Open tickets between 2 dates - oracle

Question

I'm trying to find the open tickets, that are open between may 1st 2012 and may 30th 2012 for that day.
So, I should get: May 1st : 0, May 2nd 0, 3rd : 2
But what I'm getting currently is May 1st: 2, 2nd: 2, 3rd:2 then start to go up every 3 days
data :
CREATE TABLE bugs
(
BUG_ID NUMBER PRIMARY KEY,
REPORTED_DATE DATE NOT NULL,
DESCRIPTION VARCHAR2(20),
PRIORITY NUMBER(2),
ASSIGNED_TO VARCHAR2(10),
CLOSED_DATE DATE,
NOTE VARCHAR2(20)
);
INSERT INTO BUGS VALUES (1230, '25-APR-12', NULL, 3, 'Team 3', '28-APR-12', NULL);
INSERT INTO BUGS VALUES (1231, '29-APR-12', NULL, 1, 'Team 1', '29-APR-12', NULL);
INSERT INTO BUGS VALUES (1232, '03-MAY-12', NULL, 1, 'Team 1', '03-MAY-12', NULL);
INSERT INTO BUGS VALUES (1233, '03-MAY-12', NULL, 1, 'Team 3', '08-MAY-12', NULL);
INSERT INTO BUGS VALUES (1234, '04-MAY-12', NULL, 2, 'Team 5', '15-MAY-12', NULL);
INSERT INTO BUGS VALUES (1235, '04-MAY-12', NULL, 2, 'Team 1', NULL, NULL);
INSERT INTO BUGS VALUES (1236, '05-MAY-12', NULL, 1, 'Team 2', '06-MAY-12', NULL);
INSERT INTO BUGS VALUES (1237, '05-MAY-12', NULL, 3, 'Team 3', '10-MAY-12', NULL);
INSERT INTO BUGS VALUES (1238, '09-MAY-12', NULL, 4, 'Team 5', '16-MAY-12', NULL);
INSERT INTO BUGS VALUES (1239, '09-MAY-12', NULL, 5, 'Team 6', NULL, NULL);
INSERT INTO BUGS VALUES (1240, '12-MAY-12', NULL, 5, 'Team 2', '30-MAY-12', NULL);
INSERT INTO BUGS VALUES (1241, '12-MAY-12', NULL, 1, 'Team 1', '12-MAY-12', NULL);
INSERT INTO BUGS VALUES (1242, '13-MAY-12', NULL, 4, 'Team 4', '20-MAY-12', NULL);
INSERT INTO BUGS VALUES (1243, '15-MAY-12', NULL, 4, 'Team 3', '01-AUG-12', NULL);
INSERT INTO BUGS VALUES (1244, '15-MAY-12', NULL, 2, 'Team 4', '20-MAY-12', NULL);
INSERT INTO BUGS VALUES (1245, '20-MAY-12', NULL, 2, 'Team 4', NULL, NULL);
INSERT INTO BUGS VALUES (1246, '22-MAY-12', NULL, 2, 'Team 4', '23-MAY-12', NULL);
INSERT INTO BUGS VALUES (1247, '25-MAY-12', NULL, 2, 'Team 1', '29-MAY-12', NULL);
INSERT INTO BUGS VALUES (1248, '30-MAY-12', NULL, 1, 'Team 1', '01-JUN-12', NULL);
INSERT INTO BUGS VALUES (1249, '05-JUN-12', NULL, 1, 'Team 2', '07-JUN-12', NULL);
COMMIT;
My code so far:
DECLARE
v_date bugs.closed_date%type := '01-may-12';
v_end_date bugs.closed_date%type := '20-may-12';
v_openbugs NUMBER(10);
BEGIN
WHILE v_date <= v_end_date
LOOP
SELECT COUNT(bug_id)
INTO v_openbugs
FROM bugs
WHERE bugs.reported_date < v_date
AND v_date > bugs.closed_date;
DBMS_OUTPUT.PUT_LINE (v_date ||' '|| v_openbugs);
v_date := v_date + 1;
END LOOP;
END;
I need to do this in PL/SQL.

Answer 1

You can manage this just with SQL:
WITH DAYS AS
(SELECT
TO_DATE('06/01/2012', 'MM/DD/YYYY') - ROWNUM D
FROM
DUAL
WHERE ROWNUM < 32)
SELECT
DAYS.D,
SUM(CASE
WHEN B.REPORTED_DATE IS NULL THEN
0
ELSE
1
END)
FROM
DAYS
LEFT OUTER JOIN BUGS B
ON (DAYS.D BETWEEN B.REPORTED_DATE AND NVL(CLOSED_DATE, DAYS.D))
GROUP BY DAYS.D
ORDER BY DAYS.D ASC
If you are going to make this an automatic report then I would pass the dates as an argument and store the result in a cursor and have the calling procedure format the output as required.

Answer 2

This is the Answer I got
DECLARE
v_date bugs.closed_date%type := '01-may-12';
v_end_date bugs.closed_date%type := '31-may-12';
v_openbugs NUMBER(10);
v_maxbug number(10):=0;
BEGIN
DBMS_OUTPUT.PUT_LINE ('Date' ||' '|| 'Open bugs');
WHILE v_date <= v_end_date
LOOP
SELECT COUNT(bug_id)
INTO v_openbugs
FROM bugs
WHERE bugs.reported_date <= to_date(v_date)
AND nvl(bugs.closed_date,'31-may-12') >= to_date(v_date);
if v_maxbug < v_openbugs then v_maxbug:=v_openbugs; end if;
DBMS_OUTPUT.PUT_LINE (v_date ||' '|| v_openbugs);
v_date := v_date + 1;
END LOOP;
DBMS_OUTPUT.PUT_LINE ('===========================');
DBMS_OUTPUT.PUT_LINE ('the max number of open bugs is:'|| v_maxbug);
END;