How to disply timdstamp column with specific format in Spring Data JPA - spring

Question

I am using Spring Data JPA and I have a table like below:
public class Apk {
#Temporal(TemporalType.TIMESTAMP)
#Column
private java.util.Date creationTime;
}
My DBMS is MySQL5.x and the above column is defined datetime type in it. I just call findAl() method in a repository class extends PaginAndSortingRepository.
public interface ApksRepository extends PaginAndSortingRepository<Apk, Long>{
}
public class ApksServiceImpl implements ApksService {
public PagingRes<Apk> findAll(PageInfo pageInfo){
PaginRes<Apk> result = new PagingRes<Apk>();
Page page = apksRepos.findAll(pageInfo.toPageRequest());
result.fromPage(page);
return result;
}
}
public class PageInfo {
private int page;
private int rp;
private String sortname;
private String sortorder;
private String query;
private String qtype;
//getters and setters
public PageRequest toPageRequest() {
Sort.Direction direction = Sort.Direction.ASC;
if (sortorder!=null && "DESC".equals(sortorder))
direction = Sort.Direction.DESC;
return new PageRequest(page-1, rp, direction, sortname);
}
}
public class PagingRes<T> {
private long total;
private int page;
private int rowPerPage;
private List<T> rows;
//getters and setters
public PagingRes<T> fromPage(Page page) {
this.page = page.getNumber();
this.rowPerPage = page.getSize();
this.total = page.getTotalElements();
this.rows = page.getCotent();
return this;
}
}
And I am trying to display data in the table including the column but when I did it, the column is shown as long type. I wan to display the column in the fomat 'dd-MM-yyyy hh:mm:ss'. How can I do this?
Thanks in Advance.

Answer 1

I knew that Jackson mapper for JSON response were giving weird result. So after searching, I used JsonSerializer to fix it like below:
Entity class
#JsonSerialize(using=AuDateSerializer.class)
private java.util.Date eventTime;
Custom Serializer
public class AuDateSerializerextends JsonSerializer<Date> {
#Override
public void serialize(Date value, JsonGenerator gen, SerializerProvider provider) throws IOException, JsonProcessingException {
DateFormat formatter = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
jgen.writeString(formatter.format(value));
}
}
Now it works fine. Thanks.