QHBoxLayout()
layout_text.addWidget(self.text_box)
layout_text.setAlignment(Qt.AlignCenter)
self.generalLayout.addLayout(buttonLayout)
self.generalLayout.addLayout(layout_text)
def appendText(self, text):
self.text_box.append(text)
self.text_box.setFocus()
def clearText(self):
return self.text_box.setText('')
class test_ctrl:
def __init__(self, view):
self._view = view
def main():
application = QApplication(sys.argv)
view = test_view()
view.showMaximized()
test_ctrl(view=view)
sys.exit(application.exec_())
if __name__ == "__main__":
main()
The Speech-to-Text Transcribe code is:
import azure.cognitiveservices.speech as speechsdk
import time
def setupSpeech():
speech_key, service_region = "speech_key", "service_region"
speech_config = speechsdk.SpeechConfig(subscription=speech_key, region=service_region)
speech_recognizer = speechsdk.SpeechRecognizer(speech_config=speech_config)
return speech_recognizer
def main():
speech_recognizer = setupSpeech()
done = False
def stop_cb(evt):
print('CLOSING on {}'.format(evt))
speech_recognizer.stop_continuous_recognition()
nonlocal done
done = True
all_results = []
def handle_final_result(evt):
all_results.append(evt.result.text)
speech_recognizer.recognizing.connect(lambda evt: print(evt))
speech_recognizer.recognized.connect(handle_final_result)
speech_recognizer.session_stopped.connect(stop_cb)
speech_recognizer.canceled.connect(stop_cb)
speech_recognizer.start_continuous_recognition()
while not done:
time.sleep(.5)
print(all_results)
if __name__ == "__main__":
main()
I know for sure that both of the pieces of code work, but I'm not sure how to build the speech-to-text code into the MVC code. I think it should work with a model and it should be connected through the controller to the view. I tried doing this in multiple ways but I just can't figure it out. I also figured I need some kind of threading to keep the code from freezing the GUI. I hope someone can help me with this.
You need to replace this part
print(all_results)
and push all_results asynchronously to ur code for processing the text.
If not, expose a button in the UI to invoke the speech_recognizer.start_continuous_recognition() as a separate function and pick the results to process. This way you can avoid freezing the UI

