Cocoa, output current App path - macos

Question

I am working on OS X application. In the code, I would like to output a path of the current Mac OS App to a variable for future use. So later I could read the files in the same folder. Could anyone tell me the command/method in the Xcode ?
Thanks very much.
UPDATE
To be more clear, I am using xcode and create a cocoa-application.
My application is connected with applescript to control Mac software read files on the Mac. So I have to return the files' directory and name.
Actually I have no idea about what to do. So got stuck here.

Answer 1

To get the URL of your application, you can use:
[[NSBundle mainBundle] bundleURL]
See the NSBundle Class Reference for further information.

Answer 2

my 2 cents for swift 5,x:
let path = Bundle.main.bundlePath
print(path)
If You need a path to REAL exacutable: (i.e. you mast pass to shell or similar..)
let appName = AppName()
let exePath = path + "/Contents/MacOS/" + appName
print(exePath)
where AppName() is:
func AppName()->String{
let bund = Bundle.main
//print(bund)
if let displayName = bund.object(forInfoDictionaryKey: "CFBundleDisplayName") as? String {
if displayName.count>0{
return displayName
}
}
if let name = bund.object(forInfoDictionaryKey: "CFBundleName") as? String {
return name
}
return "no AppName"
}