Hibernate exception - hibernate.internal.QueryImpl cannot be cast - spring

Question

I'm trying to authenticate with a database username. So far the error is:
Your login attempt was not successful, try again.
Reason: org.hibernate.internal.QueryImpl cannot be cast to com.**.**.model.UserEntity
The query in the dao class
#Repository
public class UserEntityDAOImpl implements UserEntityDAO{
#Autowired
private SessionFactory sessionFactory;
public void setSessionFactory(SessionFactory sessionFactory) {
this.sessionFactory = sessionFactory;
}
public Session getCurrentSession() {
return this.sessionFactory.getCurrentSession();
}
#Override
public UserEntity getUserByName(String username) {
// TODO Auto-generated method stub
UserEntity userEntity = (UserEntity)
sessionFactory.getCurrentSession().createQuery(
"select u from UserEntity u where u.username = '' + username + ''");
return userEntity;
}
service
#Service("customUserDetailsService")
public class CustomUserDetailsService implements UserDetailsService{
#Autowired
private UserEntityDAO userEntityDAO;
#Autowired
private Assembler assembler;
#Override
#Transactional(readOnly = true)
public UserDetails loadUserByUsername(String username)
throws UsernameNotFoundException {
// TODO Auto-generated method stub
UserDetails userDetails = null;
UserEntity userEntity = userEntityDAO.getUserByName(username);
if (userEntity == null)
throw new UsernameNotFoundException("user not found");
return assembler.buildUserFromUser(userEntity);
}
}
DB table that holds the user details
/*Table structure for table `user` */
CREATE TABLE `user` (
`user_id` INT(11) NOT NULL AUTO_INCREMENT ,
`name` VARCHAR(45) NULL DEFAULT NULL ,
`password` VARCHAR(45) NOT NULL ,
`username` VARCHAR(45) NOT NULL ,
`active` TINYINT(1) NOT NULL ,
PRIMARY KEY (`user_id`)
) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=latin1;
Model
#Entity
#Table(name = "user", schema = "")
#Component
public class UserEntity implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Basic(optional = false)
#Column(name = "user_id")
private Integer id;
#Column(name = "name")
private String name;
#Basic(optional = false)
#Column(name = "password")
private String password;
#Basic(optional = false)
#Column(name = "username")
private String username;
#Basic(optional = false)
#Column(name = "active")
private boolean active;
#JoinTable(name = "user_role", joinColumns = {
#JoinColumn(name = "user_id")}, inverseJoinColumns = {
#JoinColumn(name = "role_id")})
#OneToMany
private Set <Role> roles;
public UserEntity() {
}
//getters and setters
What I would like insight on is why there is a problem with the query, and why the username is not able to be retrieved from the database.
Edit: After changing the query, the login is still not successful. The login page is returned and there is no error message in the output console other than this:
Hibernate: select userentity0_.user_id as user1_1_, userentity0_.active as
active1_, userentity0_.name as name1_, userentity0_.password as password1_,
userentity0_.username as username1_ from user userentity0_ where
userentity0_.username=?
Hibernate: select roles0_.user_id as user1_1_1_, roles0_.role_id as role2_2_1_,
role1_.role_id as role1_0_0_, role1_.role as role0_0_ from user_role roles0_ inner
join role role1_ on roles0_.role_id=role1_.role_id where roles0_.user_id=?
INFO : com.**.**.controller.ApplicationController - This is the login page {}.

Answer 1

You forgot to execute the query you created. It should be:
sessionFactory.getCurrentSession().createQuery(...).uniqueResult();
Also, use a proper bind variable. As it stands your query is bogus with single quotes, I'm not sure if you made a typo pasting it into stackoverflow, but something like this would be much safer:
sessionFactory
.getCurrentSession()
.createQuery("select u from UserEntity u where u.username = :username")
.setParameter("username", username)
.uniqueResult();