How to display an icon in the systray reflecting NumLk state

My computer doesn't have any way of letting me know if my NumLk is on or off, so I am trying to add an icon in my systray that will changed depending on the state of my NumLk. This .py will always be running when my computer is on.
So far I was able to mix 3 codes and I am able to display the icon in the systray but it doesn't get updated when the state of NumLk change. Actually if I press NumLk twice, I still get the same icon (the on one) and I get this error:
QCoreApplication::exec: The event loop is already running
File "\systray_icon_NumLk_on_off.py", line 21, in on_key_press
main(on)
File "\systray_icon_NumLk_on_off.py", line 46, in main
sys.exit(app.exec_())
SystemExit: -1
My code may not be the best way to do it, so any alternative is welcome! Here is what I came up so far:
#####get the state of NumLk key
from win32api import GetKeyState
from win32con import VK_NUMLOCK
#how to use: print(GetKeyState(VK_NUMLOCK))
#source: http://stackoverflow.com/questions/21160100/python-3-x-getting-the-state-of-caps-lock-num-lock-scroll-lock-on-windows
#####Detect if NumLk is pressed
import pyglet
from pyglet.window import key
window = pyglet.window.Window()
#source: http://stackoverflow.com/questions/28324372/detecting-a-numlock-capslock-scrlock-keypress-keyup-in-python
on=r'on.png'
off=r'off.png'
#window.event
def on_key_press(symbol, modifiers):
if symbol == key.NUMLOCK:
if GetKeyState(VK_NUMLOCK):
#print(GetKeyState(VK_NUMLOCK))#should be 0 and 1 but
main(on)
else:
main(off)
#window.event
def on_draw():
window.clear()
### display icon in systray
import sys
from PyQt5 import QtCore, QtGui, QtWidgets
#source: http://stackoverflow.com/questions/893984/pyqt-show-menu-in-a-system-tray-application - add answer PyQt5
class SystemTrayIcon(QtWidgets.QSystemTrayIcon):
def __init__(self, icon, parent=None):
QtWidgets.QSystemTrayIcon.__init__(self, icon, parent)
menu = QtWidgets.QMenu(parent)
exitAction = menu.addAction("Exit")
self.setContextMenu(menu)
def main(image):
app = QtWidgets.QApplication(sys.argv)
w = QtWidgets.QWidget()
trayIcon = SystemTrayIcon(QtGui.QIcon(image), w)
trayIcon.show()
sys.exit(app.exec_())
if __name__ == '__main__':
pyglet.app.run()
The reason for QCoreApplication::exec: The event loop is already running is actually because you're trying to start app.run() twice. Qt will notice there's already an instance running and throw this exception. When instead, what you want to do is just swap the icon in the already running instance.
Your main problem here is actually the mix of libraries to solve one task if you ask me.
Rather two tasks, but using Qt5 for the graphical part is fine tho.
The way you use Pyglet is wrong from the get go.
Pyglet is intended to be a highly powerful and effective graphics library where you build a graphics engine ontop of it. For instance if you're making a game or a video-player or something.
The way you use win32api is also wrong because you're using it in a graphical window that only checks the value when a key is pressed inside that window.
Now, if you move your win32api code into a Thread (a QtThread to be precise) you can check the state no matter if you pressed your key inside your graphical window or not.
import sys
import win32api
import win32con
from PyQt5 import QtCore, QtGui, QtWidgets
from threading import Thread, enumerate
from time import sleep
class SystemTrayIcon(QtWidgets.QSystemTrayIcon):
def __init__(self, icon, parent=None):
QtWidgets.QSystemTrayIcon.__init__(self, icon, parent)
menu = QtWidgets.QMenu(parent)
exitAction = menu.addAction("Exit")
exitAction.setShortcut('Ctrl+Q')
exitAction.setStatusTip('Exit application')
exitAction.triggered.connect(QtWidgets.qApp.quit)
self.setContextMenu(menu)
class KeyCheck(QtCore.QThread):
def __init__(self, mainWindow):
QtCore.QThread.__init__(self)
self.mainWindow = mainWindow
def run(self):
main = None
for t in enumerate():
if t.name == 'MainThread':
main = t
break
while main and main.isAlive():
x = win32api.GetAsyncKeyState(win32con.VK_NUMLOCK)
## Now, GetAsyncKeyState returns three values,
## 0 == No change since last time
## -3000 / 1 == State changed
##
## Either you use the positive and negative values to figure out which state you're at.
## Or you just swap it, but if you just swap it you need to get the startup-state correct.
if x == 1:
self.mainWindow.swap()
elif x < 0:
self.mainWindow.swap()
sleep(0.25)
class GUI():
def __init__(self):
self.app = QtWidgets.QApplication(sys.argv)
self.state = True
w = QtWidgets.QWidget()
self.modes = {
True : SystemTrayIcon(QtGui.QIcon('on.png'), w),
False : SystemTrayIcon(QtGui.QIcon('off.png'), w)
}
self.refresh()
keyChecker = KeyCheck(self)
keyChecker.start()
sys.exit(self.app.exec_())
def swap(self, state=None):
if state is not None:
self.state = state
else:
if self.state:
self.state = False
else:
self.state = True
self.refresh()
def refresh(self):
for mode in self.modes:
if self.state == mode:
self.modes[mode].show()
else:
self.modes[mode].hide()
GUI()
Note that I don't do Qt programming often (every 4 years or so).
So this code is buggy at it's best. You have to press Ctrl+C + Press "Exit" in your menu for this to stop.
I honestly don't want to put more time and effort in learning how to manage threads in Qt or how to exit the application properly, it's not my area of expertis. But this will give you a crude working example of how you can swap the icon in the lower corner instead of trying to re-instanciate the main() loop that you did.

