This script
#!/bin/sh
once=true
while $once do
stop & PID=$!
sleep 10M
if [$!=0]; then
start
break
else
kill $PID
fi
done
Gives
./restart.sh: line 18: syntax error near unexpected token `done'
./restart.sh: line 18: `done'
I don't understand, it had run previously on another unix system. Am i missing something?
EDIT
stop and start are functions that simply run stop.sh and start.sh respectively.
You seem to be missing a semicolon on line 4. Modifying it to read
while ${once}; do
should fix it.
Related
I have the following bash code in a script file:
if [ 'false' == 'true' ]
then
write_map() >> 'groups.txt'
Groups='groups.txt'
fi
When I try to run the script, I get this message from bash, and nothing is run:
syntax error near unexpected token `>>'
Why is >> an "unexpected token?
Why is bash failing on code that is inside an "if" that won't be run?
This bash code was created by Cromwell wdl. write_map is a wdl function, not a bash function. Could that be what's breaking bash?
So, there were two issues
write_map was being called wrong in the wdl code that was the source for this bash code
When called correctly, write_map is turned into a file, and you can't >> a file (you have to cat it then >>)
The below code is being used to trigger a shell command using Jenkins file.
sh """
val=\$(echo ${val} | sed 's/[^a-zA-Z0-9]//g')
echo ${val}
"""
The below error reflects as part of the code :
/home/me/#tmp/abcd/script.sh: command substitution: line 4: syntax error near unexpected token `('
Any solution to the same ? Thanks in advance!
I have a sh file running that calls a ps1 file in the end sh /test/ps1 . The PowerShell file sends an alert email saying that the script is complete. Not really sure why its throwing syntax error.
Following errors when bash is calling powershell test.ps1
./TEST.PS1: line 4: -t: command not found
./TEST.PS1: line 6: =: command not found
./TEST.PS1: line 7: To: command not found
./TEST.PS1: line 8: SmtpServer: command not found
./TEST.PS1: line 9: From: command not found
./TEST.PS1: line 10: Priority: command not found
./TEST.PS1: line 11: syntax error near unexpected token `}'
./TEST.PS1: line 11: `}'
Also I tried to run the following command on bash but hitting errors as well:
git send-email --f from#email.com --t to#email.com --smtp-server ##.###.###. ~/patches/*.patch
I am configuring Cron to backup my sql automatically. However I think that Cron has some issues and it's not working well.
This is the command I am running:
mysqldump --opt -Q -uhereisthename -p'hereisthepasswordwithstrangecharactersthatmustbeescaped' databasename | gzip > /home2/username/backups/backupnamefolder/backupdbwebsitename.`date +"%Y-%m-%d"`.gz
When I run it via SSH it works fine and generates the backup.
However if I run it via Cron, I get the following error:
/bin/sh: -c: line 0: unexpected EOF while looking for matching `''
/bin/sh: -c: line 1: syntax error: unexpected end of file
Anybody can suggest what's wrong?
Cron treats % as a special character (meaning "new line", hence the references to lines 0 and 1 in the error message). You need to escape it:
date "+\%Y-\%m-\%d"
By the way, the posix $( ) syntax is generally better than backticks - it allows nested commands.
I would like to run a few instances of my bash script foo.bash in background.
When I write for i in {1..10}; do ~/bin/foo.bash & ; done in the command line I get an error: bash: syntax error near unexpected token ;
Could you explain why this error occurs and how to fix the command?
& and ; are both command separators; you don't need (and can't have) both.
for i in {1..10}; do ~/bin/foo.bash & done