this.get('controller')
is coming up null.
I am wondering if someone can explain how ember views are associated with ember controllers. Thank you.
If you follow ember's naming conventions, then for example the View InfoView would be hooked up automatically with InfoController by ember.
App.InfoView = Ember.View.extend({
templateName: 'info'
});
App.InfoController = Ember.Controller.extend({});
so if you later do this.get('controller') in your View you should get the controller.
see this fiddle for an working example: http://jsfiddle.net/intuitivepixel/AywvW/20/
This is what ended up working. Simply added this line to the view:
controllerBinding: "App.myController",
Related
I'm currently working on a homepage where I am showing the 'latest hauls' and 'latest finds' they are both separate models ofcourse.
Currently I am only showing the 5 latest hauls since I use the HaulController#getWelcome Controller so I can access $haul->title etc.
How would I be able to also access $finds->title?
Thanks for the help!
You can share a model to a view by using it inside controller function -
View::share('subadmin', App\Models\SubAdmin::class);
You can call the model in your view like
{{ \App\Model::function() }}
So you can have {{ App\Model::orderBy('created_at', 'desc')->limit(5)->get() }}
You have a couple of options.
Option 1: A combined model and one view.
To do this create a new ViewModel and have LatestHauls and LatestFinds as properties on this model. You could set these properties in the controller.
On your view simply navigate down the viewmodel to the appropriate properties.
Option 2: Extend the above solution to use partial views. Create a partial view for each model. On the parent view call each partial view. This might be considered a better solution but option 1 will get you started.
I'm still learning Laravel and I'm working on a small project to help me understand better. In the project, I am in need of a global array, so that I may display it or its attributes on every view rendered. sort of on a notification bar, so that each page the user visits, he/she can see the number of notifications (which have been fetched in the background and are stored in the array).
I have done some research, and realized that I have to fetch and compile the array in a view composer I think. But everywhere I go, I cant seem to understand how to make a view composer.
I need to fetch the relevant rows from the database table, and make the resulting array available to each view rendered (I'm thinking attaching it somehow to my layouts/default.blade.php file.). Please help, any and all advice is greatly appreciated:)
You can now inject services on your view
More info here: https://laracasts.com/series/whats-new-in-laravel-5-1/episodes/2
You have to use Sub-Views of laravel blade. I guess your functionality is like a sidebar or like a top bar which will be rendered at every page.
//Your Controller pass data
class YOUR_CONTROLLER extends Controller {
public function index()
{
$data = YOUR_DATA;
return view('YOUR_VIEW_FILE', get_defined_vars());
}
}
//In Your View File
#extends('LAYOUTS_FILE')
#section('YOUR_SECTION')
#include('YOUR_SUB_VIEW_FOR_NOTIFICATION')//You need not pass any data passed all data will be available to this sub view.
#endsection
In your sub view
//Do what ever you want looping logic rendering HTML etc.
//In your layout file just yield or render the section that's it
#yield('YOUR_SECTION')
More explanation can be found Including Sub-Views
I am trying to load a view from my controller using the follow code but I only get a raw HTML view and does not show the site's template.
$view = $this->getView( 'download', 'html' );
$view->display();
Can some help me in what I am doing wrong to display the site's template.
I also tried a redirect but that did not work either
$this->redirect(JRoute::_('index.php?option=com_atdwcsv&view=download'), false);
Edit: I figured out what was wrong with the redirect. Code I needed was
$this->setRedirect('index.php?option=com_atdwcsv&view=download');
$this->redirect();
I could be wrong, but I don't think you need to use the display() method on the view, I think you need to use $this->display(); instead.
I have a main.blade.php which contains my layout. As part of this layout, I need to show the categories from the database.
I would like to avoid doing the Eloquent call in every single controller.
How can I retrieve all categories to show on main.blade.php regardless of the controller?
You can do it in the base controller or the view layout you have.
In the view it would be:
#foreach(Category::all() as $category
and for a base controller, it would be something like:
$this->layout->categories = Category::all();
Hope this helps!
http://laravel.com/docs/templates
It would be great to call single action in template right? :)
You can check this package (check out layout facade section). Hope it helps.
Sorry about the question title, but I couldn't find a more appropriate way to phrase this.
I am currently building a CakePHP powered website and I'm not quite sure how to approach the following issue. The website looks something like the follwing mockup:
.
The greyed out areas are part of the layout, because their content does not change between views. In the sidebar, I have a collection of ads who are linked to several models. I need controller logic to determine the picture associated with an ad. Also, the ad list needs to be dynamic. Where should I put the logic for building the sidebar?
I've thought about:
putting the logic into the AppController (beforeFilter / afterFilter) - the problem is I can't use the controller logic I need (the other controllers inherit from AppController, I'm not sure how to use them there).
making a component - is it okay to build components that rely on controllers?
replicating the sidebar code in all controllers that render views - this seems kind of stupid to me.
What is the Cake way for this?
Update
After some reading and experimenting, I've gotten to refactoring most of it.
I obtained the best performance by moving the logic for building my ads in the model (eliminating the component that retrieved the pictures) and not using requestAction. It's almost three times faster and the code looks much better.
I've done something similar for data-driven navigation. I put my logic in AppController::beforeRender and haven't had any problems. I'm not sure I understand your concern related to controller inheritance. I retrieve my menus via:
$menus = $this->NavMenuItem->groupByMenu();
$this->set( compact( 'menus' ) );
I then created an element that renders the menu. It's executed by the layout via:
<?php echo $this->element( 'navigation', array( 'id' => 'secondary', 'menu' => $menus['SECONDARY'] ) ) ?>
If that doesn't help, maybe you can further explain your issue with controller inheritance in a comment.
I guess the answer is requestAction in case the results are cachable:
http://book.cakephp.org/view/434/requestAction
It can be done in this way:
Create an element that will help in layout of the Ad Block
Create one or more controller that will generate the data required for rendering of the block
Use requestAction for getting the data out of the models and into the element.
Check the cake book, there is an example of an element where data from Post Model is used to display top/latest 5 posts. Your requirement, I feel, is very similar to it.
Alex,
you're getting a SQL error because the build() function has to be in the Sidebar model, not controller. Also, you don't necessarily need to use $user = array('Sidebar'); you could calling Sidebar in all of your models with this:
$Sidebar = ClassRegistry::init('Sidebar'); and then $Sidebar->find();, $Sidebar->build(); etc.
Or, if you only need to call the build() function from the Sidebar model, you could do this:
$sidebar = ClassRegistry::init('Sidebar')->build();
$this->set('sidebar', $sidebar);
Cheers.