Works with QGridLayout not with QVBoxLayout

from PyQt4.QtCore import *
from PyQt4.QtGui import *
import sys, os, time
class SetName(QWidget):
def __init__(self):
QWidget.__init__(self)
self.show()
toplayout = QVBoxLayout()
self.setWindowTitle('Personal Info')
self.form_layout = QFormLayout()
self.setLayout(self.form_layout)
self.line_edit_param = QLineEdit(self)
self.line_edit_param.setPlaceholderText("Write Here")
self.form_layout.addRow('Write Name', self.line_edit_param)
toplayout.addLayout(self.form_layout)
self.setFocus()
class LearnApp(QDialog):
def __init__(self):
super(QDialog, self).__init__()
self.setWindowTitle("LearnApp")
self.active = False
close_button = QPushButton("Close")
close_button.clicked.connect(self.close)
self.check_button = QPushButton("Check")
self.check_button.clicked.connect(self.set_data)
self.tr = QTextEdit()
self.tr.setReadOnly(True)
# layout
layout = QHBoxLayout()
#layout.addWidget(self.button3)
sub_layout = QVBoxLayout()
sub_layout.addWidget(self.check_button)
sub_layout.addWidget(close_button)
layout.addLayout(sub_layout)
layout.addWidget(self.tr)
self.setLayout(layout)
self.setFocus()
def set_data(self):
print "in set_data"
SetName()
app = QApplication(sys.argv)
dialog = LearnApp()
dialog.show()
app.exec_()
This is the code I'm trying. If edit it with toplayout = QGridLayout(), program works fine but with toplayout = QVBoxLayout(), it gives message QLayout::addChildLayout: layout "" already has a parentand just flashes the new window. What could be the problem? How should I tackle this? I wanna use QVBoxLayout instead of QGridLayout
Firstly, the new window disappears straight away because you don't store a reference to it. You need to store a reference to the instance in your LearnApp class, or parent it to another Qt object outside of set_data() if you want it to stick around.
The error message regarding the layouts is not occurring because of your choice of layouts, but because you are calling
self.setLayout(self.form_layout)
and then
toplayout.addLayout(self.form_layout)
The first call assigns the layout to the instance of SetName, but in doing so also makes the instance the parent of self.form_layout. The second call is trying to add the same layout to toplayout and set it as the parent, but Qt sees that self.form_layout already has a parent (i.e. is being used elsewhere). This is what the error message is trying to tell you.
I suspect that instead of self.setLayout(self.form_layout), you intended to write something like
self.setLayout(toplayout)

