I am having trouble opening a .txt file that is in a different set of folders than where I have my .rb test script. I have a file structure of different test categories and then one generic folder that holds data files like .txt and Excel files.
Example:
Test Scripts -> Data This is where the data files are saved
Test Scripts -> Home Page -> Checkout This is where the .rb test file is
I am using this to open the .txt file now:
File.open("Data/activeSites.txt")
when the .rb is in the same folder as the Data folder.
Any suggestions?
If I correctly understand what you're asking, the issue is that you want to move your Ruby script from TestScripts/ to TestScripts/HomePage/Checkout/ and aren't sure how to refer to the activeSites.txt file from there. Is that correct?
If so, you just need to know that ../ means "the parent directory", so you can use:
File.open("../../Data/activeSites.txt")
The first ../ refers to the Home Page folder, then the second takes you up one more level to the Test Scripts folder.
Related
I will create a python script to download some pdf files from a web site and next save these files in some directories according to data extracted by each pdf. The problem is: I must open a pdf file in my script in ordert to extract data (I use pdfquery) but when I try to move the file to destination directory I get an error: the file is open by another process. I supposse the proces is the script. My qyestion is, it's possible to release the file from the python script and finally move it to the destination without errors?
A solution is copy (instead move) file and delete it manually or create another script which move the files when the "download and extract" script finish is job. But I search a clean approach.
I am trying to move files of various extensions to a folder if the filename contains the folder name.
Simple example: I have several files such as Fox-1.doc, Fox-2.doc, etc. I have a folder named Fox. I'm trying to move the files into the folder Fox if folder name is contained in the filename.
I tried to modify the code in the following post but I was not successful.
Move files into existing folders containing part of the filename
Any pointers is appreciated.
If you are using code for doing this try getting the filename and filter from the .contains() method often found in Strings.
If you are using Linux command line I think this could work
mv *fox* destination_path/
For Powershell I found this thread that could help you:
powershell to move files based on part of file name
All you'd have to do is create the .ps1 with the modified script.
I have around 500 JSON files sitting in their own directories that I need to re-name.
Every JSON file has the name, "list.json".
So what I need is a batch file operation for MacOS of some sort that will look in all the directories for files matching "list.json" and change the name to match name of the directory the file is sitting in. What kind of script do I need to do this?
I have zip file containing my installation files. I'm extracting this zip and copying these files into installation directory with the script shown below:
ZipDLL::extractall "$OUTDIR\demo.zip" "C:\myapp\demo\"
if I remove zip file from $OUTDIR than installer is not able to find zip file as expected. What I want to do is embedding this zip or its extracted folders into exe itself. I added
File -r "$OUTDIR/demo"
but this script didn't worked as well.
When you use the ZipDll plugin, you are referring to the file you want to process (demo.zip) by using its place at run time: along the installer.exe.
When you use the File statement to embed some files into the produced installer, you need to refer to the files by using their place at compile time.
Replace the $OUTDIR in the File statement by the path relative to the .nsi script.
BTW, you should take the habit to check at the compilation log, NSIS probably tells you about that kind of problem when paths are incorrect at compile-time.
I created a simple program that takes the path of a directory as an input, creates an archive of that directory (converting it into a single file), adds a shebang to that file (so that the contents of the file can be easily extracted), and writes the file to the base directory of the specified path.
The problem is that the file does not extract itself when I double click on it. Instead the operating system (I'm using Ubuntu 11.10) tries to open it with gedit. This obviously shows the shebang, random gibberish, and the contents of the archived files.
I made the file executable, first by using chmod +x; and when it still didn't work I tried chmod 777. However it still refuses to execute the file with the shebang when I double click on it. Perhaps this is because it's not a pure text file.
Interestingly when I try to execute the file directly from command line it reads the shebang and extracts the contents of the archive properly. So there's nothing wrong with my file format. I don't know much about what operating systems do when you double click on a file but I would sure like to understand.
It surely makes no sense to add a shebang to a file if you still need to manually execute it from the command line. One advantage could be that you don't need to specify the program to open it with but I believe that's hardly an advantage. Any help will be greatly appreciated.
Update 1:
The program that creates the archive is called opm. It can be installed via the node package manager using the following command:
npm install opm
After that you simply use opm to pack and unpack directories for you. For example if I have a directory called test in my home directory then I can open a terminal and execute the following command to pack it:
opm test
This will create an archive of the directory called test.pack in the home directory. The .pack file has the shebang #!/usr/bin/opm. Opening a file with the extension .pack with opm tells it that it's an archive and opm unpacks it in the same directory.
Note: Change the name of the test.pack file if you do not want it to overwrite your existing test directory.
I added the shebang to the .pack file so that it would extract itself when I opened it. However that doesn't seem to work. Nevertheless if I run one of the following command then it works:
./test.pack
You may check my source code and make any modifications to the program as you may wish to.
Update 2:
Alright I created the following .desktop file for opm and stored it in the $HOME/.local/share/applications/ directory:
[Desktop Entry]
Type=Application
Version=1.0
Encoding=UTF-8
Name=OPM
GenericName=Object Packer and Minifier
NoDisplay=true
Comment=JavaScript Package Manager
TryExec=opm
Exec=opm %f
Terminal=false
MimeType=application/opm
Now I was able to associate .pack files with opm by right clicking on a .pack file, going to the Properties window, the Open With tab, and setting opm.desktop as the default application. Now I am able to unpack a .pack file by simply opening it.
However I would like to know how to associate .pack files with the mime type application/opm. Currently the .pack files are associated with application/x-java-pack200. How do I do so? Is it better if I use a different extension (e.g. .opm)? By associating the packed archives with the mime type application/opm will the OS open them with opm by default without having to explicitly set a default application from Properties > Open With?
If there's already a MIME-type associated with .pack then you'll want to use a different extension (.opm) to associate with your MIME-type (application/opm). The way you automatically associate a program that opens files of a specific MIME-type is with xdg-mime .
Alternatively,
Edit ~/.local/share/applications/mimeapps.list and put your MIME/application combo under [Default Applications] like so:
[Default Applications]
application/opm=opm.desktop;
Place your opm.desktop file in ~/.local/share/applications/ folder. (You've already done this)