I am trying to introduce Unit testing in the interface layer.In code we provide <from:sedaQueueName> and camel parses the message and send it to external systems.
I want to change the route <to:ExternalSystem> to <to:PrintMessageOnScreen>.
I am already using a static global value isUnitTest to get database connection outside the container.
Is there a way I can use the same variable value in application Context to decide my route?
I can access the property value using Spring SL like this:
<bean id="forTesting" class="test.UnitTest">
<property name="isUnitTest">
<value>#{T(test.UnitTest).isUnitTest}</value>
</property>
</bean>
I am not sure how to read this property inside a camel route and decide my route based on its value.
you can use the dynamic router just check the documentation, or you can use the content based router here its documentation
Related
Is it possible to specify complete path of a view file in controller without making use of view resolver?
Suppose I have just one file, say a XML file in my views and for a particular request I want to serve that XML file. By using view resolver, I am not able to find a way to pick up such a file and server it directly like me serve a jsp. So, for such a case can I do something in which I specify complete path in controller like we used to do in servlet's getRequestDispatcher?
My view resolver is currently configured for JSP only, I am not able to find a view using view resolvers to handle this situation, my view resolver is like as given below:
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/jsp/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
Currently I am using getRequestDispatcher in controller for this? Is there any spring based alternative?
Spring MVC allows you to create a request handling method with different return types, see the reference guide. Instead of a String return a View from your method which points directly to your resource. When you return a View instance Spring MVC will not consult a ViewResolver but simply use the view as is. For you case you probably want to use an InternalResourceView.
#RequestMapping
public View yourRequestHandlingMethod() {
return new InternalResourceView("path/to/resource");
}
I am new to Apache Camel and I am in a situation where my application needs a codec (HL7) to be registered with camel context. I know there is a solution where you can create a default camel context with an instance of your own registry but is there any way I could configure my own registry in the camel context?
I am using JavaDSL to develop my application and the configuration in context goes like this.
<bean id="hl7codec" class="org.apache.camel.component.hl7.HL7MLLPCodec">
<property name="charset" value="iso-8859-1"/>
</bean>
<camelcontext id = "context">
<ref bean = "MyRouteBuilder"/>
<camelcontext/>
I build the routes in MyRouteBuilder Class by overriding the configure method. My route goes like this.
from("mina2:tcp://localhost:8888?sync=true&codec=#hl7codec").to("jms:queue")
However, the codec doesn't seem to work. When I remove the codec, My application runs just fine and accepts HL7 messages but with the codec, I am not able to receive any messages. I feel this occurs because the codec bean is defined but the context isnt able to pick it up. I do not want to create a defaultcamelcontext with the required registry settings. Rather, I am looking for a way to register the codec within camelcontext configuration xml, and so far, I have failed.
Am I missing anything with my configuration? Any help would be greatly appreciated.
You normally should not need to use & in Java DSL, so replace &codec= with &codec=
I have config xml based spring application for which I have moved proprties required at start up time in database. It was very difficult to manage hundreds in property file and that is why database is introduced. To read properties a spring restful service is developed to return a map of all properties required at start up time.
I want to know how to replace properties reading from a map to spring context file e.g. ${config.service.url} should be polulated from a map read via web service.
One option I considered is to upgrade to Annotation based and start using MapPropertySource and Environment interface as environment.getRequiredProperty("config.service.url"). However upgrading to Annotation based is a big impact on project and is no at this time.
Second option that I am looking forward is to have a customised PropertyPlaceholderConfigurer.
Any pointer/help on this will be great.
Cheers,
Amber
You could define a PropertyPlaceholderConfigurer, but instead of specifying a file location, you can pass the properties directly as returned by your restful service.
<bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="properties" .../>
</bean>
I have this scenario, I have three declarative services that provide the same interface (say a reader interface and I have readerimpl1-database- readerimpl2-flat file- readerimpl3-memory). I want to have a consumer that binds only to the database implementation. In the component definition we give it a name so I am pretty sure that the name is in the registry so if I were to add an activate method I can lookup from the component context using the name.
I want to try to it via the bind/unbind though using the service name as the parameter. I am pretty sure that the "target" parameter in the component reference element can be used to do this but I have not found how to use it.
Has anyone else done this?
This would be similar to using
#Reference(mapped-name="foo")
Target is simply an OSGi filter. You can use it to filter by any service property. So, if your services have property named backend with values file or database, you can bind with the following target:
<scr:reference ... target="(backend=database)"/>
And the service with database backend itself will register as:
<scr:component ...>
...
<property name="backend" type="String" value="database"/>
</scr:component>
I have a Spring Boot & Spring Security application running, which should now get multi tenancy support.
I'd like to keep things as simple as possible. Though I'd like to determine the the database by path variable or request parameter. (the Apache Web Server in front of the Spring Boot app will handle that, i.e. it maps from subdomain to either path variable or request parameter).
Now I need a way to grab the first path variable (or a specific request param) before Spring calls the controller, and of course the value must be stored somewhere, so I can access it when I need to choose the right database.
So either (depending on what's possible / easier)
http://localhost:8080/customer1 (which I'd prefer) or
http://localhost:8080?_customer=customer1
should simply call the #Controller with #RequestMapping("") and the value customer1 should be stored somewhere for that request.
I know that 2. might be simpler, because it will already hit the right #Controller, but I'd prefer 1. somehow.
Thank you!
EDIT:
I just recognized, that HandlerInterceptor doesn't work as expected, because Spring Security always handles the requests first. Though I need an Interceptor that handles it before Spring Security kicks in.
You can make use of org.springframework.web.servlet.HandlerInterceptor. Implement the logic to store the values in request via preHandle method.
Configure it in spring config file as below
<mvc:interceptors>
<bean class="com.blah.interceptor.SomeInterceptor"/>
</mvc:interceptors>
In case requests are to be intercepted based on path, use below config instead
<mvc:interceptors>
<mvc:interceptor>
<mvc:mapping path="/customer1" />
<bean class="com.blah.interceptor.SomeInterceptor"/>
</mvc:interceptor>
</mvc:interceptors>