Putting stuff in windows

How can I put stuff in the main window? I want to create a line edit in the main window(beneath the menu bar, maybe with some decription laber in front of it). How is this done? I used grid layout and this box layout, nothing works.
(sry for another trivial question, there are only few tutorials on pyside out there, and most of them only cover how to create single windows with buttons ect.)
import sys
from PySide import QtGui, QtCore, QtWebKit
class FirstClass(QtGui.QMainWindow, QtGui.QWidget):
def __init__(self):
super(FirstClass, self).__init__()
self.startingUI()
def startingUI(self):
self.setWindowTitle('Hauptfenster')
self.resize(800, 400)
self.statusBar()
#Menueinstellungen an sich
menue = self.menuBar()
#Actions des Menues:
#datei menue
menuleiste_datei = menue.addMenu('File')
datei_exit = QtGui.QAction('Exit', self)
datei_exit.setStatusTip('Close the programm')
menuleiste_datei.addAction(datei_exit)
datei_exit.triggered.connect(self.close)
#Einstellungen menue
menuleiste_configurations = menue.addMenu('Configurations')
configurations_settings = QtGui.QAction('Settings', self)
configurations_settings.setStatusTip('Configurations(Settings)')
menuleiste_configurations.addAction(configurations_settings)
configurations_settings.triggered.connect(self.newwindow)
self.lineedit = QtGui.QLineEdit()
self.layout = QtGui.QHBoxLayout()
self.layout.addWidget(self.lineedit)
self.setLayout(self.layout)
self.show()
def newwindow(self):
self.wid = QtGui.QWidget()
self.wid.resize(250, 150)
self.setWindowTitle('NewWindow')
self.wid.show()
def main():
app = QtGui.QApplication(sys.argv)
start = FirstClass()
sys.exit(app.exec_())
if __name__== '__main__':
main()
I do not believe creating a class with a multiple inheritance is recommended best practice. If an attribute is not found in FirstClass, then it searches left to right (QtGui.QMainWindow to QtGui.QWidget). From my perspective, this would turn into a nightmare to support and debug. My guess this is why the self.layout is not working properly.
I made separate classes for QtGui.QMainWindow and QtGui.QWidget. FirstWindowClass sets the central widget as FirstWidgetClass. FirstWidgetClass has your QLineEdit and I went ahead and inserted a label. I changed QHBoxLayout to QGridLayout to help you understand how it works.
Some tips from my learning experiences with Python and Pyside these past couple months:
Remember you can always look at PyQt examples and majority will work directly with PySide modules.
I recommend looking over http://srinikom.github.io/pyside-docs/index.html as a lot of the modules have simple examples.
For my personal project, a lot of the solutions to my Qt questions were in C++ so do not be afraid to convert it to python.
import sys
from PySide import QtGui, QtCore, QtWebKit
class FirstWindowClass(QtGui.QMainWindow):
def __init__(self):
super(FirstWindowClass, self).__init__()
self.setWindowTitle('Hauptfenster')
self.resize(800, 400)
self.statusBar()
# Set central widget that expands to fill your window
self.main_widget = FirstWidgetClass(self)
self.setCentralWidget(self.main_widget)
#Menueinstellungen an sich
menue = self.menuBar()
#Actions des Menues:
#datei menue
menuleiste_datei = menue.addMenu('File')
datei_exit = QtGui.QAction('Exit', self)
datei_exit.setStatusTip('Close the programm')
menuleiste_datei.addAction(datei_exit)
datei_exit.triggered.connect(self.close)
#Einstellungen menue
menuleiste_configurations = menue.addMenu('Configurations')
configurations_settings = QtGui.QAction('Settings', self)
configurations_settings.setStatusTip('Configurations(Settings)')
menuleiste_configurations.addAction(configurations_settings)
configurations_settings.triggered.connect(self.newwindow)
# Open the window
self.show()
def newwindow(self):
self.wid = QtGui.QWidget()
self.wid.resize(250, 150)
self.wid.setWindowTitle('NewWindow')
self.wid.show()
class FirstWidgetClass(QtGui.QWidget):
def __init__(self, parent=None):
super(FirstWidgetClass, self).__init__()
self.label_example = QtGui.QLabel('Enter Data:')
self.lineedit = QtGui.QLineEdit()
self.layout = QtGui.QGridLayout()
self.layout.addWidget(self.label_example, 0, 0)
self.layout.addWidget(self.lineedit, 0, 1)
self.setLayout(self.layout)
self.show()
def main():
app = QtGui.QApplication(sys.argv)
start = FirstWindowClass()
sys.exit(app.exec_())
if __name__== '__main__':
main()

pyQT4: How to open a window from another window

I'm trying to open a window (QWidget) when clicking on a button. My problem is that the second window doesn't show up when I click on the button no matter what I've tried. The two windows are created using QTDesigner.
Here is a little snippet explaining what I'm trying to do:
from PyQt4.QtGui import *
from PyQt4.QtCore import *
from win1 import *
from win2 import *
import sys
class win1(QWidget, Ui_Win1):
def __init__(self, parent = None):
self.parent = parent
QWidget.__init__(self)
self.setupUi(parent)
self.connect(self.pushButton, SIGNAL("clicked()"), self.on_btn_clicked)
def on_btn_clicked(self):
self.child = win2(self.parent)
self.child.show()
class win2(QWidget, Ui_Win2):
def __init__(self, parent = None):
QWidget.__init__(self)
self.setupUi(parent)
def main(args):
app = QApplication(args)
win = QWidget()
a = win1(win)
win.show()
result = app.exec_()
if __name__=="__main__":
main(sys.argv)
What am I missing here ?
Thanks.
Not sure, but two random thoughts:
If you add a print statement to on_btn_clicked, do you see anything when you click on the button? This would diagnose whether it's an event triggering issue
Does it work if you change the setupUI(parent) commands to setupUI(self)?

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