Uploading/Displaying Images in MVC 4 - image

Question

Anyone know of any step by step tutorials on how to upload/display images from a database using Entity Framework? I've checked out code snippets, but I'm still not clear on how it works. I have no code, because aside from writing an upload form, I'm lost. Any (and I mean any) help is greatly appreciated.
On a sidenote, why don't any books cover this topic? I have both Pro ASP.NET MVC 4 and Professional MVC4, and they make no mention of it.

Answer 1

Have a look at the following
#using (Html.BeginForm("FileUpload", "Home", FormMethod.Post,
new { enctype = "multipart/form-data" }))
{
<label for="file">Upload Image:</label>
<input type="file" name="file" id="file" style="width: 100%;" />
<input type="submit" value="Upload" class="submit" />
}
your controller should have action method which would accept HttpPostedFileBase;
public ActionResult FileUpload(HttpPostedFileBase file)
{
if (file != null)
{
string pic = System.IO.Path.GetFileName(file.FileName);
string path = System.IO.Path.Combine(
Server.MapPath("~/images/profile"), pic);
// file is uploaded
file.SaveAs(path);
// save the image path path to the database or you can send image
// directly to database
// in-case if you want to store byte[] ie. for DB
using (MemoryStream ms = new MemoryStream())
{
file.InputStream.CopyTo(ms);
byte[] array = ms.GetBuffer();
}
}
// after successfully uploading redirect the user
return RedirectToAction("actionname", "controller name");
}
Update 1
In case you want to upload files using jQuery with asynchornously, then try this article.
the code to handle the server side (for multiple upload) is;
try
{
HttpFileCollection hfc = HttpContext.Current.Request.Files;
string path = "/content/files/contact/";
for (int i = 0; i < hfc.Count; i++)
{
HttpPostedFile hpf = hfc[i];
if (hpf.ContentLength > 0)
{
string fileName = "";
if (Request.Browser.Browser == "IE")
{
fileName = Path.GetFileName(hpf.FileName);
}
else
{
fileName = hpf.FileName;
}
string fullPathWithFileName = path + fileName;
hpf.SaveAs(Server.MapPath(fullPathWithFileName));
}
}
}
catch (Exception ex)
{
throw ex;
}
this control also return image name (in a javascript call back) which then you can use it to display image in the DOM.
UPDATE 2
Alternatively, you can try Async File Uploads in MVC 4.

Answer 2

Here is a short tutorial:
Model:
namespace ImageUploadApp.Models
{
using System;
using System.Collections.Generic;
public partial class Image
{
public int ID { get; set; }
public string ImagePath { get; set; }
}
}
View:
Create:
#model ImageUploadApp.Models.Image
#{
ViewBag.Title = "Create";
}
<h2>Create</h2>
#using (Html.BeginForm("Create", "Image", null, FormMethod.Post,
new { enctype = "multipart/form-data" })) {
#Html.AntiForgeryToken()
#Html.ValidationSummary(true)
<fieldset>
<legend>Image</legend>
<div class="editor-label">
#Html.LabelFor(model => model.ImagePath)
</div>
<div class="editor-field">
<input id="ImagePath" title="Upload a product image"
type="file" name="file" />
</div>
<p><input type="submit" value="Create" /></p>
</fieldset>
}
<div>
#Html.ActionLink("Back to List", "Index")
</div>
#section Scripts {
#Scripts.Render("~/bundles/jqueryval")
}
Index (for display):
#model IEnumerable<ImageUploadApp.Models.Image>
#{
ViewBag.Title = "Index";
}
<h2>Index</h2>
<p>
#Html.ActionLink("Create New", "Create")
</p>
<table>
<tr>
<th>
#Html.DisplayNameFor(model => model.ImagePath)
</th>
</tr>
#foreach (var item in Model) {
<tr>
<td>
#Html.DisplayFor(modelItem => item.ImagePath)
</td>
<td>
#Html.ActionLink("Edit", "Edit", new { id=item.ID }) |
#Html.ActionLink("Details", "Details", new { id=item.ID }) |
#Ajax.ActionLink("Delete", "Delete", new {id = item.ID} })
</td>
</tr>
}
</table>
Controller (Create)
public ActionResult Create(Image img, HttpPostedFileBase file)
{
if (ModelState.IsValid)
{
if (file != null)
{
file.SaveAs(HttpContext.Server.MapPath("~/Images/")
+ file.FileName);
img.ImagePath = file.FileName;
}
db.Image.Add(img);
db.SaveChanges();
return RedirectToAction("Index");
}
return View(img);
}
Hope this will help :)

Answer 3

<input type="file" id="picfile" name="picf" />
<input type="text" id="txtName" style="width: 144px;" />
$("#btncatsave").click(function () {
var Name = $("#txtName").val();
var formData = new FormData();
var totalFiles = document.getElementById("picfile").files.length;
var file = document.getElementById("picfile").files[0];
formData.append("FileUpload", file);
formData.append("Name", Name);
$.ajax({
type: "POST",
url: '/Category_Subcategory/Save_Category',
data: formData,
dataType: 'json',
contentType: false,
processData: false,
success: function (msg) {
alert(msg);
},
error: function (error) {
alert("errror");
}
});
});
[HttpPost]
public ActionResult Save_Category()
{
string Name=Request.Form[1];
if (Request.Files.Count > 0)
{
HttpPostedFileBase file = Request.Files[0];
}
}